Python Program to Check Leap Year (Hindi) | Python Tutorial

In this video, learn Python Program to Check Leap Year (Hindi) | Python Tutorial. Find all the videos of the 100+ Python Programs Course in this playlist: • Python Program to Add ...
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[@learningcoder]

Mam here is an easy and alternative program to calculate this:
year = int(input("Enter year to check: "))
if (year%4==0) and (year%400==0) :
print("It is a leap year.")
elif (year%4==0) and (year%100!=0):
print("It is a leap year.")
else:
print("It is not a leap year.")

[@darkminds35]

🎉

[@BMWCLASSICS_]

so easy nice

[@indrajitkumar2795]

Here's an easy way to do this
year=int (input("Enter a year "))
temp=year//100
if temp%4==0:
print (year,"is a leap year")
else:
print (year,"is not leap year")

[@100msplays4]

This is also wrong. we need both 4 , 100 and 400 to check leap years.

[@nxtjourney1827]

​@@100msplays4why we need

[@nxtjourney1827]

​@@100msplays4why we need

[@100msplays4]

@@nxtjourney1827 cauz not every year divisible by 4 is not leap year, u can check online, i think 1900 is one of them

[@xyz-ub8qo]

Madam faltu me itne saare conditions lagaye. Agar / 4 == 0 karte. To hi condition satisfy ho jata

[@Yoursarveshrajput]

Yess brother 😂

[@rockmode404]

use year 1900 to check if you are right or wrong

[@rohaanali937]

​@@rockmode4041900%4 == 0 so isn't he right

[@Jaimatrabhumi]

​@@rockmode404satisfied ho jayega bhai (475)

[@Jaimatrabhumi]

​@@rockmode404satisfied ho jayega bhai (475)

[@GoogleAndroidSmart]

Success is the result of perfection,hard work, learning from failure,loyalty,and persistence ?

[@abhishektiwari2643]

Absolutely right 👍👍

[@factstime7582]

Mam it can be done with simple program than this. There is no need to write such conditions
[n=int(input("enter any year = "))
if n%4==0 :
print (n," is a leap year")
else:
print(n," is not a leap year ")]

[@100msplays4]

u dumb or wht not every year divisible by 4 is a leap year.

[@shikhasolankistartforeverl1336]

Greatest videos it very helpful for bigners

[@_devil_tm727]

ryght dedi😂

[@GoldTechOfficial498]

Thank you ma'am

[@subhashchandra9690]

Year = int(input("enter a year: ")
If (year % 400 == 0) and (year % 100 == 0):
print (year,"is a leap year")
elif (year % 4 == 0) and (year % 100 != 0):
print ( year,"is a leap year ")
else ( print ,"is not a leap year")

[@AayushSoni-17]

Year = int(input("Enter the Year about which you want to know wheather it's a leap year or not: "))
if Year%4 == 0:
print("The year give by you is a leap year")
else:
print("The year give by you is not a leap year")
is that true??

[@RishiRajxtrim]

6:15
No need to use "and (year % 100 == 0)" in line 3 of program code

[@Dutifly07]

print("" if (n:=int(input("Enter a year: "))) else "hi" ,f"{n} is leap year" if n%400==0 or n%4==0 and n%100 else f"{n} is not a leap year")

[@ALEX_Edts]

try this:
a=int(input("enter year"))
if(a%4==0 and (a%100!=0 or a%400==0)):
print("its a leap year")
else:
print("noooo")

[@Sathvikachava-hn9zf]

Import calendar
Print(calendar.isleap(2020))
O/p true

[@soumyanandan1567]

Here is an easy way to do this:
Year=int(input("Enter the year"))
if Year%4==0 and Year%100!=0 or Year%400==0:
print("It is a leap year")
else:
print("It is not a leap year")

[@Ihateanimalloverstheyareshit]

Bhai yeh leap year kya hota hai . Badi confusion hai . Python ka course kr rha hoon pr aadhe se zyada cheeze to h pta hi nahi kya hoti hai 😢

[@_HARSH9797]

wow omg nice video

[@kritikasharma8thb712]

2006 is not a leap year ma'am

[@vedbhensdadia]

Yess 2006 is not leap year, Code is right 👍

[@user-zz4wm2fc1l]

Corrected Code👇👇
year = int(input("Enter a year: "))
if (year % 400 == 0) and (year % 4 == 0) or (year % 100 == 0):
print(year,"is a leap year")

else:
print(year,"is not a leap year")

[@muhammadusama6633]

great video

[@velocxty2477]

Great explanation ma’am!👍

[@bikibharali5240]

x = int(input("Enter the year: "))
if x%400==0 or x%4==0:
print(f"The year {x} is a Leapyear")
else:
print(f"The year {x} is not a Leapyear")

[@ashifshaikh199]

year = int(input("enter a year:"))
if (year % 4 == 0):
print(year, "is a leap year")
else:
print(year, "is not a leap year")

[@yogeshverma5620]

Is it work

[@ashifshaikh199]

@@yogeshverma5620 yes you can check it

[@AbdullahKhan-xo6fy]

@@ashifshaikh199 i am confused why she divide year by 100 and 400.

[@ashifshaikh199]

i was also confused thats why i comment@@AbdullahKhan-xo6fy

[@sachinverma8628]

@@AbdullahKhan-xo6fy she did that to check if a century is leap year or not like 1600 year is leap year but 1500 not that's why the 400 and 100 condition enters the chat

[@satyanii7668]

It is nice video.

[@ravindarahirwar2343]

Good mem

[@GalaxyCookies76]

Even Dr. Angela failed to explain this concept the way you have, in a simple and easy way.

[@VANSHRAJOTIA]

a = int(input("Enter the year : "))
b = a%4
if(b==0):
print(a, "is a leap year")
else:
print(a, "is not a leap year")

[@sachinverma8628]

To bhai jo centuries 100 200 300 500.....1100,1300 1400, 1500 bhi leap year hi show hogi but ye to normal year h

[@VANSHRAJOTIA]

ooh bhai thanks yaar main ye centuries pe to dhyan hi nhi diya tha 😁😁😁@@sachinverma8628

[@bobbyrajgorai695]

@@sachinverma8628 these years were leap.....yes 0th year was leap.....so the 4th.....and so the 100, 200, 300,....were leap years every 00 i.e. a century is leap only, amazing hus:) .......-ve years are the years before the calender starter i.e. 2023 years ago from this year so it wont be affected by this that those whice were -ve multiple were leap year only......as when we divide any no. (-ve/+ve) with is factor it will always give remainder 0 which doesnt determive any sign ......hope you found this useful nigga:)

[@user-st4xy4fc5b]

Hello maim mera question ye hai k humare phone mein do tarah ki ip show hoti hai aik to phone ki settings mein aur dosri agar google pe my ip likh k search karein to, to kon c ip pe koi bhi attack perform ho sakta hai, phone ki settings wali ya jo google pe my ip likh k search kartay hein plz reply

[@samdavid4941]

Agar aap LAN me attack kar rahe ho to apni LAN ki IP use Karo (wlan0) , Jo ki jyadatar 193.168 se suru hoti hai. Lekin agar aap over internet use kar rahe ho to to public IP use karna

[@user-st4xy4fc5b]

Ok thank u

[@Hamadkmehsud]

its simple if num = int(input("Enter a year: "))
if num % 4 == 0:
print(num," is a Leap year")
else:
print(num, " is not Leap year")

[@sachinverma8628]

Then what about centuries like 1500 1300 1400....... From this program it will be also shown as leap year but these are normal year

[@darkminds35]

In this calculation 1000 is a leap year which is wrong bro
This code is not right😊

[@ihaveitinme638]

years=int(input("Enter Last Year till you want to see is that leap year or not:"))
for i in range(1999,years+1):
if i%400==0 and i%100==0:
print("Leap Year :",i)
if i%4==0 and i%100!=0:
print("Leap Year :",i)
# else:
# print("NOt Leap Year :",i)

[@simpleguy098]

Whats wrong in this method pls anybody explain
Year = int(input('enter a year: ') )
If(year % 4 == 0) :
print(year, "is a leap year) else:
print(year, " is not a leap year)

[@safariyakm]

It have two conditions
#1 The year must be perfectly divisible by 400
#2 The year must be divisible by 4 but not by 100
year=int(input("enter year:"))
If (year%400==0 or (year%4==0 and year%100 !=0)):
print(year," is a leap year ")
else:
print(year," is not a leap year")

[@heevanrazdan4769]

​@@safariyakmsir I have the same qst why this 400 and 100 thing? Can't we just go by checking if it's a multiple of 4 or not?

[@safariyakm]

@@heevanrazdan4769it's actually a calender thing.A year evenly divisible by 4 is a leap year, unless evenly divisible by 100, unless evenly divisible by 400. This keeps the Gregorian calendar accurate to within a day every 3236 years

[@rishiraj2548]

Respected Teacher,
Kindly have a look at the simplified program for leap year:
year = int(input("Enter a year number to check for being leap or non leap: "))
# handle invalid inputs like negative or zero year number, non-numeric strings input
status = "non leap"
if year%400 == 0:
status = "leap"
elif year%100 == 0:
status = "non leap"
elif year%4 == 0:
status = "leap"
print("The year",year, "is a",status,"year.")

[@prajwalatkar9398]

why we divided by 100 ?

[@RishiRajxtrim]

Out of 100 and 400, if the year number is divisible only by 100 and not by 400, it is not a leap year.
Examples: 1900, 2500, 2600, 2700 not leap.
2000, 2400, 2800 are leap.

[@prajwalatkar9398]

@@RishiRajxtrim thank you

[@RishiRajxtrim]

🙏💯

[@kanchanthakur08835]

Bhai error aa rhi hai

[@harshavardhana3067]

hey what kind of error are you facing??

[@alifff1111]

🎯🎯🎯🎯🔥😁😂😂🎯🎯

[@maniac3449]

Century wale? Century 100 years hoti hai, 1000 years ko millennium bolte hain