As per the periodic table the mass of Be is 9, not 7 (4 protons, 5 neutrons). Be 7 is very unstable. Is there a reason why you chose an unstable isotope as your example instead of the stable element Be 9 ?
Nicely explained. Thanks! But don't we consider the mass of electrons in the calculation for mass of constituents? I think, this is missing. By considering this, mass defect will be slightly higher than that you have calculated. It's it?
Hi. Why are u dividing by 56. Is this not the binding energy of an Iron 56 nucleus. But u are saying it has 56 nuclei . I'm so confused right now. Where am I getting this wrong.
You divide by 56 to get the average per nucleon. The are a total of 56 particles in the nucleus of each atom, protons + neutrons. That is why it is calle iron-56, 26 protons and 30 neutrons.
You do not have to but the energy is usually given mega-electron volts (MeV) not Joules. You can a listing of all my videos from my website at www.stepbystepscience.com
Hey, great video thanks... I have a quick question, in the graph at the end, how come the average binding energy per nucleon generally increases as the number of nucleons in the nucleus increases? Aren't they still the same protons and neutrons?
David D29 because the average binding energy per nucleon relates to stability. Fe is the most stable known element, so for small nuclei the stability generally increases until reaching Fe after which (for large nuclei) the stability generally decreases... Although it's theorised that there is an island of stability further along the graph
So easy when someone explains it well! You should do videos about angular velocity and all that jazz
As per the periodic table the mass of Be is 9, not 7 (4 protons, 5 neutrons). Be 7 is very unstable. Is there a reason why you chose an unstable isotope as your example instead of the stable element Be 9 ?
As ever , brilliantly explained! Thanks
Glad you liked it and thanks for watching!
Great Video. You just Saved me for my Chem test tomorrow. TY SO MUCH (:
Hope the test goes well.
Great ways to explain!
🙂
Thanks so much 🤠
Nicely explained. Thanks! But don't we consider the mass of electrons in the calculation for mass of constituents? I think, this is missing. By considering this, mass defect will be slightly higher than that you have calculated. It's it?
You can either include the mass of the electron for all of the constituents or leave if off. Either way works.
i have a test tom and u helped me from failing ty so much
Great hope the test goes or went well. Thanks for the comment.
How about the sign ? It should be negative of mass defect?
is 1.007 825 and 1.008 665 a constant for mass of protons and neutrons?
yes
You saved me for my Physics Exam Today.
where are you know how succesful?
Very good, very clear. Thanks.
Glad to hear it. You are welcome!
Hi.
Why are u dividing by 56.
Is this not the binding energy of an Iron 56 nucleus. But u are saying it has 56 nuclei .
I'm so confused right now. Where am I getting this wrong.
You divide by 56 to get the average per nucleon. The are a total of 56 particles in the nucleus of each atom, protons + neutrons. That is why it is calle iron-56, 26 protons and 30 neutrons.
dividing 56 is to find binding energy for each nucleon which is "Binding fraction".
I tried this for Cu 63 my answer came out in negative sir, please help.
Thank you very much❤️💯.
Very nice of you to say.
When the nucleus is put together, where does that energy get released , inside the nucleus or outside it ?
of course outside.
Do you always have to convert to electron volts. Great video
You do not have to but the energy is usually given mega-electron volts (MeV) not Joules. You can a listing of all my videos from my website at www.stepbystepscience.com
Does anyone know if MCAT gives the mentioned conversion factors in the exam?
Hey, great video thanks... I have a quick question, in the graph at the end, how come the average binding energy per nucleon generally increases as the number of nucleons in the nucleus increases? Aren't they still the same protons and neutrons?
David D29 because the average binding energy per nucleon relates to stability. Fe is the most stable known element, so for small nuclei the stability generally increases until reaching Fe after which (for large nuclei) the stability generally decreases... Although it's theorised that there is an island of stability further along the graph
thx
As atomic no. increases, stability increases so does the binding energy.
Thank you for this. Really helpful👍
So glad it was helpful!
What is the name of the book you are reading from?
Where am I reading from a book?
Why do you have amu as 1.007 825 u and not 1.00727647 u?
That is a very good question.
nice explaination.I loved it.
Thanks a lot. that's really helpful.
Thank you. You help me a lot.
This is great !!!
Thanks for letting me know that you think so.
Thank you ver much sir
Great video thanks!
You are very welcome, thanks for watching and commenting.
Please make the video on frame reference and all related stuff
1:45 am before test, getting desperate y’all
You got this!
u solved a circuit diagram question for me ....u remember?
Yes I do, I keep that problem and used it in my physics class, thanks.
Thanks broham
Any time!
Binding energy is always negative please crosscheck very well
Explain slowly pls
sir u r amazing...❤❤.... hope u remember me...i can't find ur email id 😭
of course....
sir can i have ur email id?
my email address is bhswarthout@gmail.com
Step-by-Step Science thank u soo much sir
Clutch asf
MEDICALLLL PHYSICSSSS
Koi smg nahi a raha.....
I'll take that as a compliment, thanks!