I have taken classes long time a ago in the US, my instructor never explained it this easy. Please keep up creating more of these such helpful lectures. Thanks
Dear sir @5:28 in free vibrations you applied d alemberts principle for that, why dont we apply that here ? shouldn't we consider acceleration here ? how to know when to consider and not to consider acceleration clarify sir plzz
Sir, In newtons method, you have stretched at some distance x , so you told the force act on the mass by spring is -kx. But, In energy approach, you virtually stretched some infinitesimally small distance ∆r , it could be, the force by spring, -k ∆r. How it could -kx. This is my doubt, i don't know, it may be a totally wrong question....
Hello and sorry for replying late, When we are doing energy approach, we actually disturbing our system from its equilibrium state, means at this moment, the spring is stretched. So if you give del_r displacement actually the spring is now having a total change in length is (x+del_r), but as del_r is infinitesimal small so we assume the spring force still kx and then we say the work done by spring force is k.x.del_r. if still I could not answer your query, let me know I will try to explain it in other way.
You are just awesome , the way u explained everything , I am loving it : )
very good woodwork in explaining the fundamentals. Thank you!!
thank you!! very helpful and easy to understand!!
I have taken classes long time a ago in the US, my instructor never explained it this easy.
Please keep up creating more of these such helpful lectures. Thanks
how are you doing now ?
how are you doing now ?
amazing teacher
These lectures hit different when you know sir teaches in the same university in which you study
Which university
@@akangkshyadutta5820 Thapar
Dear sir
@5:28 in free vibrations you applied d alemberts principle for that, why dont we apply that here ?
shouldn't we consider acceleration here ?
how to know when to consider and not to consider acceleration
clarify sir plzz
Excellent lecture. The next one too.
Thank you
Excellent 👌
Complete lecture serie of mechanics for your refernce th-cam.com/play/PLi0hoi2vOpnQ1wu7w4CMSUobzKuWIEThQ.html
That is an awesome exolaination
Great guru GGG
🙂🙂
Complete lecture serie of mechanics for your refernce th-cam.com/play/PLi0hoi2vOpnQ1wu7w4CMSUobzKuWIEThQ.html
where I can know what is K?
Wow sir..
thank you
Thank you 🇩🇿❤️
what happened to your finger sir?
Dear @samuel Isaac, thank you for your concern, it was just a cut, now perfectly fine. Thank you again
thank you sir
great video
Complete lecture serie of mechanics for your refernce th-cam.com/play/PLi0hoi2vOpnQ1wu7w4CMSUobzKuWIEThQ.html
Sir aap farishta ho thapar students ke liye
You are so kind Aastha..thank you for appreciation
well explained
Thanks
Complete lecture serie of mechanics for your refernce th-cam.com/play/PLi0hoi2vOpnQ1wu7w4CMSUobzKuWIEThQ.html
Very nice
Thank you
Sir civil 1 St year sa hai hm ..physics yaha pr kaha sa start kra
Dear ye subject to mechanisc hai for engineering 1st year. Aap civil engineering 1st yr ho. Physics ka stllabus bilkul alag hai
Sir pls provide link jaha sa hm video dekh saka civil engineering ka
Complete lecture serie of mechanics for your refernce th-cam.com/play/PLi0hoi2vOpnQ1wu7w4CMSUobzKuWIEThQ.html
Thanks
Complete lecture serie of mechanics for your refernce th-cam.com/play/PLi0hoi2vOpnQ1wu7w4CMSUobzKuWIEThQ.html
Bhaiya mechanics ka exam hai maine padha hai hai aapke channel se lekim time bht kmm tha isiliye ache se nhi padh paya thora help krr do exam me plzz
In what way need my help
felt bad for your finger ,sir
❤️❤️❤️❤️
Sir, In newtons method, you have stretched at some distance x , so you told the force act on the mass by spring is -kx.
But,
In energy approach, you virtually stretched some infinitesimally small distance ∆r , it could be, the force by spring, -k ∆r.
How it could -kx.
This is my doubt, i don't know, it may be a totally wrong question....
Hello and sorry for replying late, When we are doing energy approach, we actually disturbing our system from its equilibrium state, means at this moment, the spring is stretched. So if you give del_r displacement actually the spring is now having a total change in length is (x+del_r), but as del_r is infinitesimal small so we assume the spring force still kx and then we say the work done by spring force is k.x.del_r. if still I could not answer your query, let me know I will try to explain it in other way.
@@ashishpurohit9138 no need for that sir, this is enough, i understood and thank you very much sir to consider the doubt.
Complete lecture serie of mechanics for your refernce th-cam.com/play/PLi0hoi2vOpnQ1wu7w4CMSUobzKuWIEThQ.html
Thank you sir