For those struggling with calculating the concentration for compound X; notice the ratio difference between 200mg/l and 250mg/l, the pattern is that for 1 mg, the peak area increases with 1000. Therefore its only a matter of multiplying peak area for compound X with 1mg/1000... The answer is as stated in the video: 207,757 mg/l
@@user-cj8zj8sc2g No,the peak area is 207757(p.area of compound X). u have every 1mg increases with1000 p.area,so how many mg in 207757p.area? So :207757x1/1000=207,757
This was very helpful to me. I have a question for you. I need to create a tool (either in R, Excel or python) to calculate and plot the critical peak pair (pair with the lowest resolution) for a given set of parameters. Firstly, what is "resolution" in this context? Also, can you point me to literature that would help me come up with this tool?
+Jebus Slaves try to adjust pH, or other columns. It could be many reasons. The chemicals react with the filling materials, or two components are not separated thoroughly, or it could be isomers, or try to adjust the gradient time of mobile phase.
In my case, I had also troubles in not staight baselines, and the reason was preassure, a strong hydrophobic compound in Reversed phase HPLC can be stuck at the begining of the column, one way to solve it is turning around the column. By doing this, they can be eluted easily.
Hi Sir, In your video, you stated that the peak area represents the amount of compound that has passed the detector. Does this statement apply to the chromatogram with mV as y-axis as well? Looking fwd to your reply. Thanks
Yes it does. In this example if was Arbitrary Units. As long as the concentration of the calibrant compound is not too high, so that Lambert Beer's Law is valid, it should work with such units as well
kindly help me, what is the exact formula to calculate syn:anti from hplc spetra? this video explanation not clear to me. from retention time, area, peak and concentration values, how to determine syn:anti of chiral compound?
Maybe the mobile phase absorbs some of the light from the detector, so it is set in a bad wavelenght; or the sample contains a wide mixture of compounds.
Hi sir, I catch you very nice but my question is to you is you said that higher peaks doesn't mean higher concentration .how? And if you recall in normal way as compound conc increase its give higher peaks.
For those struggling with calculating the concentration for compound X; notice the ratio difference between 200mg/l and 250mg/l, the pattern is that for 1 mg, the peak area increases with 1000. Therefore its only a matter of multiplying peak area for compound X with 1mg/1000... The answer is as stated in the video: 207,757 mg/l
So you divide by 1000 in order to get the concentration but the Peak area is = to 200,000? So how has the answer become 207,757?
@@user-cj8zj8sc2g No,the peak area is 207757(p.area of compound X).
u have every 1mg increases with1000 p.area,so how many mg in 207757p.area?
So :207757x1/1000=207,757
OMG I really love all of these videos 'cause it's helping me a lot for tuesday's final exam
Wow! Thank you. I wish you were my science teacher
By far the best video I’ve ever seen for explaining this in simple terms, I now get it, Thank you ❤
Excellent explanation! Thanks!
Yo dat peak area was THE SHIT, bro!
11/10 would analyze again.
2357y1113 what is mg/l ?
miligram per litre. a concentration unit.
THAT IS PPM YOU PEASANT
Your all videos are well explained. I really enjoyed. Keep it up and upload more
this saves my assignment >< thanks a lot
Loved the way of explanation....hats off...keep up the good work
Thank you for saving my grades at Uni
Good luck at uni
simplicity is the ultimate sophistication
Lovely.. most easiest explation. Thanks a lot
अति श्रेष्ठ व्याख्यान धन्यवाद
tqsm for this well explained video. it helps me a lot
Thanks for the video. 👌
Very good job sir ji
Thank you so much
super ji I am watching this series of video which is more informative than my book I am preparing for analytical engineering test using this video
Thank you for this video. It is helpful.
very well explanation. Thank you.
It was so helpful, thanks a lot:)))
Clearly explanation cheers
Thank you this is what I want
Thank you for the fantastic vid 👍🏽😎😎
Thank you for this!
this is good and informative video
amazing, thank you!
This was very helpful to me. I have a question for you. I need to create a tool (either in R, Excel or python) to calculate and plot the critical peak pair (pair with the lowest resolution) for a given set of parameters. Firstly, what is "resolution" in this context? Also, can you point me to literature that would help me come up with this tool?
Explanation is good
But it’s so irritating to watch video without voice
good...very well explained..
Thank you so much.
thank you very muchh
Nice elaboration.
So how do you calculate the concentration of the unknown sample?
Divide the area of unknown by area of known then multiply by the concentration of known. Hey presto!
Y=mx+b
Where do you get the retention times from?
as in the reference list of compounds and retention times
Superb!!
What does it mean if the baseline is not straight? Is it an error with sample prep, or an error with detector?
+Jebus Slaves try to adjust pH, or other columns. It could be many reasons. The chemicals react with the filling materials, or two components are not separated thoroughly, or it could be isomers, or try to adjust the gradient time of mobile phase.
In my case, I had also troubles in not staight baselines, and the reason was preassure, a strong hydrophobic compound in Reversed phase HPLC can be stuck at the begining of the column, one way to solve it is turning around the column. By doing this, they can be eluted easily.
LOVE U!!!
Love It .♥
well , super ,tq so much
I uploaded practical video on HPLC and HPTLC analysis using software OpenLab and Visioncats...
Great job
Very helpful
What else does the peak height indicate if it doesn't guarantee more concentration than any other below jit
Hi Sir,
In your video, you stated that the peak area represents the amount of compound that has passed the detector. Does this statement apply to the chromatogram with mV as y-axis as well? Looking fwd to your reply. Thanks
Yes it does. In this example if was Arbitrary Units. As long as the concentration of the calibrant compound is not too high, so that Lambert Beer's Law is valid, it should work with such units as well
Excellent
1:21 why all samples are named C1?
A bit late but it's because it's the same sample (Caffeine) but with an increasing concentration with the purpose of making the calibration curve.
really
amazing
thank you!!!
what does it mean that a column has been calibrated?
kindly help me,
what is the exact formula to calculate syn:anti from hplc spetra? this video explanation not clear to me. from retention time, area, peak and concentration values, how to determine syn:anti of chiral compound?
I think chiral compounds also have different R-time, maybe you can find the explaination from instrumenal analysis
Thanks but it will be great with voice
Can you please provide raw hplc data file so that , can learn to interpret them
Which phenomenon couldn explain the bad baseline?
Maybe the mobile phase absorbs some of the light from the detector, so it is set in a bad wavelenght; or the sample contains a wide mixture of compounds.
easy to understand
Thank's :)
does anyone have audio complications?
I did my master's degree in analytical chemistry but synthetic organic chemistry for PhD. how to determine syn:anti from hplc spetra?
Hi sir,
I catch you very nice but my question is to you is you said that higher peaks doesn't mean higher concentration .how?
And if you recall in normal way as compound conc increase its give higher peaks.
Geaaaaaaaaaaaaaaaaaat
I wish there was talking
Duke city
OK
White Matthew Clark Charles Thomas David
👍🏻
not even close to HPLC
I liked to watch more of your videos in other interesting technics
I did my master's degree in analytical chemistry but synthetic organic chemistry for PhD. how to determine syn:anti from hplc spetra?
chem chem so what is mg/l ? how is this concetration? is this ppm?? why the peek 277456 pf compound x is 277,456 mg/l ??