1:00 how tf are we looking at the pixel to the right hand side of the pixel whom we are comparing with? its 0x1 so 0 rows and one row above. so it should be the pixel directly over the head of the main test pixel right?
it represents a shift in (row,column), therefore 0,1 means we are comparing the current pixel (at each position x,y), with the pixel x+0, y+1, therefore it would be the pixel on the right hand side for the person that it is looking at the matrix.
i also had that doubt then i figured it out, in digital image processing the matrix representation starts from top left corner and is not like a conventional graph axes, i.e., in the given figure (0,5) would be 0 according to traditional graph but using the image processing it would be (0,0) hence you have to take top left corner as (0,0) basically tilt your head right and then use the traditional graph method.
Thank you the very clear illustration!
Great explanation. Thanks!
so, this is fundamental of texture descriptors introduction. thanks sir
1:00 how tf are we looking at the pixel to the right hand side of the pixel whom we are comparing with? its 0x1 so 0 rows and one row above. so it should be the pixel directly over the head of the main test pixel right?
it represents a shift in (row,column), therefore 0,1 means we are comparing the current pixel (at each position x,y), with the pixel x+0, y+1, therefore it would be the pixel on the right hand side for the person that it is looking at the matrix.
i also had that doubt then i figured it out, in digital image processing the matrix representation starts from top left corner and is not like a conventional graph axes, i.e., in the given figure (0,5) would be 0 according to traditional graph but using the image processing it would be (0,0) hence you have to take top left corner as (0,0) basically tilt your head right and then use the traditional graph method.
Luke Smith?
At 5:37 how did you normalise the GLCM matrix?
I got it. divide each element by sum of all elements. i.e., (2+2+1+4+5+2+4 =20)
thx ! good video !
thank u sir very helpful
sir can you share the code?