man, i really wish my teacher was you. my teacher is so confusing and explains things horribly. your 5 minute video explains everything that took my teacher 2 hours. Thank you so much
Mr. Brian, you, you are a true lifesaver. This was so hard for me to grasp in an entire 45-minute class, but with this 5-minute video, I understand this easier than the alphabet. Thank you for all you do.
Professor McLogan, your videos have been my lifeline throughout this semester! I can honestly attribute my success in the conics portion of my pre-calculus class to you and your fantastic videos. I made the (rather poor) decision to take a 5 credit pre-calculus class through my college's online program where the workload is very heavy, and I have struggled to keep up. Thanks to you, however, I've managed very well these past few weeks. Thank you once again for making such helpful material widely available to those who need it!
So my teacher does an amazing job of explaining himself but when it comes to test time I dont retain all the information so I have been checking out your videos this semester to help remind me of the formulas and procedures and these really help refresh my memory right before a test and its really helping me out.
I am from INDIA ... I understand your speed English language not properly but it sufficient for understanding this question......😎😎nice teaching method sir
Not sure if this will help, but many of you asked about what to do if the focus has a fraction, as my problem does. What he did without really saying it is he took the 4 from the focus and subtracted the 1 from the vertex to get 3. So, for instance if you have vertex (3,5) and focus (3, 79/16), you would do this: 79/16 minus 5/1 and find the least common denominator to get -1/16 as your "p". Once you do this, just slip it into your formula: (x-3) ^2 = 4 (-1/16) (y-5). Of course, you will need to multiply 4/1 and -1/16 to get -1/4. And then just use all your algebra 2 mathematics to solve the problem. Your final answer will be y = -4(x-3)^2 +5. I hope this is not confusing, if so I can give more details.
Another way that can help you figure out which standard equation to use is by remembering that the (x-h)^2=4c(y-k) equation is to look for the number in the coordinate that the vertex and focus both have in common. In this case that number is two, which lies on the X portion of the coordinate. Thereby, I remember that I have to use the (x-h)^2=4c(y-k) formula. If the vertex were at (0,3) and focus (0,-1) then I would find that the 0 is the common number that they both share, which is on the x and write the equation for the origin : X^2=4cy.
Thank you so much for all these videos, I was absent when we first went over this and whenever my teacher does these problems he rushes over it and barely explains. Probably because he normally teaches calculus and IAT is very easy to him and were one of the rare years he's teaching IAT instead of all calculus. I really needed this because most of the kids in my class cheat off each other on tests because no one gets it except the kids who have tutors teaching them and I feel extremely guilty when I cheat on tests.thanks again
you are very welcome! happy to be there for you, I know exactly the feeling of you and your students, been there many times. Let me know if there is anything else I can do to assist you
Im new to your subscription 😊 Thanks alot now I know how to find the standard equation 😊... So sir is it the final answer? Or I need to multiply it? Cause mine is X=1/8(x² - 4x +12)
dont know if you still needed help but, you would swap x-h and y-k, so it would be (y-k)=4p(x-h) if its opened to the right, or (y-k)= -4p(x-h) if it is opened to the left
not always above, because the parabola can open down left and right as well. Just remember that the parabola always opens towards the focus and the directrix is the opposite direction perpendicular to the axis of symmetry
i’m a bit confused, your description says (x-h)^2=4p(y-k) is for parabolas that open left or right but you used it in the video and the parabola opened up
Sir, how do we obtain standard equation form for horizontal parabola which consists of 2 cases present at left or right? And, even what about the vertical one? And how do you
@@KarenWasherGrudzien you have only 20 to 25 crore people very less population then surrender your country against covid 19 and we have 125 crore huge population fight against corona virus very systematic and proper way.. WHO praise India to fight against corona virus
xcrazydianax the distance between the focus and the vertex is 3 going up. The distance between the vertex and the directrix is 3 going down so either way p=3. Hope that helped =)
The letter p represent the distance between the focus, vertex and directrix. The focus is (2,4) and the vertex is (2,1) we only need to focus on the y, which are 4 and 1. You will need to count the spaces in between the focus and vertex which is 3 spaces. So you just plug in 3 where the p is and get 4(3); 12
Thanks for the video it really helped me out! I thought I was gonna do terrible the rest of the year and the regents (The test we take at the end of the year if you didnt know what it was) because in 2 hours of help per day I still never got it but by watching 5 minutes of your videos I get it completely. Also I was wondering was this filmed in front of a live class that your teaching?
Brian McLogan im sorry i really dont get it? because my teacher once used the equation (x-h)^2= -4p (y-k) so we've been equating it to -4p to get the p. is she correct?
4 Mistakes Students Make with This Parabola - th-cam.com/video/cPM33QYisWk/w-d-xo.html
man, i really wish my teacher was you. my teacher is so confusing and explains things horribly. your 5 minute video explains everything that took my teacher 2 hours.
Thank you so much
happy to help
Michael oh same!!
Same!!
Same! This is crazy lol. Thank you Brian.
Bro, I learnt how to graph from the standard form in 5 mins from these videos, and my teacher taught over 2 weeks and I didn't learn a thing
Mr. Brian, you, you are a true lifesaver. This was so hard for me to grasp in an entire 45-minute class, but with this 5-minute video, I understand this easier than the alphabet. Thank you for all you do.
Professor McLogan, your videos have been my lifeline throughout this semester! I can honestly attribute my success in the conics portion of my pre-calculus class to you and your fantastic videos. I made the (rather poor) decision to take a 5 credit pre-calculus class through my college's online program where the workload is very heavy, and I have struggled to keep up. Thanks to you, however, I've managed very well these past few weeks. Thank you once again for making such helpful material widely available to those who need it!
Very happy to be there for you Noah. Congrats on working hard and making the best of your decision. Your hard efforts will pay off.
Hlo sir❤️
Hello sir
I m from India and I always watch ur videos
Tq so much for ur efforts.😇
indian tech support
So my teacher does an amazing job of explaining himself but when it comes to test time I dont retain all the information so I have been checking out your videos this semester to help remind me of the formulas and procedures and these really help refresh my memory right before a test and its really helping me out.
Survived my SHS days with you professor and now here i am again for my 1st examination as a college student!!
You went to shs
You are like the only person that answers all my questions I am having trouble at, thanks man!
Catch me buying mclogang merch because mr mclogan teaches me more than my actual teacher
just spent a half hour looking for a way to do this, this was the only video that helped,. thanks mate keep it up
happy to be able to help
You are one of the Math Messiah during this Pandemic helping people through their stufies
I got an 100 on my test because of this video! Thank you so much
awesome! great work!
Thank you very much.
💕 from Philippines
can I ask why you add 12 on both sides on 4:30, thank you!
2nd part of my final exam tomorrow :P Thank you so much for your videos, they're a great method of reviewing
you are very welcome! best of luck!
Oh my goodness. THANK YOU SO MUCH! You made what seemed like hieroglyphics into something I can actually understand.
Awesome!!
With online learning this really helps!! thank you!
I am from INDIA ... I understand your speed English language not properly but it sufficient for understanding this question......😎😎nice teaching method sir
I understand you than my teacher who teaches thing for 1 HOURRR, thank you for this!!
I am from india . It clears my concept.thnx dear professor
OMG!! You literally have done all the questions that i need help with. Best teacher in the world!!!
happy to be there for you Esha!
Your videos are really a lifesaver!
Your video helped me a lot in my studies. Thank you!!!
Not sure if this will help, but many of you asked about what to do if the focus has a fraction, as my problem does. What he did without really saying it is he took the 4 from the focus and subtracted the 1 from the vertex to get 3. So, for instance if you have vertex (3,5) and focus (3, 79/16), you would do this: 79/16 minus 5/1 and find the least common denominator to get -1/16 as your "p". Once you do this, just slip it into your formula: (x-3) ^2 = 4 (-1/16) (y-5). Of course, you will need to multiply 4/1 and -1/16 to get -1/4. And then just use all your algebra 2 mathematics to solve the problem. Your final answer will be y = -4(x-3)^2 +5. I hope this is not confusing, if so I can give more details.
Hello Mr McLogan, do you have videos on how to find the directix and foci of quadratic parabolas on your yt channel?
U literally save me for my test tomorrow
thanks very much it has really helped me, i will not let myself miss any of your tutorials.
thanks once again
be careful, I upload a lot! However I do have 90% of my videos organized in playlists so that should help you out for multiple examples
i wish my teacher will learn from you sir... thanks for your vids
Oh my god thank you sir you save me from my pre calculus subject I love you sir
Another way that can help you figure out which standard equation to use is by remembering that the (x-h)^2=4c(y-k) equation is to look for the number in the coordinate that the vertex and focus both have in common. In this case that number is two, which lies on the X portion of the coordinate. Thereby, I remember that I have to use the (x-h)^2=4c(y-k) formula. If the vertex were at (0,3) and focus (0,-1) then I would find that the 0 is the common number that they both share, which is on the x and write the equation for the origin : X^2=4cy.
thanks for sharing
You're the real
GOAT
What would u do if its in a fraction form likr the vertex for example is -1,-3 then the focus is -17/16,-3
you explain better than my teacher. she just uses the textbook to explain us . thanks for your videos
+Gustavo Rodriguez you are very welcome! happy to be able to help you out!
your videos help me a lot. continue making more!
Thank you so much for all these videos, I was absent when we first went over this and whenever my teacher does these problems he rushes over it and barely explains. Probably because he normally teaches calculus and IAT is very easy to him and were one of the rare years he's teaching IAT instead of all calculus. I really needed this because most of the kids in my class cheat off each other on tests because no one gets it except the kids who have tutors teaching them and I feel extremely guilty when I cheat on tests.thanks again
you are very welcome! happy to be there for you, I know exactly the feeling of you and your students, been there many times. Let me know if there is anything else I can do to assist you
For the (x-2)^2 portion, how did you get x^2 -4x-+4?
i was wondering this too but this comment is a year old :(
@@luci316 he expanded it making it (x-2)(x-2) then solving to x^2-4x+4
Im new to your subscription 😊 Thanks alot now I know how to find the standard equation 😊... So sir is it the final answer? Or I need to multiply it? Cause mine is X=1/8(x² - 4x +12)
1:15 you marked your head
Bringing you back 7 years :)
@@pat1373 Bringing you back 7 months :)
@@nakiro1646 bringing u back 2 months
@@logank8727 bringing you back 3 weeks later
@@usherrepeating Me rn doing my hmwk at 9 pm
How do you make an equation if all you get is the focus? For an example the focus is (0, 1/3). How would you solve that?
This video is very helpful. I was wondering what equation you would use if the parabola was horizontal?
dont know if you still needed help but, you would swap x-h and y-k, so it would be (y-k)=4p(x-h) if its opened to the right, or (y-k)= -4p(x-h) if it is opened to the left
sir u're my savior
omg man thank you im taking a test and you just saved my life though
sweeet! happy to help, hope you did well!
haha same
Is the focus above and the directrix always behind the vertex of the parabola?
not always above, because the parabola can open down left and right as well. Just remember that the parabola always opens towards the focus and the directrix is the opposite direction perpendicular to the axis of symmetry
Wow this video really helped me for my quiz and now I'm currently studying for my last midterm and final... With that said thank you very much.
you are very welcome! happy to help you out
I wish that the teachers in india could have been like you
Thank you so much sir .
You helped me a lot.
Thank you for the guide and hopefully I ace my test in a couple of hours.
hope you do as well, best of luck
hi! I just want to ask how did you get the p?
Thank for the video..it helps me lot..want video lecture on calculus..
thankyou soo much the book i use made it soo complicated to understand
i’m a bit confused, your description says (x-h)^2=4p(y-k) is for parabolas that open left or right but you used it in the video and the parabola opened up
Tnk u sir ur vedios are amazing. U explained it very easily that my tuition teacher was unable to do.
happy to be there to help you out!
Sir, how do we obtain standard equation form for horizontal parabola which consists of 2 cases present at left or right?
And, even what about the vertical one?
And how do you
Thank you! If if you didnt make theese videos i would never graduate.
happy to be able to support you, your hard work is paying off
Thanks man, even though posted 4years ago it's still helping me out
that is why I love TH-cam
This is really great.... I have understand, ready for exam now
awesome! happy to help
Believe us. Thank you. I feel sorry for my parents if they found out that I've learned from TH-cam not in my University 😂. Thank you so much sir!
haha, happy to be there for you
Hey we have the same last name
@@cledlirahariola7454 Hey waddup! Studying for Online Class?
@@chambinabi9646 yup
Love from India 🇮🇳🇮🇳🇮🇳
@@KarenWasherGrudzien you have also delta and beta variant of corona virus..
@@KarenWasherGrudzien you have only 20 to 25 crore people very less population then surrender your country against covid 19 and we have 125 crore huge population fight against corona virus very systematic and proper way.. WHO praise India to fight against corona virus
Where can i get teh entire playlost
I am sort of confused how you got the 3 for the absolute value.. How did you get it?
xcrazydianax what point in the video are you referring to?
Mr. McLogan's Math Channel Around @3:31
xcrazydianax the distance between the focus and the vertex is 3 going up. The distance between the vertex and the directrix is 3 going down so either way p=3. Hope that helped =)
been there done that! haha
Brian McLogan I think you forgot to write squared while you were solbing for the perfect swuare trinomial it must X squared minus 4x plus 4
@@giaannevillagracialaguyo5988 yeah his girl cprrected him
Thanks Mr. McLogan. Your explanation was amazing! : )
you are very welcome! happy to be able to help
Hi guysss, may I ask how did the professor get the 3 beside the 4 and it becomes 4(3)
The letter p represent the distance between the focus, vertex and directrix. The focus is (2,4) and the vertex is (2,1) we only need to focus on the y, which are 4 and 1. You will need to count the spaces in between the focus and vertex which is 3 spaces. So you just plug in 3 where the p is and get 4(3); 12
very well explained👍
I think you switched up the h, k values for both formulas in the comment sections maybe I'm wrong ,can you tell me if I am?
Thank you so much!
Sir. Why do you plus both side by 12?
to isolate the y
Professor youre the best
Sir superb explanation sir well understood
Thank u so much, you saved my life
Happy to be able to help you out!
What if some of the given is negative?
How did you get the -4 in x^2-4x+4=12y-12
Never mind, you foil. Thanks for the instructional video
correct
Brian McLogan thanks for the videos. they are verry helpful
Thanks for the video it really helped me out! I thought I was gonna do terrible the rest of the year and the regents (The test we take at the end of the year if you didnt know what it was) because in 2 hours of help per day I still never got it but by watching 5 minutes of your videos I get it completely. Also I was wondering was this filmed in front of a live class that your teaching?
+JackLeahy'sChannel great to hear, and I hope you do really well on your test, yes I record myself actually teaching every day
where u got the +12 thingy?
Sir Benedict Quejado same question
Thank you so much!! Your videos are very helpful
+MrTrollygames awesome! happy to be able to help!
Sir amazing i am from India thank you sir
How do you solve for y=28x because I used the equation (h,k+p) to find the focus but my teacher said it was wrong.
what do you mean solve for which variable is squared?
+Brian McLogan y is squared and thank you for responding!
your teacher is correct, since y is squared your parabola opens left or right so your focus would be (h+p,k)
literally my mind makes sense of this
You have a video for everything thank you
you are very welcome!
that thing on your head was distracting me
it was a boo boo
@@drewsimone100 😁😂
What if the parabola has equation in quadratic in both x and y ,how to solve it ?
then it is an ellipse not a parabola
Can you make a video for Parabolic comet problems?
+Rainman 10 sorry I am not teaching that this year
What to do if my vertex is at (0,0)
Finally I cleared my doubt with the help of eight year's old video...
What if it opens to the right?
thank you so much i had no idea what i was doing before
THANKS FOR THIS!
you are very welcome!
uhmmm what if the p is positive but your parabola opens up?then the 4 in 4p would be negative???
or does your p needs to be negative right away? and do you always multiply it to positive 4??? in 4p???
if the parabola opens up or to the right p is positive, down and left it is negative
Brian McLogan so the 4 in 4p is constant? it will not be negative? the p is the one that will bring negative?
no if the parabola opens left or down 4p is negative
Brian McLogan im sorry i really dont get it? because my teacher once used the equation (x-h)^2= -4p (y-k) so we've been equating it to -4p to get the p. is she correct?
Amazing explanation.
What if you have to find the standard form using only the focus?
you will need more information that just the focus
you teach better in 5 minutes than my teacher in 2 hours! WTF! she says nonsense!
sorry to hear, but very happy to be able to help you out
Hi sir can you help me how to find the vertex, focus, axis of symmetry and the equationof the directrix given the equation
How would you write the vertex form equation and the standard form equation of a parabola when the vertex and focus are both provided?
so you find your equation, plug in the knowns, and then fit it into either the standard form or vertex form?
plug it in to vertex form, then expand to write in standard form
But what if the focus has a fraction
is that y=1/12(x²-4x+16) ???
yes
What if its vertex (-3,1) focus (-1,1)? Is there a different equation
your final equation will be different but the process outlined in the video will be the same
Howd you find the h and k?(the X minus ___ and y minus ___)
those are the values of the vertex
Brian McLogan so vertex is center?
no vertex is on a parabola, center is similar for ellipse and hyperbola
Brian McLogan ohh ok thanks sir
Thank you!
I'm struggling to answer this question, find the equation of the locus of the point(x,y),which is equidistant from the point (2,0) and y-axis
sorry I started school this week so focusing on classes
what if the vertex is (0,0) and the focus is (0,4) ??? how do i write the standard equation
same process,