But now they are doing photon upconversion. Compton effect in reverse. It is done in something like cesium atoms... they kick an electron up a level, then there is a short ammount of time they get to do it again before it decays. Then it relaxes 2 levels giving a higher frequency.
Take aways:- 1) Compton shift in wavelength:- ∆(lambda) = h/m·c (1-cos∅) 2) kinetic energy of recoil electron:- E(kinetic)= hc/(lambda) 3) direction of the Recoil electron:- Tan∅= (lambda) sin∅/ (lambda)' - (lambda)cos∅ 4) Compton wavelength of electron:- h/m·c =0.24Å
0:30 It changes the photons direction and frequency: is this correct? Shouldn't we say the collision generates another photon with different direction and frequency?
Ye correct. No, collision of photon and electron can not generate another photon of different frequency in any process. Photons are produced during the de excitation of atoms or the collision between matter and antimatter and in some cases from vacuum.
When a photon interact with elecron, new photon can be generated, but in this case electron is not ejected from the atom. The incident photon excite the electron to higher energy state, electron oscillate, as a result the oscillating electron which is an accelerated charge, come to its ground state new photon of same frequency and wavelength is produced. This process occurs during reflection of light from a plane mirror or a polished smooth surface.
@@Janvisualphysics So your point is that when the Electron only jumps to a higher energy state/orbit, we say it is the same photon. But how do know it is the same photon and not a 2 step process: electron absorbs the photon, jumps to a higher state and ejects another photon with the 'left over' energy from the jump? In the inverse process, where the electron falls back to a lower energy state, we say it will eject a 'new' photon. Why would it not eject a new photon when it jumps to a higher state? Note: a quick check on the wikipedia page: their they make a difference between the "incident photon" and the "scattered photon", implying it are 2 different photons. I am confused by your comment on reflection. How is this related to compton shattering?
Reflection is not related to Compton effect. It is a process in which new photon is generated. You are thinking the generation of new photon in Compton effect, which have no experimental evidence. Instead you can imagine the photon as a packet of energy, during the interaction the packet share some of its energy with electron and scatter with the left over energy
Then electron in the target material would just oscillate in the host atom and incident radiation would scatter off the target. But actually we observe electron nocked out by the incident photon.
@@Janvisualphysics So you mean that incident radiation frequency would be same as the frequency of the scattered radiation IF light had behaved as wave ? BUT in reality the observed frequency is different HENCE we know it is particle ?
Short and very clear. Great work, thanks!
Thanks for appreciation
Thanks for appreciation
Straight outta Compton effect.
Parental Advisor required
not that easy😂😂
WE'RE SCATTERING WITH THIS ONE🔥🔥🔥🔥
Imagining a crip walkin photon
Word! ✊
Nice explanation man 🙂
Good job, thank you.
Thanks for appreciation
But now they are doing photon upconversion. Compton effect in reverse. It is done in something like cesium atoms... they kick an electron up a level, then there is a short ammount of time they get to do it again before it decays. Then it relaxes 2 levels giving a higher frequency.
Thank you
Keep it up the good work
Great 👍
Take aways:-
1) Compton shift in wavelength:-
∆(lambda) = h/m·c (1-cos∅)
2) kinetic energy of recoil electron:-
E(kinetic)= hc/(lambda)
3) direction of the Recoil electron:-
Tan∅= (lambda) sin∅/ (lambda)' - (lambda)cos∅
4) Compton wavelength of electron:-
h/m·c =0.24Å
0:30 It changes the photons direction and frequency: is this correct? Shouldn't we say the collision generates another photon with different direction and frequency?
Ye correct.
No, collision of photon and electron can not generate another photon of different frequency in any process. Photons are produced during the de excitation of atoms or the collision between matter and antimatter and in some cases from vacuum.
@@Janvisualphysics is that a by definition statement, or do we have 'proof' it is the same photon (or how do we proof it is the same one).
When a photon interact with elecron, new photon can be generated, but in this case electron is not ejected from the atom. The incident photon excite the electron to higher energy state, electron oscillate, as a result the oscillating electron which is an accelerated charge, come to its ground state new photon of same frequency and wavelength is produced. This process occurs during reflection of light from a plane mirror or a polished smooth surface.
@@Janvisualphysics So your point is that when the Electron only jumps to a higher energy state/orbit, we say it is the same photon. But how do know it is the same photon and not a 2 step process: electron absorbs the photon, jumps to a higher state and ejects another photon with the 'left over' energy from the jump?
In the inverse process, where the electron falls back to a lower energy state, we say it will eject a 'new' photon. Why would it not eject a new photon when it jumps to a higher state?
Note: a quick check on the wikipedia page: their they make a difference between the "incident photon" and the "scattered photon", implying it are 2 different photons.
I am confused by your comment on reflection. How is this related to compton shattering?
Reflection is not related to Compton effect. It is a process in which new photon is generated. You are thinking the generation of new photon in Compton effect, which have no experimental evidence. Instead you can imagine the photon as a packet of energy, during the interaction the packet share some of its energy with electron and scatter with the left over energy
What would have happened to momentum/energy of photon after collision if it behaved like a wave NOT packet of energy particle?
Then electron in the target material would just oscillate in the host atom and incident radiation would scatter off the target. But actually we observe electron nocked out by the incident photon.
@@Janvisualphysics So you mean that incident radiation frequency would be same as the frequency of the scattered radiation IF light had behaved as wave ? BUT in reality the observed frequency is different HENCE we know it is particle ?
Yes this is reality. The Compton shift formula shows this.
Brilliant
India wale like karo ❤❤❤
Sir self inductance and mutual inductance ki link send ker dain plzz
th-cam.com/video/QVOLMptF9Ts/w-d-xo.html
th-cam.com/video/3XgWDBO2Lnc/w-d-xo.html
Thank uu sir
That's awesome man🪽
adam ptk
😢
That’s right cpt
we all love vicidior
😅😅😅well information good show you can 😅😅😅
it is very cool bruh
i love physics
محمود الصالح
Subbed
In which language ?
@@Janvisualphysics Glischen
طالب عراقي مر من هنا
الاستاذ ميشرح زين و چماله اني طاب الكتروني و يم استاذ كلش معروف بس شنسوي خرط الماده كلها ب شهر 5