Codeforces Round 843 Div 2 | Problem B : Gardener And The Array Solution | Newton School

[@KaranMashru]

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Code :
#include
using namespace std;
#define ll long long
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);

ll t, f, i, j, n, p;
string ans;

cin>>t;

for(;t--;)
{
cin>>n;

unordered_map mp;

ll k[n];
vector bits[n];

for(i=0; i>k[i];

for(j=0; j>p;
if(mp.find(p)==mp.end()){
mp[p]=1;
}else{
mp[p]++;
}
bits[i].push_back(p);
}
}

ans="NO";

for(i=0; i

[@haste291]

sir how to store whole bits in one index
in this line bits[i].push_back(p);

[@mannumichel1925]

@@haste291 😄aree bhai idhar push_back ho rha hai , vector in c++ ka property hai push_back karne se element attach ho jata hai last mein vector k. Tum ek bar vector in c++ ka video dekh lo samajh jawoge.

[@saurabh.gupta22]

Great Explanation sir

[@beinghappy9223]

Thanks for the amazing explanation .You are doing a great work

[@reddotcheese]

Great Explanation sir.

[@yashagrawal1663]

thank you so much

[@varunakrishnani7688]

Thank you! 😊🙏🏻

[@aradhyapandey1489]

nice explanation!!

[@jerichoicbm6648]

Any specific reason for taking the subsequence of size n(the total numbers) and not k(

[@codingcommunitynewtonschoo8582]

If I consider all n elements , then after remaining 1 element, the chances of OR value remaining same is more. Eg : if n = 10, so in one subsequence I take all 10 elements and in another I take 5 elements. Now, I remove one same element from both subsequence. Now, chances of subsequence having 9 elements and OR value same is more then subsequence having 4 elements. There are 5 more elements in bigger subsequence to fulfill the requirement of the set bits of the element which is removed.
I hope you got my point.

[@hariharibolll3459]

I Have applied the same logic but it gives TLE On Test 5 .Here is the code :
#include
using namespace std;
#define ll long long int
const int N = 2e5+10;
int main(){
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
#ifndef ONLINE_JUDGE
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
#endif
int t;cin>>t;
while(t--){
int arr[N];
memset(arr,0,sizeof(arr));
arr[0] = 1;
ll q ;cin>>q;
ll qq = q;
int ff =0;
vectorbits[q];
for(ll j= 0;j>n;
for(ll i = 0;i>y;
bits[j].push_back(y);
arr[y]++;
}


}
for(vectorx:bits){
int f = 1;
for(ll i= 0;i

[@codingcommunitynewtonschoo8582]

Use unordered map instead of arr....

[@hariharibolll3459]

@@codingcommunitynewtonschoo8582 Yes is got accepted by using map. Thanku PrabhuJi for replying 🙏🌸

[@siddhantnigam2015]

@@codingcommunitynewtonschoo8582 why does it give TLE?

[@hariharibolll3459]

@@siddhantnigam2015 Hare Krishna PrabhuJi. It gives TLE because memset(arr) is done by running a loop of 10^5 . so doing it again and again for each test case will give TLE

[@HarshKumar-jx3ds]

hey can you explain what's wrong with my code, it gives WA at some hidden test case
#include
using namespace std;
#define int long long
#define pairs pair
#define vll vector
#define vps vector
#define ip(arr) for(int i = 0; i < arr.size(); i++) cin >> arr[i];
#define op(arr) for(int i = 0; i < arr.size(); i++) { cout k;
vll curr;
while(k--){
int temp;
cin>>temp;
curr.push_back(temp);
}
arr.push_back(curr);
}
bool ans1 = solve(arr);
reverse(all(arr));
bool ans2 = solve(arr);
bool ans = ans1||ans2;
cout

[@vimalkumardubey6834]

Sir apni codeforces id bataiye !

[@user-zw3di8fv9z]

sir aap please koi example leke samjha diya kariye.
aise jyada nahi samajh aata.

[@nitintyagi7105]

+1