StatMolThermo 08.01 Helmholtz Free Energy

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  • เผยแพร่เมื่อ 13 ก.ย. 2024

ความคิดเห็น • 19

  • @zsuzsannabarnaneszabo4094
    @zsuzsannabarnaneszabo4094 4 ปีที่แล้ว +1

    Thank you for sharing, it is so clear!

  • @mariaorsic9763
    @mariaorsic9763 5 ปีที่แล้ว +1

    Finally, someone explained this clearly! Thank you!

  • @kubawlo
    @kubawlo 5 ปีที่แล้ว +1

    I found this course way too late... It is so useful to understand also the classical thermodynamics and get the feeling rather than an empty notion of all these S, H, F, G... Thank you for doing an excellent pedagogical job!

    • @kubawlo
      @kubawlo 5 ปีที่แล้ว

      By the way, where would be the best place to start investigating the partition functions for liquids, particularly in light of activity coefficients in concentrated solutions?

    • @ChemProfCramer
      @ChemProfCramer  5 ปีที่แล้ว

      so glad to get your perspective, and pleased to have been helpful!

  • @LibertyAzad
    @LibertyAzad 5 ปีที่แล้ว +1

    Illuminating explanation. Than you so much!

    • @ChemProfCramer
      @ChemProfCramer  5 ปีที่แล้ว

      Always a pleasure to learn people find the videos useful, thanks!

  • @jakubjan44
    @jakubjan44 8 ปีที่แล้ว +1

    Grate tutorial to thermodynamics!

    • @ChemProfCramer
      @ChemProfCramer  8 ปีที่แล้ว

      Very glad to know you found it useful -- thanks for the feedback!

  • @eoncarlyle
    @eoncarlyle 6 ปีที่แล้ว +1

    Professor Cramer is the 🐐

  • @caiohussene9923
    @caiohussene9923 5 ปีที่แล้ว

    Best Professor ever

    • @ChemProfCramer
      @ChemProfCramer  5 ปีที่แล้ว +1

      aw... 😊

    • @caiohussene9923
      @caiohussene9923 5 ปีที่แล้ว

      @@ChemProfCramer I am graduating in chemistry next year and it is good to have examples like this. Not only you made it easy to understand but also the fact that you spend time doing it to teach other. Thank you for that

  • @mehmetbaran3450
    @mehmetbaran3450 6 ปีที่แล้ว

    The greatest puzzle in helmholtz free energy is this: If the volume is constant, how to extract work? No explanation I have seen up till this point is clear on this point..
    The only explanation I could construct was to form the ensemble from two parts, one expanding against the other, while keeping the total volume costant...

    • @ChemProfCramer
      @ChemProfCramer  6 ปีที่แล้ว

      To borrow a quote from: chemistry.stackexchange.com/questions/91255/what-is-non-pv-work-how-is-it-related-to-gibbs-energy
      PV work is only the work done during the change in volume. There can be different types of works that a system can do during a process, for instance: electrical work, work against gravity, work against friction, magnetic work, shaft work, etc. This is the concept of non expansion or non PV work. (And I'll add that the "etc." can include chemical work, transport work, and add my own etc.) So, don't let the elementary coursework's focus on ideal gases confuse you -- ideal gases are nice because we can put things in contact with them at equilibrium and use our near-analytical understanding of the ideal gas to understand the more complicated system in contact as well, but the more complicated systems can do many, many more kinds of work than can the ideal gas.

    • @solsticetwo3476
      @solsticetwo3476 5 ปีที่แล้ว

      I think the following:
      dU = dW + dQ
      dU

    • @gowrissshanker9109
      @gowrissshanker9109 3 ปีที่แล้ว

      Sir, can you give an example for constant temperature and volume process?