week1

[@hazard2576]

@2:00:47 how come the node Vp is at 3/5 of Av. Im stuck at that part .

[@satwikbhat_18]

Applying voltage divider rule, you get Vp=AVe(15/(15+10)) = (3/5)AVe

[@KrushiRaj-r9g]

sir how it is 3/5AVe at Vp side by calulating using voltage divider formula it should be
Ave*(15/5+15)=3/4AVe.
Vp-Vn= 3/4AVe-AVe= -1/4AVe -> -ve feedback ..
I eagerly await your response sir.