Love your stuff Derek...thank you very much for making it available to people. It's a GREAT review if one has taken courses that taught this material in the past, but then haven't used it in a while. I especially like the way you stress dimensional homogeneity. It's the first step in ensuring the reasonableness of an answer, yet so many people simply neglect it. Off to review Calculus with your material, so thanks again!!!
Thank you, THANK YOU!! I've seen the 8 videos of Projectile Motion and I understood everything!. At the end all you need to know is X= X0+VoxT+1/2aT^2 (and the same for Y) and then you have to realize when a or V is zero or negative. I hope I can do now some problems of charged particles moving in an uniform electric field.
wait i dont get why the Final height Y is = 0. Because I start off by finding the height by using this formula v^2=Vo^2 + 2ay, so by rearranging it and substitution i should get: y= v^2 - vo^2 / 2(a) which is y= 0 - 151.54 / -19.6 yFinal = 7.73m then to solve for time i use t = √2(y)/a so t = √15.46/-9.80 time = 1.26s could you please explain what i did wrong? thank you so much!
Hello Derek! Your calculus and Physics videos are terrific! I am taking Physics for Engineers and am struggling with a projectile motion problem involving a projectile object stiking a falling object. Could you please help me with such a question. Thanks, Lee
is there any reason why you couldn't use formulas' derived from calculus? x=(v^2 . sin2θ)/gravity I get the same answer in one formula. Just an idea ^_^
oh i think i know what i did there! I solved for the apex of the football which is 7.73m which gives me half the time it take takes to reach its maximum distance! 2.51/2 = 1.26s! thanks
as there in no air resistance considered, there is no other force acting acting on object horizontally except the the force applied (kick in this case) that will make the ball move in the speed as initial velocity horizontally or the speed with which the ball is kicked (horizontal speed) for the whole journey
![จบจนได้ ! | Black Myth: Wukong #007 [ตอนจบ?]](http://i.ytimg.com/vi/DSqvWndF0sw/mqdefault.jpg)
![ฮักเทื่อสุดท้าย - บอย ศิริชัย [OFFICIAL MV]](http://i.ytimg.com/vi/-1PoPoQ-B-k/mqdefault.jpg)
Thank you so much sir! 14 years this video is still rolling and we're so glad for its existence! Thankk youu
Love your stuff Derek...thank you very much for making it available to people. It's a GREAT review if one has taken courses that taught this material in the past, but then haven't used it in a while. I especially like the way you stress dimensional homogeneity. It's the first step in ensuring the reasonableness of an answer, yet so many people simply neglect it. Off to review Calculus with your material, so thanks again!!!
finally i have found the person who can explain much better thank u and keeping doing ur work may the Lord bless you
Thank you, THANK YOU!! I've seen the 8 videos of Projectile Motion and I understood everything!. At the end all you need to know is X= X0+VoxT+1/2aT^2 (and the same for Y) and then you have to realize when a or V is zero or negative. I hope I can do now some problems of charged particles moving in an uniform electric field.
you have no idea how much you have helped me thank you so much!!!!
finally someone who completes a damn problem
your amazing I love the way ur teaching thank u soo much
THANK YOU! I watched all 8 of your videos, and i got the idea of projectile motion! :D
Thanks Derek you are making my finals week MUCH easier.
Your handwriting is so amazing and thanks this helped me a lot in physics
Seriously, your explanation about this is very clear and understandable. Thanks for this!
Thanks, this practical example helps.
I have watched all of your physics practice problems and my test is tmrw. I will let you know how i do. These have been great help.
Thanks
wait i dont get why the Final height Y is = 0. Because I start off by finding the height by using this formula v^2=Vo^2 + 2ay, so by rearranging it and substitution i should get:
y= v^2 - vo^2 / 2(a) which is y= 0 - 151.54 / -19.6 yFinal = 7.73m
then to solve for time i use t = √2(y)/a so t = √15.46/-9.80 time = 1.26s
could you please explain what i did wrong? thank you so much!
@VaisaNacia You probably could. There are usually multiple ways to solve a given problem.
I love ur physics practice problems I have exam in TUS
wish me luck
your both drawing and explaining is very nice
Hello Derek! Your calculus and Physics videos are terrific! I am taking Physics for Engineers and am struggling with a projectile motion problem involving a projectile object stiking a falling object. Could you please help me with such a question.
Thanks,
Lee
very good tutorials! thank you
THANK YOU SO MUCH your the BOMB!!
THIS IS GREAT I LOVE YOU
is there any reason why you couldn't use formulas' derived from calculus?
x=(v^2 . sin2θ)/gravity
I get the same answer in one formula. Just an idea ^_^
Awesome thanks!
man, talk about high pass filter! lol. but your handwriting is pretty darn good!
well explained!!
oh i think i know what i did there! I solved for the apex of the football which is 7.73m which gives me half the time it take takes to reach its maximum distance! 2.51/2 = 1.26s!
thanks
when solving the horizontal why is acceleration 0?
as there in no air resistance considered, there is no other force acting acting on object horizontally except the the force applied (kick in this case) that will make the ball move in the speed as initial velocity horizontally or the speed with which the ball is kicked (horizontal speed) for the whole journey
What app did you use as your calculator sir?
I usually use an emulator program called VTI. I would love to find a similar app for the TI-84 Plus CE.
How is it possible that every video I watch from you, it feels like I didn't learn anything from the previous one I watched?