did you drop the 1/N in the very beginning toward the end? if I'm not mistaken, the fourier coefficient formula is divided by the period of the signal.
Other plots I have seen related to the DFT and FFT express a series of magnitudes in the frequency domain. How come we didn't achieve that here / what is needed to get to that stage?
dude im ngl I have no idea what u did after 10 minutes but ur other vids have been super helpful
You are a life saver btw, love your videos, simple and easy to understand
Yes, you are correct; the k got dropped. I will add an annotation to correct it. Thanks for pointing this out.
did you drop the 1/N in the very beginning toward the end? if I'm not mistaken, the fourier coefficient formula is divided by the period of the signal.
The 1/N does appear to have gone missing; thanks for pointing this out. I will add an annotation to fix it.
I'm glad I found this video. Thanks!
At 11.23 Ck should be 2 cos k(2*pi)/N ((Exponential power of -jK(2*pi)/N)-(Exponential power of -jK4(2*pi)/N)).
Other plots I have seen related to the DFT and FFT express a series of magnitudes in the frequency domain. How come we didn't achieve that here / what is needed to get to that stage?
Sir could u solve this problem???
X(k)=cos(K*pi/4)+sin(3K*pi/4). where X(K) is Fourier coefficients,
find x(n) timing signal..
Where did the 1/N go after you did all that computation?
It took a stroll...
I checked the phase plot again, and it is correct. It should be [0, -pi/4, 0, pi/4, 0, -pi/4, 0, pi/4]
shouldn't it be cos((k.2pi)/N) at 08:41 ?
my question is that when you take the euler formula how come there is a constant 2 in front of the cos()
cos(x) = (1/2) * [ (e^jx) + (e^-jx) ], so (e^jx) + (e^-jx) = 2cos(x)
I would really appreciate if you would rather show how to find the X[n] if C[k] is given.
I'm not understanding how he was factoring. Can someone explain it to me?
Abby Estabillo e^(2)=e^(1+1)=e^(1)e^(1)
Factoring is really ugly..Why cant we leave this without factoring?
this is wrong
e^0=1
what is he doing?
He's factoring out an exponential so he can have a form that becomes cosine, since cos(x) = (1/2) * [ (e^jx) + (e^-jx) ]
i think i under stand some thing
amarjeet advocate delhi high court new delhi india
Why so slow?? 😴