I’m currently an electrical engineering student, and it has come to my attention that students have trouble grasping the concept of Kirchhoff’s Voltage Law in many of the introductory courses. My colleagues and I set out to help these student by offering a technical description of the process to coincide with the course material. We discovered it was much easier to grasp this concept with analogies, as you did. We then provided a strategy for solving these problems by analyzing the circuit, choosing a loop, and finally applying Kirchhoff’s Law to solve for unknown variables. We hope this technical description will benefit struggling students.
Also why would be there a potential drop across second capacitor, since the larger capacitor will store all the charge. unless the dielectric potential breaks.could you through some light
We know that voltage drives the current around but at the end point of the source before entering is zero so does it mean no current there or current is in motion and only voltage drop?
Thank you. I do have a question. How is voltage (potential difference) stored in the moving electrons? What I mean by this is when a current of electrons goes through a battery, how does the voltage give them power to carry out their functions, (ex. light bulbs)? Should I think of it as like Amplitude in waves? because the current is same all through the circuit. I just want to know how energy is delivered from the battery to the resistor?
So battery is a elastic rubber band holding charge on it and it releases charge around circuit, when a load comes it lose energy just like friction cause to lose energy of body which causes to lose energy of charge. But how it regain it energy from battery?
Thank you for helping me all the time, I use your videos a lot - you explanation is perfect! I had one question about Kirchoff's Rule, what happens if those 'loop' that we are working on has capacitor or Inductor? how does the equation change? Thank you very much~!
+amrita kumari Think of it this way... suppose they ask you to sum 3 and negative 4. How would you write that? Even though they are asking you to add them, you would write them as 3 - 4 because of the negative sign that 4 has. It is the same thing here. When you sum up the voltages it is like adding with negative numbers because when you go through the resistors in the direction of the current there is a voltage drop or loss of potential energy. Therefore the voltage across that resistor is expressed with a negative. 9V + (-6V) + (-3V) = 9V - 6V - 3V = 0. Hope that helps.
You have probably made me pass the physics course, thanks a lot and I wish all the good things happen in your life !
I’m currently an electrical engineering student, and it has come to my attention that students have trouble grasping the concept of Kirchhoff’s Voltage Law in many of the introductory courses. My colleagues and I set out to help these student by offering a technical description of the process to coincide with the course material. We discovered it was much easier to grasp this concept with analogies, as you did. We then provided a strategy for solving these problems by analyzing the circuit, choosing a loop, and finally applying Kirchhoff’s Law to solve for unknown variables. We hope this technical description will benefit struggling students.
Thank you so much Mr. Andersen , you are the best.
Physics bless us all
Truly amazing channel you have Paul. Leaving small pauses after conclusions would help to realize and remember before the next part.
Thanks for sharing your videos. They are wonderful and easy to understand. The best videos about electrical ever seen.
you are the definition of a blessing my friend
Excellent description, very simple to grasp.
Thank you a lot! I struggle with physics and this made me understand better about Kirchhoff's law.
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lol.. get over yourself.
thank you, I was so lost when we went over this in class. I'm grateful for this, I just needed a different look at it I guess.
Wonderfully explained, thank you so much.
This analogy is phenomenal
Thank you for the Presentation !!! Very helpful
Really helped me a lot. Thanks for doing this video
Thanks, u explained so smoothly
great educators are great communicators.
Fantastic explanation, thank you.
Wow very very helpful. Especially for 10 class students
YOU ARE AWESOME!! Thanks so much for uploading this video🤗
you are the best!!! this is the easiest exanation I have ever heard. thank you thank you so much!!!!!
Amazing video.........extremely helpful
Really helped me a lot, Thanks
Also why would be there a potential drop across second capacitor, since the larger capacitor will store all the charge. unless the dielectric potential breaks.could you through some light
what is the software you have used?? please give me the download link
+Rabby Moni phet.colorado.edu
Thank you ,sir. you are a great help.neither my tutor nor my college was this much of a help.
first time watching n the best explanation that I have heard,I'm just a beginner hungry for knowledge..
thank you Paul
What's that program he used to simulate a circuit? Does anyone know other application like that? Thanks for the help :)
+Himanshu Sharma
Thank you 👍
Really helpful, Thanks.
It's a wonderful video..... for the good learners...
you are AMAZIING. thnk you
that was awesome. very very helpful. I thank you so much!
We know that voltage drives the current around but at the end point of the source before entering is zero so does it mean no current there or current is in motion and only voltage drop?
it's very clear thank you , please took about thevenin theorem and superposition because i don understand it and i'll be thankful ❤
Thank you.
I do have a question.
How is voltage (potential difference) stored in the moving electrons? What I mean by this is when a current of electrons goes through a battery, how does the voltage give them power to carry out their functions, (ex. light bulbs)? Should I think of it as like Amplitude in waves? because the current is same all through the circuit. I just want to know how energy is delivered from the battery to the resistor?
Can you please share whoch software you are using where you measure with the multimeter? Or is it just graphics?
So battery is a elastic rubber band holding charge on it and it releases charge around circuit, when a load comes it lose energy just like friction cause to lose energy of body which causes to lose energy of charge. But how it regain it energy from battery?
Thank you for helping me all the time, I use your videos a lot - you explanation is perfect!
I had one question about Kirchoff's Rule,
what happens if those 'loop' that we are working on has capacitor or Inductor?
how does the equation change?
Thank you very much~!
very educative. thank you. regards.
yeah...good one very help full
What software are you using to simulate the circuit?
yes I am asking for this too. I wish someone knows
Philip Kirkbride 7
thank you sir!
would be nice if you explained how its .6 and 6v and 3v.
assume i know nothing. i just missed out on valuable info
Is there also a video for the rule in parallel circuits?
Can you take a look at my video...am not sure if its series or parallel or both.
salaz SVG that's parralel
James Grigg thank you...how did you know.Can you briefly explain.
A switch is series will cause all the lights to turn on/off at once
I looped the common at the 2 gang switch.
Great Video.Which software were you using?
Wouldn't the 9V be shared between the other circuit?
very hard 2 make this easier 2 understand. thx!
Which circuit software are you using?
sir you are awesome thank you
What type of software do you use for the circuit simulations?
THANK U SO MUCH
That works great as long as there isn't a changing magnetic field going through the loop ;)
thank you man, finally got it👍
Nice , i am from India (Delhi )
I have a doubt
You said that the sum of the voltage is zero then why did you subract them
+amrita kumari Subtraction is the same thing as addition of a negative value. Losing potential (i.e. across a light bulb) is a negative value.
+amrita kumari Think of it this way... suppose they ask you to sum 3 and negative 4. How would you write that? Even though they are asking you to add them, you would write them as 3 - 4 because of the negative sign that 4 has. It is the same thing here. When you sum up the voltages it is like adding with negative numbers because when you go through the resistors in the direction of the current there is a voltage drop or loss of potential energy. Therefore the voltage across that resistor is expressed with a negative. 9V + (-6V) + (-3V) = 9V - 6V - 3V = 0. Hope that helps.
Now i can actually pass my class
كيف تحقق قانون كيرتشوف عمليا؟
helpful , thanks a lot
How did he get the 6?
Thank you!
bigger caps means more charge storage, so why is the potential drop less? could you please explain the inverse property.
Thanks!
why it is happening
same
so helpful
'I' in the circuit is 9/15A but not 6A.please acknowledge.
thx for the vid just a minor complaint "MR"?
Kirchoff was a bastard 😂😂😂
you're awesome :D
great !
CLASSIC!!!!!!
Nice. Subscribed :)
Good man!
thnxs good
Praaaaaaaaaa...
Look up Lewin's response to this. You will realize that this is actually false. They do not = 0 after all!
Paada
what's the point of showing your face if no one is paying attention to your face. You get me unhard
THANK YOU!
Thank you!