I have to identical speaker connected to a computer playing the same song. I tried to place the speaker opposite from each other and 90 degree from each other but I did not get destructive interference. How do I position the two speaker so that I will get 100% destructive interference (no sound or almost no sound).
Hi GPB Education. I have two identical speakers connected to a computer playing the same song. I did placed the two speakers opposite from each other and 90 degree from each other but I did not get destructive interference. How do I position the two speakers so that I will get 100% destructive interference (no sound or almost no sound) ?
Mathematically, when the waves are identical but 180 degrees out of phase, they are in fact each other's negative counterparts. In physical terms, when the other wave creates an increase in air pressure, the other creates an identical amount of decrease, and vice versa, resulting in no change of air pressure = no sound.
*I concur* Given an isolated table-top demonstration a "beam" of sufficiently narrow focal tightness should display backscattering which should show that "light" it the normal senses ( rainbow) is only narrow spectra with hard backscattering such that Rutherford backscattering spectrometry would display on-beam lambda within 0.04 degrees of neutral axis displaying the most conserved tensor with a neutral at 90° then reduction of "frequency" toward near-zero in the backreaction
Don't believe everything you see on TH-cam!! The thunder high crack - low rumble phenomenon is a better example of the atmospheric absorption of sound than of the diffraction of sound. Lightening in the desert or on the plains will still sound low when it is further away even though there are no obstacles (diffraction) between your ears and the source. Atmospheric absorption is based on a combination of viscous & thermal conduction effects as well as molecular relaxation processes. The attenuation curve is roughly the square of frequency. See: ANSI standards S1-26:1995, "Calculations of the Absorption of Sound by the atmosphere" (ISO 9613-1:1996) andH.E. Bass, et al, "Atmospheric absorption of sound: Further developments", J. Acoust. Soc. Am., 97(1), 680-683 (1995).
my man really called cornelius
Bruh why youtubers better at teaching then my teachers
"To understand the universe, one must think in terms of energy, frequency, and vibration."
Nikola Tesla
Thank you so much ma'am every concept is crystal clear
Well explained! I just need something like this in my class. Thank you so much.
I have to identical speaker connected to a computer playing the same song. I tried to place the speaker opposite from each other and 90 degree from each other but I did not get destructive interference. How do I position the two speaker so that I will get 100% destructive interference (no sound or almost no sound).
Super explanation
I love 😍 it
Hi GPB Education. I have two identical speakers connected to a computer playing the same song. I did placed the two speakers opposite from each other and 90 degree from each other but I did not get destructive interference. How do I position the two speakers so that I will get 100% destructive interference (no sound or almost no sound) ?
Nice illustrations. Thank you.
excellent video
Who is the speaker? she is not among the teachers listed in the website
Hello, what I really wonder is how we can obtain the attenuation in two waves after having the interference?
Mathematically, when the waves are identical but 180 degrees out of phase, they are in fact each other's negative counterparts. In physical terms, when the other wave creates an increase in air pressure, the other creates an identical amount of decrease, and vice versa, resulting in no change of air pressure = no sound.
Love the energy 😍🤍really thank u for this video
Thanks for watching!
Me: sitting 2 weeks after my work is due at 10 pm watching this for homework
Amazing explaition
yo how is diffraction defined in this video
@Julian thx bruh
Julian thanks julian ily
why is cornelius acting like a statue at 7:33
my jaw dropped when she explained beat frequency 7:32, so cool
How do you calculate how much a sound wave of a given frequency diffracts?
Thorough
very good explanation, why so few likes
Chopin's Polonaise in C#minor, 2nd theme.
cornelius is da goat
yessir!
They don’t ‘bend’ ... they reflect.
Elephants talk through the ground
"bending" does not make much sense
*I concur*
Given an isolated table-top demonstration a "beam" of sufficiently narrow focal tightness should display backscattering which should show that "light" it the normal senses ( rainbow) is only narrow spectra with hard backscattering such that Rutherford backscattering spectrometry would display on-beam lambda within 0.04 degrees of neutral axis displaying the most conserved tensor with a neutral at 90° then reduction of "frequency" toward near-zero in the backreaction
Don't believe everything you see on TH-cam!! The thunder high crack - low rumble phenomenon is a better example of the atmospheric absorption of sound than of the diffraction of sound. Lightening in the desert or on the plains will still sound low when it is further away even though there are no obstacles (diffraction) between your ears and the source. Atmospheric absorption is based on a combination of viscous & thermal conduction effects as well as molecular relaxation processes. The attenuation curve is roughly the square of frequency. See: ANSI standards S1-26:1995, "Calculations of the Absorption of Sound by the atmosphere" (ISO 9613-1:1996) andH.E. Bass, et al, "Atmospheric absorption of sound: Further developments", J. Acoust. Soc. Am., 97(1), 680-683 (1995).
hi tillie
hi orelia!
workout?