sir i think when rho=sigma(36:27), the body will stay where it is left it need not float with it's surface with liq, because the net force on body on body is zero.
Hello sir,,,, l wanted to ask you a question that how can I contact you....... In which school do you teach sir???? Please reply when you see this message.........
sir we have derive formula for volume of solid=loss in weight(divided by)density of water. but sir loss in weight is equal to upthrust so i think we need to be more precise and formula should be volume of solid=loss in mass (of solid) divided by density of water so that gravity will not be included.sir am i right or it does not make any difference.
Anayta Amisha since i had this doubt 4 month ago i have cleared it up.actually loss in weight =buoyant force=weight of fluid displaced by solid =mass of fluid displaced multiplied by 'g' and mass of fluid displaced=volume of solid multiplied by density of fluid so loss in weight of solid=volume of solid multiplied by density of fluid multiplied by g .and by arranging this equation and taking volume of solid on one side we get volume of solid =loss in weight divided by both -density of fluid and g.so here there is mistake in video there should be g as well.
Respected Sir .. as you said ..Relative Density = Density of the sub. / Density of the water but in many books I've read ... relative density = density of the sub / density of water at 4 degree Celsius !! why so sir ??
Actually relative density=density of sub/density of water at 4 deg celsius. this is because it is at 4 deg celsius that water has a density of 1000 kg/metre cube. when sir has said that Relative Density = Density of the sub. / Density of the water, he actually assumes that water is at 4 deg celsius and has a density of 1000kg/metre cube. I think that answers your question...
Great service to humanity
nice videos for understanding physics concepts very easily.
Make interest in physics
please explain working aneroid barometer
The students in ur class r very lucky sir as they are taught by you............
thank you sir...you made many students' interest in physics.
Excellent work
Great teacher !!
Dear sir,
in calculating the dipping of boat, how the up thrust = the weight of the person gets into the boat,please explain Sir...
sir i think when rho=sigma(36:27), the body will stay where it is left it need not float with it's surface with liq, because the net force on body on body is zero.
Sir,
In barometer what will happen if we increase the area of the container,the height above free surface will change or not?..
Sir the topic measurement of pressure difference( Gauge pressure) is missing in the lecture
Hello sir,,,, l wanted to ask you a question that how can I contact you....... In which school do you teach sir???? Please reply when you see this message.........
sir your videos have helped me a lot in physics... but to whom should i refer for physics and chemistry to get my concepts clear
Sir what will happen when we increase the surface area of the container....
Will the height of mercury be still 760mm.
Sir, when v immerse 5kg wt solid, why dnt the upthrust bcmz 5kg?
that is bcuz density of block is more than water so vpg>vkg where p is density of block and k is density of water. easy yaar!
Thank you Sir...!
sir we have derive formula for volume of solid=loss in weight(divided by)density of water. but sir loss in weight is equal to upthrust so i think we need to be more precise and formula should be volume of solid=loss in mass (of solid) divided by density of water so that gravity will not be included.sir am i right or it does not make any difference.
shaikh zoya even i have the same doubt
Anayta Amisha since i had this doubt 4 month ago i have cleared it up.actually loss in weight =buoyant force=weight of fluid displaced by solid =mass of fluid displaced multiplied by 'g' and mass of fluid displaced=volume of solid multiplied by density of fluid so loss in weight of solid=volume of solid multiplied by density of fluid multiplied by g .and by arranging this equation and taking volume of solid on one side we get volume of solid =loss in weight divided by both -density of fluid and g.so here there is mistake in video there should be g as well.
sir how can one contact you??
Respected Sir ..
as you said ..Relative Density = Density of the sub. / Density of the water
but in many books I've read ...
relative density = density of the sub / density of water at 4 degree Celsius !!
why so sir ??
Actually relative density=density of sub/density of water at 4 deg celsius. this is because it is at 4 deg celsius that water has a density of 1000 kg/metre cube.
when sir has said that Relative Density = Density of the sub. / Density of the water, he actually assumes that water is at 4 deg celsius and has a density of 1000kg/metre cube. I think that answers your question...
thank you so much :)
sir hydraulics is missing ?
sir many many thanks
Respected Sir,,
Sir,this video is XI_79.....You have already uploaded XI_75...:)
Sir, you should start uploading 10 day crash course for medical & engineering aspirants. We will be very thankful.
Thanks a lot of sir
Sir. Thanks a lot
Got it