Introductory Newton's 2nd Law Example Problem and Demonstration

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  • เผยแพร่เมื่อ 25 ธ.ค. 2024

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  • @bradleyhowell4155
    @bradleyhowell4155 7 ปีที่แล้ว +34

    Man, this guy deserves more views with the amount of work he does.

    • @FlippingPhysics
      @FlippingPhysics  7 ปีที่แล้ว +9

      Yep, I can agree with that.

    • @Ndiedddd
      @Ndiedddd 2 ปีที่แล้ว

      Force times the displacement? 😂

  • @FlippingPhysics
    @FlippingPhysics  10 ปีที่แล้ว +19

    Using Newton’s Second Law to solve for the Force of Friction between a Dynamics Cart and Track. Is friction really negligible?
    Also, publishing today’s video marks an interesting Flipping Physics milestone. It means there are now more than 100 hours of me teaching on the internet. 17 Hours of edited Billy, Bobby and Bo videos, 79 hours of in-class lectures and 4 hours of presentations. Wow, that’s a lot of mr.p. #PhysicsED #flipclass

  • @katelyndouay9844
    @katelyndouay9844 9 ปีที่แล้ว +15

    Mr. P, thank you so much for creating Flipping Physics! If it weren't for these videos, I would be doing really poorly in my Physics 1 class, and would be incredibly stressed. So thank you!

    • @FlippingPhysics
      @FlippingPhysics  9 ปีที่แล้ว +5

      +Katelyn Douay Ahhhhh, reducing stress. so nice.

  • @daASSassin117
    @daASSassin117 10 ปีที่แล้ว +2

    Thank you so much for making these videos! You saved my life! God Bless you, keep on making these videos

    • @FlippingPhysics
      @FlippingPhysics  10 ปีที่แล้ว +2

      You are welcome. Keep liking the videos and leaving awesome comments like this one. It will help me "keep on making these videos"!

  • @cabincrewinternationalinst2734
    @cabincrewinternationalinst2734 4 ปีที่แล้ว +2

    The voice of the student on the left reminds me of SpongeBob's voice. Great vids, thank you! :)

  • @mustafaRoya
    @mustafaRoya 8 ปีที่แล้ว +2

    Thank you for help us mr p so good explanation

    • @FlippingPhysics
      @FlippingPhysics  8 ปีที่แล้ว +1

      +Gholam Mustafa Ali As always, you are welcome.

  • @oweznero
    @oweznero 7 ปีที่แล้ว +4

    Your videos really helped me. I'm not understanding physics but when I watch your videos I've started loving physics. Please can you create videos on quantum mechanics. And some calculas

    • @FlippingPhysics
      @FlippingPhysics  7 ปีที่แล้ว +4

      Thanks! Sorry, I do not plan to make any videos specifically about quantum mechanics at this time. I am concentrating on the AP Physics 1 curriculum right now. I do have videos about calculus based physics: www.flippingphysics.com/ap-physics-c-review.html But not Calculus specifically.

    • @oweznero
      @oweznero 7 ปีที่แล้ว

      Flipping Physics. Mr. P we your videos really helped me but I'm still getting problem in calculas and vector please please please create videos on that topic please please please please please please please please please please please Mr p

  • @srinivas22222
    @srinivas22222 9 ปีที่แล้ว +1

    nice work i enjoyed learning too ; )

  • @deathstramy7272
    @deathstramy7272 2 ปีที่แล้ว

    What do you write on the paper while filming as the students?

  • @technotux7835
    @technotux7835 2 ปีที่แล้ว

    Sir, can use an electronic hanging spring scale, instead of the force meter?

  • @OliVer-nc1tm
    @OliVer-nc1tm 8 ปีที่แล้ว +2

    What's wrong with getting the acceleration by using the v-final minus v-initial over time. with v initial being 0 and v- final being the displacement of 0.52 meters over 1.15 seconds = 0.452 m/s.
    a= (0.452-0)/1.15 = 0.393 m/s^2 ... why is it wrong?

    • @FlippingPhysics
      @FlippingPhysics  8 ปีที่แล้ว +4

      Average velocity equals displacement over change in time. Velocity final is an instantaneous velocity, which is not the same as average velocity. Here is a video about the difference between the two: www.flippingphysics.com/instantaneous-and-average-velocity.html

  • @arsenal78910
    @arsenal78910 5 ปีที่แล้ว +1

    Why do you assume net force to be constant? How do you know when forces will be constant so that you can use uniformly accelerated motion equations?

    • @FlippingPhysics
      @FlippingPhysics  5 ปีที่แล้ว +1

      In general, when the force is pretty close to constant, you can consider it to be constant. In the next video: www.flippingphysics.com/force-vs-time.html I show three sections: Blue and Red are clearly constant, and yellow is clearly not constant.

  • @WeAreShowboat
    @WeAreShowboat 10 ปีที่แล้ว

    This seems more convoluted than it needs to be. Why not use a motion detector, and use the slope of the velocity graph to get the acceleration? That way the acceleration is also found experimentally, and we don't need to make additional assumptions like constant acceleration (to use UAM) since we can just see the velocity graph is linear and get the acceleration directly.

    • @FlippingPhysics
      @FlippingPhysics  10 ปีที่แล้ว

      There are usually multiple ways to solve physics problems and absolutely, one could find the acceleration using a motion detector and use the velocity as a function of time. Instead of using a motion sensor, we could also measure the final velocity using the photogate, with velocity initial of zero and the change in time we can determine the acceleration.
      I wanted to show an actual measurement of a force as a function of time and I already have many videos about UAM. The point wasn't really to find acceleration, the point was to understand Newton's Second Law and I thought it would be fun to find the force of friction between the cart and the track.
      Also, I have another video in the works which is an extension of this one. That video will explain why the tension force in the string changes as a function of time even though the free body diagram on the mass hanging doesn't change, which is often a stumbling block for students.

    • @WeAreShowboat
      @WeAreShowboat 10 ปีที่แล้ว

      Can't wait to see it. I love these videos.

    • @FlippingPhysics
      @FlippingPhysics  10 ปีที่แล้ว

      We Are Showboat Glad you enjoy the videos. By the way, thanks for the suggestion on how to solve this problem. It reminded my that I need to reflect more on how I solve problems for my videos to see if there is an alternate, useful solution. Sometimes the one that occurs to me first isn't the best one and the more variety I have in my solutions, the better the education will be. So thanks.

  • @MrSoccerstud5
    @MrSoccerstud5 9 ปีที่แล้ว +1

    You are the best

  • @nataliamendiola8191
    @nataliamendiola8191 4 ปีที่แล้ว

    Mr.P when calculating for the force using mass times acceleration in the x direction, how come you only used the mass of the cart (.613kg) instead of adding both masses (.613kg+.055kg). ik they are in the same system but how do you know which situation you only focus on 1 mass and which you focus on both. is the acceleration not the same for both or am i mixing things here?

    • @FlippingPhysics
      @FlippingPhysics  4 ปีที่แล้ว +2

      The acceleration is the same for both the cart and the hanging mass.
      The force sensor is attached to the cart, therefore, the force measured is the force applied to the cart. This is why we summed the forces acting on the cart only.
      You can also sum the forces on the system (cart and hanging mass), however, that was not the approach I took in this video.

  • @ronerickson8083
    @ronerickson8083 5 ปีที่แล้ว

    Newton's Second Law of Motion needs a slight correction since they did not know about squaring a number in Newton's era we can assume that this may have been overlooked. As such (F=ma^2) is a natural correction that can be easily proofed through calculation, formulation, and experimentation. This correction is 33% more accurate if you do not accept it proof it yourself.

  • @oweznero
    @oweznero 7 ปีที่แล้ว +2

    Mr p are you on Twitter

    • @FlippingPhysics
      @FlippingPhysics  7 ปีที่แล้ว +2

      +Owez Khan's Science Yep. @FlippingPhysics

  • @georgerumachik3430
    @georgerumachik3430 ปีที่แล้ว

    can you review my problem let me know f I made any mistakes. thanks.

  • @dante3478
    @dante3478 9 ปีที่แล้ว

    I don't understand how you go from one equation: (UAM) to 2 times the change of displacement in the x direction divided by the change in time squared...

    • @FlippingPhysics
      @FlippingPhysics  9 ปีที่แล้ว

      +Fathom XalxTV I don't understand @ 6:15 Bobby describes the UAM equation and how he uses algebra to rearrange it to solve for acceleration in the x-direciton. It's algebra and knowing the initial velocity of the cart is zero. What _exactly_ is confusing you?

    • @dante3478
      @dante3478 9 ปีที่แล้ว

      +Flipping Physics Hi! I love how you reply to your subscribers! I don't understand how he rearranges the uam to solve for acceleration, is it just reversed?

    • @FlippingPhysics
      @FlippingPhysics  9 ปีที่แล้ว

      +Fathom XalxTV No, it is not just reversed. Δx=(Vi)(Δt)+(1/2)(a)Δt^2 with an initial velocity of zero becomes Δx=(1/2)(a)Δt^2 multiply through by 2 and switch sides gives (a)Δt^2=2Δx then divide by Δt^2 to get a=(2Δx)/(Δt^2).
      However, it confuses me that you are asking this because this is exactly what Bobby describes in the video which is why I make the videos because it is so annoying to try to write things like this out in a comment of a TH-cam video.
      Did any of that help?

    • @dante3478
      @dante3478 9 ปีที่แล้ว

      +Flipping Physics I understand, i didnt mean to make your day any harder than what it is. I believe I lack comprehension for this equation due to the fact that I suffered in algebra. Thank you though, I understand now, I had my dad explain it to me. Thank you!! These videos help me a lot with what my physics work

    • @FlippingPhysics
      @FlippingPhysics  9 ปีที่แล้ว

      +Fathom XalxTV No worries about my day. Sorry I seemed put off. Now I understand it is the algebra which is tripping you up. Glad to know I can help you ... and your dad as well :)

  • @anilkumarsharma8901
    @anilkumarsharma8901 2 ปีที่แล้ว

    Ma
    Mathon
    Mather
    Ma ta
    Matter
    Main
    Ma formula for force 🤣🤣🤣🤣🤣🤣🤣🤣🤣