preach man, i am currently studying circuits and i literally cannot rely on my professor, he does weird stuff in the lecture, and here i am getting simplified ideas that are much easier to understand.
6:17 Question: Are we assuming from the start that the circuit would be connected to point A and to the point between R4 and R5 ? What happens if the circuit is assumed to be connected to other points such as point A and point B or point B and point C would we get different R equivalent for those circuits ? Thank you for your great videos.
Q: Why _R_1_ and _R2_ aren't in series, and _R_4_ and _R_5_ are neither? A: two components are in series if _(i)_ they both share just one (not two) common node; _(ii)_ that node that they're sharing is exclusive for them, that is, that their common node is not being shared with other components; (iii) therefore, the current through them is the same. Now, perhaps in the diagram of this video it is not shown clearly, but a wire is exiting from _(A)_, and another from the lowest node. Therefore, the pair _R_1_ and _R2_, and _R_4_ and _R_5_ aren't in series.
4:20 are R4 and R5 in series? I understand why Rb and R4 are in series and why Rc and R5 are in series, but i can not understand why R4 and R5 in series? Thank you so much
Thanks ,very detailed and easily explained.Now that I know the total current how do i find the individual currents in the circuit.Did this using kirrchoffs law when i first got into electronics some 50 years ago, this bridge circuit has always been difficult to work on -to many equations-.
4:20 are R4 and R5 in series? I understand why Rb and R4 are in series and why Rc and R5 are in series, but i can not understand why R4 and R5 in series? Thank you so much
@@MichelvanBiezen thank you for your reply! but why? I am a little bit confused about the current! I thought that r4 and r5 have the same current and that's why are in series..but you told me that are NOT. I don't understand how to think to find the right type of connection...What can I do? Thank you
I notice that by removing the top set of resistors we effectively eliminate the cross resistor R3. But I wonder what if we had removed the bottom set of resistors having different values from the top? We would still eliminate the cross resistor, but should have different values for the survivors. Could you do another video showing that using both methods we obtain the same result?
Sir, if I instead transformed the bottom side as the Y connection, is that still correct? I got exactly 6 as the answer though, I used fractions so I didn't round off any decimal
Thank you sir that was very helpful, I have a question, how do I calculate current in each resistor separately? If there is already a video explaining it can you reply with the link or name because I can't find it, thank you
is it the way i press my calculator...but its like am getting a different answer everytime i use the lower circuit instead....anyway..let me stay calm and try to figure it out...but i will be glad if am corrected instantly
We made a video in the playlist that shows you how to do it. Essentially you use Kirchhoff's rules and end up with 5 equations and 5 unknowns which is then solved with a matrix technique.
So, Rb = R1... Rc = R2... Ra = R3??? I'm asking because after you made the conversion, then re-drew the schematic below, it is important to know which resistors are in relation to the other side of the circuit where the other 2 resistors were NOT involved in the Delta-Wye Conversion. In other words, how did you determine that Rb is in Series w/R4 & Rc is in Series w/R5? If someone does NOT fully understand, then the calculation may be performed INcorrectly
This video shows how the resistors are converted: Electrical Engineering: Basic Laws (29 of 31) Delta to Y Conversion Derived R1=? as well as the 2 following that one.
Not sure I understand this reasoning about parallel and serial connection. To me, Rb, Rc, R4 and R5 are all in series. R4 and R5 share a single node, just as Rc does with R5. So where is the difference?
You are the Lord and Saviour of engineering students.
Thank you for your work, and please never stop.
preach man, i am currently studying circuits and i literally cannot rely on my professor, he does weird stuff in the lecture, and here i am getting simplified ideas that are much easier to understand.
@@DocHolidayKY99 Deserves a nobel prize
@@Lombard2023 the same goes to my professor, he gave me like 28 bonus marks out of 100 in the course xD
The Best Teacher I've ever seen!!!
6:17
Question: Are we assuming from the start that the circuit would be connected to point A and to the point between R4 and R5 ?
What happens if the circuit is assumed to be connected to other points such as point A and point B or point B and point C would we get different R equivalent for those circuits ?
Thank you for your great videos.
That circuit is known as a bridge circuit and is connected at the top and at the bottom.
Great, video easy to understand, better explanation, best knowledge 😍😍💦,, now I understand, thankyou much ✊
You are welcome.
Your are one of the best teachers on the internet
Thank you. We appreciate your comment. 🙂
The Almighty created to actually help us. May God continue to grant u more energy
Thank you. God bless you as well.
Incredible video! Absolute precision in Knowledge Transfer. I hope the entire community of Current and Future engineers learns of Michael Van Biezen
Thank you for your kind words. Glad you found our videos.
Thank you so much sir!
You really helped me through so many tough times through your brilliance in teaching. You make it so understandable!
Glad we are able to help. Thanks for writing.
Ended my months of problem in just minutes. Absolute king
Great! Glad you found our videos! 🙂
one of the ever best class i had ever seen
hats off u sir
Thank You You are best teacher in Internet i have ever seen💖
Thank you.
I am from Pakistan.Sir You are great.Your method of teaching is v.good.Thanks.God bless you
Welcome to the channel.
apart from that....your an amazing teacher...i THank God forYou ..more life...and the good things of life be your share
Thank you. Glad you found our videos. 🙂
Thank you so much, you are a seriously talented teacher
You're very welcome!
Thank you Sir, I have cleared my doubt after watching your video.
Glad to help. Yes, this is a great technique for delta - y conversion.
Thanks for posting this kind of video, this is great for engineering students
Thanks for the feedback.
Q: Why _R_1_ and _R2_ aren't in series, and _R_4_ and _R_5_ are neither?
A: two components are in series if _(i)_ they both share just one (not two) common node; _(ii)_ that node that they're sharing is exclusive for them, that is, that their common node is not being shared with other components; (iii) therefore, the current through them is the same. Now, perhaps in the diagram of this video it is not shown clearly, but a wire is exiting from _(A)_, and another from the lowest node. Therefore, the pair _R_1_ and _R2_, and _R_4_ and _R_5_ aren't in series.
thanks for correcting that, that had me confused
4:20 are R4 and R5 in series? I understand why Rb and R4 are in series and why Rc and R5 are in series, but i can not understand why R4 and R5 in series? Thank you so much
Great video master. I wish my professor would explain like you and with an American accent
Bless you, good sir. I love your explanation. THANK YOUUUUU!!
Thank you Michael Sir, You made my day!
You are great teacher for engineering students. Thank you sir
You're welcome, we need more engineers in our world.
Thank you for this, now I understand it better 🙏🏻
You are welcome.
My varsity lecturer suggested your classes.😮
Thank your lecturer. Glad you find these helpful. 😊
Thanks ,very detailed and easily explained.Now that I know the total current how do i find the individual currents in the circuit.Did this using kirrchoffs law when i first got into electronics some 50 years ago, this bridge circuit has always been difficult to work on -to many equations-.
I wish I've had seen your videos early
Thank u sir ❤
Glad you found them now. 🙂
Hi teacher, I have a question .
Is there any general relation of current or voltage between delta and it's corresponding Y circuit ?
They are equivalent in all respects of resistance, current and voltage.
For that, the below part its simple but can we still use the delta to y conversion
For the lower part, it is not necessary.
What an amazing instructor!
Thank you, sir, for doing this easy. I am from Bangladesh.
You are most welcome.
4:20 are R4 and R5 in series? I understand why Rb and R4 are in series and why Rc and R5 are in series, but i can not understand why R4 and R5 in series? Thank you so much
R4 and R5 are NOT in series
@@MichelvanBiezen thank you for your reply! but why? I am a little bit confused about the current! I thought that r4 and r5 have the same current and that's why are in series..but you told me that are NOT. I don't understand how to think to find the right type of connection...What can I do? Thank you
The current through R4 is not the same as the current through R5
I notice that by removing the top set of resistors we effectively eliminate the cross resistor R3. But I wonder what if we had removed the bottom set of resistors having different values from the top? We would still eliminate the cross resistor, but should have different values for the survivors. Could you do another video showing that using both methods we obtain the same result?
There is only one method (that I know of) to perform a delta to Y conversion. This is derived by using Kirchhoff's voltage loops and current nodes.
sir you are so wonderful thank you very much
Thank you. We are glad you like the videos.
Thank you sir ,you save my time
Very well explained.
Thank you.
Glad it was helpful!
Sir, if I instead transformed the bottom side as the Y connection, is that still correct? I got exactly 6 as the answer though, I used fractions so I didn't round off any decimal
Yes, you can do that as well and you will get the same answer.
@@MichelvanBiezen thank you sir! Your videos are so helpful.
Thank you sir that was very helpful, I have a question, how do I calculate current in each resistor separately? If there is already a video explaining it can you reply with the link or name because I can't find it, thank you
yes, we typically use Kirchhoff's rules. I remember doing such an example but can't remember where.
@@MichelvanBiezen I found the playlist, thank you for your effort and response
@@justanobody5202 may i also ask for the link? I am kinda troubled on how to solve it using Kirchoff's rules.
is it the way i press my calculator...but its like am getting a different answer everytime i use the lower circuit instead....anyway..let me stay calm and try to figure it out...but i will be glad if am corrected instantly
Depending on which calculator you use, the order of your operation is important. Try to calculate each part separately and see if that works.
Here in 2024😂.
Yes another year.
Education is timeless :)))
Lmaaaooooo
Legend 2024😂
great teacher!
thanks for making it that simple!!
thankyou sir this was so helpfull
Glad you found our videos. 🙂
If u were my lecturer I would have understood since the first week.
Sir,how can we find current in each branch of the circuit
We made a video in the playlist that shows you how to do it. Essentially you use Kirchhoff's rules and end up with 5 equations and 5 unknowns which is then solved with a matrix technique.
So, Rb = R1... Rc = R2... Ra = R3??? I'm asking because after you made the conversion, then re-drew the schematic below, it is important to know which resistors are in relation to the other side of the circuit where the other 2 resistors were NOT involved in the Delta-Wye Conversion. In other words, how did you determine that Rb is in Series w/R4 & Rc is in Series w/R5? If someone does NOT fully understand, then the calculation may be performed INcorrectly
This video shows how the resistors are converted: Electrical Engineering: Basic Laws (29 of 31) Delta to Y Conversion Derived R1=? as well as the 2 following that one.
Thanks for sending that... watched & understood
sir you are too good.thank you
why not R4 & R5 in series 🤔
It is not that straight forward with a delta circuit. See the playlist: ELECTRICAL ENGINEERING 2.1 DELTA TO Y CONVERSION DERIVED
Thank you very much, Sir.
Best e eng tutorials!
isn't R1 and R2 in series and also R4 and R5?
No they are not. If two resistors are in series, then there is only one path for the current through both resistors.
Okay, thank you for the response.
th-cam.com/video/qQYRc9UibKk/w-d-xo.html&lc=UgzeUjwU53pLgg7VOdJ4AaABAg
You are awesome brother KEEP IT UP
😍😍thanks for the vedio
Welcome!!
Not sure I understand this reasoning about parallel and serial connection. To me, Rb, Rc, R4 and R5 are all in series. R4 and R5 share a single node, just as Rc does with R5. So where is the difference?
With a delta connection you cannot use that logic. See this playlist: ELECTRICAL ENGINEERING 2.1 BASIC LAWS SUPPLEMENT
We changed the name of the playlist to: ELECTRICAL ENGINEERING 2.1 DELTA TO Y CONVERSION PROOFS
brilliant explanation thank you
You are welcome!
God bless you sir
Thank you! 😃
great teacher
Thank you! 😃
Thank you. Glad you found our videos. 🙂
can you use it with capacitors?
We are currently working on a playlist that will include capacitors and inductors in circuits. Some are already published (see chapter 8).
Just like how u drew the resistor symbol😊
Yes, I picked that up from one of my classes in college (a long time ago) and it stuck with me
if one need to communicate with you how do i get hold of you all you videos helped me so so much
We try to keep track of all the comments from the viewers
thank you mr.
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thank you micheal
Thank you so much!
I'm here in 2023, from Bangladesh.
Thanks sir. ❤
~Arjun.
Welcome to the channel!
Who’s here in 2018 ? 😃
2019
2020 Get to da choppa
2022
2022 🎉
2023
And R3?
This is amaxing
THANK YOU SO MUCH!!!!
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thank you sooo much!!
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Thank you sir
now I am understood..
Thanks!
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God bless you!!!!!!!!
Super nice
If you were a superhero, you'd be MR FANTASTIC
im confused
We have videos that show where the delta to y conversion came from and how to derive it.
Put a dot on that decimal Like you mean it! Haha
Thanks
amazing
ممكن ترجمه للعربي 😭😭
Awesome
2:67 "the product of those two vectors" hahahahaha
hero !
thank sir , very good explanation.
Thanks and welcome 🙂
Thank you sir
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Amazing
Thanks. Glad you liked it.