Excellent video session Sir! Great overall explanation of CIDR (CIDER), awesome slides, great Audio...very Professional. Keep them coming!!!! an A+ for you Sir.
am confused on how to perform the math for range 192.168.1.0 through 192.168.1.255(254 hosts),i don't know how we are getting this.kindly help and if they is any tutorial about you can re -direct to it.
There are technically 256 hosts. We say 254 available hosts when we do subnetting because we don't use the network address (192.168.1.0) and the broadcast address (192.168.1.255). 256-2=254
Ok, I don't think other folks explained this well, but I figured it out and was very confused at first. Let me try to better explain this for future reference: 0000 0000 is 1 count , now doing the binary math 1111 1111 is 255 count. You get 256 from the two different binaries, everyone forgets that zero counts as an item! so there are 256 possibilities with 8 binary digits, 1111 1111 = 255 + 0000 0000 = 1 = 256 !!! Now, you subtract the two reference hosts that the instructor said we don't count ... the network host... 0 and the broadcast host... 255 and we get 256-2 = 254 possibilities. You're Welcome.
I do not get when getting the address or host per subnet what do you to subtract 2 to get 254 or 65,534 and so on can someone help? what needs to be subtracted to get the correct host per subnet?
If you study the IP address classes, you will see how every class has a different subnet mask that allows you to create subnets and subsequent hosts. Every single part of the ip is divided into 8 bits and if you consider class C ip addresses, you have last 8 bits for the host. Now, the very 1st bit of the 8 bits is used to identify the subnet to which your destination ip address belongs, and the very last bit of the 8 bits is used as a directed loopback address, more like a loopback address to local host. So clearly, the 1st and last bits cannot be used to assign ip addresses to a host. Hence, you subtract 2. So for Class C IPs that can have a total of 256 hosts, 1st host is used to identify the subnet and the last host is used as a directed-loopback address. So now you are left with 256-2 = 254 IP addresses that you can assign to your hosts. I hope this helps!
Ok, I don't think other folks explained this well, but I figured it out and was very confused at first. Let me try to better explain this for future reference: 0000 0000 is 1 count , now doing the binary math 1111 1111 is 255 count. You get 256 from the two different binaries, everyone forgets that zero counts as an item! so there are 256 possibilities with 8 binary digits, 1111 1111 = 255 + 0000 0000 = 1 = 256 !!! Now, you subtract the two reference hosts that the instructor said we don't count ... the network host... 0 and the broadcast host... 255 and we get 256-2 = 254 possibilities. You're Welcome.
Confused at how the CIDR notation adds up in the last part regarding MCI. The 1's under MCI only add up to 4 and to 8 under Automation Research Systems. How did they end up with /11 and /22?
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I've watched countless videos on this subject, could never grasp it. You just cleared it right up. THANK YOU
Sweet baby jesus I think I love you.
JUST grasped this! What a wonderful video! Thank you Professor Messer!! It all makes sense now!
Excellent video session Sir! Great overall explanation of CIDR (CIDER), awesome slides, great Audio...very Professional. Keep them coming!!!! an A+ for you Sir.
am confused on how to perform the math for range 192.168.1.0 through 192.168.1.255(254 hosts),i don't know how we are getting this.kindly help and if they is any tutorial about you can re -direct to it.
There are technically 256 hosts. We say 254 available hosts when we do subnetting because we don't use the network address (192.168.1.0) and the broadcast address (192.168.1.255). 256-2=254
Ok, I don't think other folks explained this well, but I figured it out and was very confused at first. Let me try to better explain this for future reference: 0000 0000 is 1 count , now doing the binary math 1111 1111 is 255 count. You get 256 from the two different binaries, everyone forgets that zero counts as an item! so there are 256 possibilities with 8 binary digits, 1111 1111 = 255 + 0000 0000 = 1 = 256 !!! Now, you subtract the two reference hosts that the instructor said we don't count ... the network host... 0 and the broadcast host... 255 and we get 256-2 = 254 possibilities. You're Welcome.
I have a question: So the purpose of CIDR is to use more bits than having to choose from 8, 17, and 24?
I do not get when getting the address or host per subnet what do you to subtract 2 to get 254 or 65,534 and so on can someone help? what needs to be subtracted to get the correct host per subnet?
If you study the IP address classes, you will see how every class has a different subnet mask that allows you to create subnets and subsequent hosts. Every single part of the ip is divided into 8 bits and if you consider class C ip addresses, you have last 8 bits for the host. Now, the very 1st bit of the 8 bits is used to identify the subnet to which your destination ip address belongs, and the very last bit of the 8 bits is used as a directed loopback address, more like a loopback address to local host. So clearly, the 1st and last bits cannot be used to assign ip addresses to a host. Hence, you subtract 2. So for Class C IPs that can have a total of 256 hosts, 1st host is used to identify the subnet and the last host is used as a directed-loopback address. So now you are left with 256-2 = 254 IP addresses that you can assign to your hosts. I hope this helps!
Ok, I don't think other folks explained this well, but I figured it out and was very confused at first. Let me try to better explain this for future reference: 0000 0000 is 1 count , now doing the binary math 1111 1111 is 255 count. You get 256 from the two different binaries, everyone forgets that zero counts as an item! so there are 256 possibilities with 8 binary digits, 1111 1111 = 255 + 0000 0000 = 1 = 256 !!! Now, you subtract the two reference hosts that the instructor said we don't count ... the network host... 0 and the broadcast host... 255 and we get 256-2 = 254 possibilities. You're Welcome.
you r good man. thanks a lot
Crystal. Clear.
Confused at how the CIDR notation adds up in the last part regarding MCI. The 1's under MCI only add up to 4 and to 8 under Automation Research Systems. How did they end up with /11 and /22?
The CIDR block describes the number of bits in the subnet mask, not the number of ones in the binary representation of the IP address.