Sir please contact me i need your help seriously i've none to take advice since school teachers are not so much good and in my home my sister don't have time pls sir if you see my comment then don't ignore it this would very crucial help for me sir plssss...
0:00 Introduction & Nature of Chapter 3:21 Index and Critical topics 7:01 Iota & Powers of Iota 16:53 Describing complex numbers & its Algebra 55:54 Conjugate of complex numbers 1:34:30 Argand Plane (Modulus and Argument) 2:00:49 Properties of modulus 2:58:07 Properties of Argument 3:08:26 Representation of complex numbers in different forms 3:25:17 DE-Moivre' Theorem 3:34:21 Cube roots of Unity
Significance of i : 7:10 ( i kabhi dikhega nhi, bas ye dimaag mein rkhna h ki i = √-1 ) 🌟 Std step 1) 1:00:56 1:02:05 write z = x + iy (z nikalna ho from eqn, use this) OR. 2) 21:5531:2936:52 (make out that the result/answer is a CN, say z which is = x + iy) 🌟 22:2623:3731:3936:591:52:58 : in CN, 1 eqn gives two info (1st by comparing real part on both sides, 2nd by comparing imaginary part on both sides) Imp Variety Q in Conjugate of CN : 1:00:37. (Put z = x + iy and then obtaining 2 info from 1 eqn) 1:15:05 1:19:02 1:19:56 : Conjugate mein power andar bahar ja skti h Method to use info that CN (say z) is purely imaginary or real : 1:22:33 1:26:05 1:27:43 1:32:38 1:55:30 (z aur zconj. ka addn aur subtraction yaad kro and use accordingly as per q) 1:29:55. : Also use this property to comment upon Re(z) or Im(z) {har baar 0 ho, zaroori thodi h} 2:09:22 2:15:26 : Solving Tip - Aese q mein ek side bnane ki koshish kro, doosri side apne apne bn jaegi ( for eg here we created RHS by taking mod and sq in given eqn) 🌟 ie desired cheez ko create kro!!! 2:06:32 : Cubic in z - Find 1 root by hit and trial (like we used to do in a cubic in x) by putting values = i, -i etc. 2:16:05 : MOD chahiye toh mod apply kro ( to get eqn in |z| ) 2:18:46 2:20:15 2:22:05 2:28:17: 1) Jab bhi MOD ke andar z baitha ho, sq it and use (z.zconj = |z|²). 2) MOD baitha h aur kuch smjh nhi aa rha, Sq it and use (|z|² = z.zconj) 2:31:42 2:32:23 2:34:47 2:35:45 : MOD ki value given ho (let |z| = a) , toh use (z.zconj = a²) anyhow in asked expn 3:10:34 3:12:48 : Polar Form : |z|, theta pta h then we can write CN
THANKS ALOT SIR!!! I am OVERWHELMED by the way you teach ALL the concepts including ADV. LEVEL with such an ease, it directly goes in head! Literally I feel you are one of THE BEST MATHEMATICS TEACHERS in INDIA. MERA BHAI MERA BHAI 🔥. You made it easy for me to enjoy learning.
1:54:36 Method -4 put z = i y ( iota* y) and then rationalize and put imaginary part equal to zero the we got answer...Plz do it in smart way it`s not a lengthy method
Sir at 1:07:20 .. We're getting x=+2 or -2 and y +1 or -1... But sir since we're using "X*Y=15"..doesn't that mean that X and Y need to have the same sign? And doesn't that also ultimately mean that x and y also need to have the same sign.... So aren't possible solutions for this equation (2,1) and (-2,-1)? So the answer should be D(2) right?
@@aaravbaid6164 I didn't wanna type the entire "(x²+y²)(x²-y²) so I substituted that with capital X and capital Y. If sir had seen this message he'd have understood But thanks to your comment I've realised my silly mistake. It'll be too complicated to explain what mistake exactly I made through TH-cam comments, but yeah I figured out what I was doing wrong. My mistake isn't what you think it is, it's something different.
@@aaravbaid6164 exactly..they're squared so they can be both +-2 and +-1..i missed the square part when i originally solved this..that's kinda the silly mistake hahah
Sir main apne jee ke journey main completely TH-cam par relay hoon please suggest video lectures complete karn ke baad kya kya steps apply karoon to reach JEE ADVANCE level 😢
The PDF of the session is in the link pinned in the telegram channel t.me/JEEnexus
Hii sir I am your big fan 🎉🎉🎉
Sir please contact me i need your help seriously i've none to take advice since school teachers are not so much good and in my home my sister don't have time pls sir if you see my comment then don't ignore it this would very crucial help for me sir plssss...
bhaiya thoda or detail me explain Karo pls pls pls bhaiya thoda week hu kuch kuch chize samaj nahi ata
@@passionaticmusicbyvansh1838 how sir will contact you
Add some way he can contact you 🤔
Bhai please today sa aur gehrai me explain karo meko samajh me nahi aata jaldi bahot week hu padhne me please bhaiyya please😔😔🥺
Like to get cs in iit bombay😂😂😂
😂
Iti bombay😂😂😂
Yes
Four like congratulations 🎉@Hhuubhgyh
Ya ofcourse chacha hi to IIT ka paper banate h tumhare
Is it just me who needs 7-8 hrs to complete a 4 hr lecture?
u r sincere thats why
You are not the only one I will take 2 days to complete lecture 😂😂😂😅
Yes
Me also
4 dys still not complete
0:00 Introduction & Nature of Chapter
3:21 Index and Critical topics
7:01 Iota & Powers of Iota
16:53 Describing complex numbers & its Algebra
55:54 Conjugate of complex numbers
1:34:30 Argand Plane (Modulus and Argument)
2:00:49 Properties of modulus
2:58:07 Properties of Argument
3:08:26 Representation of complex numbers in different forms
3:25:17 DE-Moivre' Theorem
3:34:21 Cube roots of Unity
Significance of i : 7:10 ( i kabhi dikhega nhi, bas ye dimaag mein rkhna h ki i = √-1 )
🌟 Std step
1) 1:00:56 1:02:05 write z = x + iy (z nikalna ho from eqn, use this)
OR.
2) 21:55 31:29 36:52 (make out that the result/answer is a CN, say z which is = x + iy)
🌟 22:26 23:37 31:39 36:59 1:52:58 : in CN, 1 eqn gives two info (1st by comparing real part on both sides, 2nd by comparing imaginary part on both sides)
Imp Variety Q in Conjugate of CN : 1:00:37. (Put z = x + iy and then obtaining 2 info from 1 eqn)
1:15:05 1:19:02 1:19:56 : Conjugate mein power andar bahar ja skti h
Method to use info that CN (say z) is purely imaginary or real : 1:22:33 1:26:05 1:27:43 1:32:38 1:55:30 (z aur zconj. ka addn aur subtraction yaad kro and use accordingly as per q)
1:29:55. : Also use this property to comment upon Re(z) or Im(z) {har baar 0 ho, zaroori thodi h}
2:09:22 2:15:26 : Solving Tip - Aese q mein ek side bnane ki koshish kro, doosri side apne apne bn jaegi ( for eg here we created RHS by taking mod and sq in given eqn) 🌟 ie desired cheez ko create kro!!!
2:06:32 : Cubic in z - Find 1 root by hit and trial (like we used to do in a cubic in x) by putting values = i, -i etc.
2:16:05 : MOD chahiye toh mod apply kro ( to get eqn in |z| )
2:18:46 2:20:15 2:22:05 2:28:17:
1) Jab bhi MOD ke andar z baitha ho, sq it and use (z.zconj = |z|²).
2) MOD baitha h aur kuch smjh nhi aa rha, Sq it and use (|z|² = z.zconj)
2:31:42 2:32:23 2:34:47 2:35:45 : MOD ki value given ho (let |z| = a) , toh use (z.zconj = a²) anyhow in asked expn
3:10:34 3:12:48 : Polar Form : |z|, theta pta h then we can write CN
Dhanywad bhai 🙏
No argument ,
Arvind sir One shot lectures are top notch. ❤️🗿
❤❤
THANKS ALOT SIR!!! I am OVERWHELMED by the way you teach ALL the concepts including ADV. LEVEL with such an ease, it directly goes in head! Literally I feel you are one of THE BEST MATHEMATICS TEACHERS in INDIA. MERA BHAI MERA BHAI 🔥. You made it easy for me to enjoy learning.
Starting the lecture
Will complete with repetition aur sheet by tomorrow evening
Thankyou bhai ❤❤❤
Completed
1:21:20 done nd dusted 1 take conjugate on both side 2 multiply i^5 in both the side nd simplify get the ans
Thx
Sir Remark✅ , questions in between✅ and worksheet ✅ basically everything done and dusted 👍 . Thank you bhai. ♥️
😂😂😂
Hasa kyu be@@Fhkdutdfhkorhfjg
copied from jee nexus comments🙂
😂😂😂
Sir iske baad sequence and series one shot kijiye na please 🥺🥺
Lets everyone say KNOCK. KNOCK KAUN AAYA ,MERA BHAI AAYA ❤
Knock knock knock, kaun aaya , mera backlog mate aaya 😂😂
everything done and dusted , amazing lecture very easily explained...🥰
1 subscribe = under 2k rank in jee advanced ❤❤❤❤❤😊😊😊😊😊
1:21:02 remark done and dusted
Sir please take one shot of sequence and Series
Yeah crystal clear
Mera bhai 😊😊😊❤❤❤❤❤❤
1:24:41 sir 1 ke jagah (alpha)(alpha) conjugate rakh dete to calculation nhi karna padta direct answer aata
7:01 lecture starts
Thank you
I am an nda aspirant and believe me sir is one of the best teachers of class 11 for making the concept permanent
1:21:36
Remark: Done and Dusted
Commerce with math students will like❤️
Really awesome ❤
Sir please sequence and series
Relation and functions plz sirrrr
yes sir
2:23:34 Unimodular wala question done and dusted.
Can you tell me the answer?
U are the best bhai
2:17:35
Sir didn't ask but still I dropped the banger
Done and l Dusted😎
1:13:39
Advance wala badiya Q done and dusted
Unimodular wala question done and dusted 😊
Sq root formula
Reciprocal is multiplicative inverse
Best teacher
Sir PLEASE bring class 12 calculus
44:20 smile 🙂🙂🙂🙂😊😊
Very good video sir , best explanation , a suggestion: give us some time to make notes
Unimodular Q done and dusted❤
2:23:13 unimodular qs done and dusted 🫡
Thanks sir Aap hame free pada rahe hai❤❤
Sir bhagwan ke liye agla chapter snp le aao sirrr aapki bhot kripa rahegi 🙏🙏🙏🙏
Kiya bola tumne siiiiirrrr arvind bhaiya ab bhai nahi raheee sir ho gaay haa
Sno mtlb ??
@@Guru-mf3ew snp matlab sequence and progressions. Different coachings me different naam se bolte hai
Watching this for straight 4 hours, I became a subscriber of this channel as well as a permanent disciple of the teacher..
Thankyou sm sir😊
unimodular ques done and dusted!
sir nahi ❌ bhai✔
You made my journey easy with this chapter.
Thankx BHAI ❤
21:15
1:54:32
2:02:04
1:21:02
by using binomial
Bada sa question done (modulus z² wala) and tested and by myself without method 1,2,3
1:21:10 Remark Done And Dusted🫡
How
Who's watching this for IIT -JAM??
😅
2:00:32 Done and Dusted!!!!
1:21:20 question is done and dusted
1:08:59 ❤
1:54:36 Method -4 put z = i y ( iota* y) and then rationalize and put imaginary part equal to zero the we got answer...Plz do it in smart way it`s not a lengthy method
How can you say that Z is purely imaginary??
REPEAT
48:30
1:06:00
1:13:05
2:13:00
sir jaldi se sabhi chapter ke one shot daal dijiye Nov tak
syllabus Pura revise bhi karna hai
Sir answer is, x=-4+-√73/16
Sirji done and dusted ❤
3:04:45
3:19:33 note there will be+i√3/2
Bhai aap solution of triangle and trigonometric equation ka session kab laoge
Sir at 30:00 can n be 0 , if not then why
Thank you 😊
Unimodular wala done and understad
Sir at 1:07:20 .. We're getting x=+2 or -2 and y +1 or -1... But sir since we're using "X*Y=15"..doesn't that mean that X and Y need to have the same sign? And doesn't that also ultimately mean that x and y also need to have the same sign.... So aren't possible solutions for this equation (2,1) and (-2,-1)? So the answer should be D(2) right?
Where did we use that X*Y=15 ??
@@aaravbaid6164 I didn't wanna type the entire "(x²+y²)(x²-y²) so I substituted that with capital X and capital Y. If sir had seen this message he'd have understood
But thanks to your comment I've realised my silly mistake. It'll be too complicated to explain what mistake exactly I made through TH-cam comments, but yeah I figured out what I was doing wrong. My mistake isn't what you think it is, it's something different.
@@joshuabell1133 Yeah both your substitution as 'X' and 'Y' are both positive when x= ±2 and y = ±1 due to being squared in 'X' and 'Y'
@@aaravbaid6164 exactly..they're squared so they can be both +-2 and +-1..i missed the square part when i originally solved this..that's kinda the silly mistake hahah
Thanks sir❤❤❤❤
done and dusted
9:38 Sir you have done wrong either we can take three or it should be i to power 52 x i power 5
Yes, in sir's case it should be 5.
But why make it complex.
Better go with i⁵⁷ = i⁵⁶⁺¹ = 1 × i = i.
Sir really made a mistake
Sir plz take pyqs session on complex no.s
Ok sir
You guys shocked me
You all understand his teaching , How?
Sir physics ke lecture kb ayenge class 12 ke
Sir please relation and function ka session le aaye
unimodular question done and dusted! on 21-08-2024
thank u sir
Any 289ians😅
yes 💀🐐
1:46:02😂😂😂
unimodular wala question done and dusted bhai!
1 subscribe = 99.9%ile in jee mains ❤❤❤❤😊😊😊😊😊
Sir unimodular Waala question done and dusted
2:23:34 unimodular wala question done and dusted
ans 4 ??
3:16:18 that's my name Debasish
3:27:51 here aswell
Sir Complex number conjugate wala calculation done and dusted
Sir Revision+Sheet Done and Dusted
unimodular question done and dusted
ADVANCED 2022 QUESTION DONE AND DUSTED
Sir ur camera becoming blurr....😢
43:17 divide me toh 5 tha?
24:23
Bhai Sequence and Series ka one shot too please!
Mod ka bada question done and dusted
Remarks done and dusted
Not to Brag abt it But i study from A Math Legend 💎💎
Sir sets and relation and functions
complex numbers done and dusted
Is this from basic !?
No
yes but it is fast as sir does not repeat anything again so we listen again by going backward so it takes a lot of time
1:25:00
remark done and dusted
unimolecular question done and dusted
unimodular waala question done and dusted
Sir main apne jee ke journey main completely TH-cam par relay hoon please suggest video lectures complete karn ke baad kya kya steps apply karoon to reach JEE ADVANCE level 😢
Study from Sameer sir Old lectures In Sequence
Hatttttt!
Cengage Karo 💀!!!
4 mahine me 247 rank ayyi hai hatttt!
Chomu students hattt!
Cool banega hattt !
15 saal ke massooom bache hatttt!
1:46:18 😂