A Nice Algebra Problem | Math Olympiad | How to solve for x ?

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  • เผยแพร่เมื่อ 6 ก.พ. 2025
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    Find the value of x?
    How to solve √x√4 + √x√8 = √x√16
    In this video, we'll show you How to Solve Math Olympiad Question A Nice Algebra Problem √x√4 + √x√8 = √x√16 in a clear , fast and easy way. Whether you are a student learning basics or a professtional looking to improve your skills, this video is for you. By the end of this video, you'll have a solid understanding of how to solve math olympiad exponential equations and be able to apply these skills to a variety of problems.
    #matholympiad #maths #math #algebra

ความคิดเห็น • 9

  • @فیروزاهنگری
    @فیروزاهنگری 12 วันที่ผ่านมา +1

    (16/4)^1/(√x)+(16/2)^1/(√x)-16^1/(√x) =0
    16^1/√x•4^(-1/√x)+16^1/√x•2^(-1/√x)-16^1/√x=0 because 16^1/√x>0
    the two parties simple on 16^1/√x
    2^2(-1/√x)+2^(-1/√x)-1=0
    2^(_1/√x)=(-1+-√5)/2
    1/[2^(1/√x)]=(-1+-√5)/2
    2^1/√x=2/(-1+-√5)
    0

    • @SALogics
      @SALogics  12 วันที่ผ่านมา +1

      Very nice! ❤

  • @gauravkanwar2800
    @gauravkanwar2800 12 วันที่ผ่านมา

    do these questions change your life or are used anywhere in your life to earn money ?

  • @igorsidorin3585
    @igorsidorin3585 13 วันที่ผ่านมา +1

    Sorry. but sqrtX=X in 1\2!!! U wrote 1/x... Mistake

    • @SALogics
      @SALogics  12 วันที่ผ่านมา +1

      Yes, Thanks for pointing this out! ❤

  • @prollysine
    @prollysine 12 วันที่ผ่านมา +1

    ..... , ..... , u=(V2)^(Vx/2) , u^2-u-1=0 , real u=(1+V5)/2 , Vx=(2*ln((1+V5)/2))/ln2 , x=~ 1.92789 ,
    test x=~ 1.92789 , (V4)^Vx+ (V8)^Vx=~ 6.8541 , (V16)^Vx=~ 6.8541 , same , OK , solu , x=~ 1.92789 ,

    • @SALogics
      @SALogics  12 วันที่ผ่านมา +2

      Very nice! ❤

    • @prollysine
      @prollysine 12 วันที่ผ่านมา

      @@SALogics Thanks!