Japanese Math Olympiad Problem A Nice Math Problem Comparison
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- เผยแพร่เมื่อ 5 ก.ย. 2024
- Japanese Math Olympiad Problem A Nice Math Problem Comparison
math olympiad
olympiad math
Math olympiad question
Math olympiad questions
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algebra olympiad problems
math tricks
how to improve maths
how to solve any math problem
In this video, we'll show you How to Solve Math Olympiad Question in a clear , fast and easy way. Whether you are a student learning basics or a professtional looking to improve your skills, this video is for you. By the end of this video, you'll have a solid understanding of how to solve math olympiad equations and be able to apply these skills to a variety of problems.
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"888^111 is greater OR EQUAL to 9^111" ?
why not just ">"?
That's too complicated isn't it.
222^333 = 222^3 ^ 111
333^222 = 333^2 ^ 111
222^3 > 333^2 obviously
or 111^3 * 2^3 (8) > 111^2 * 3^2 (9) obviously
every one has different way of solving a problem...that's the beauty of Maths.
💯💯💯💯
222^333333^222
222^3333^2
a=log_222(333)
222^3222^(a2)
3a2
3/2a
3/2log_222(333)
3/2log_222(222)+log_222(3/2)
Since:
1/2>log_222(3/2)
so:
222^333>333^222
nice approach
yawn already anseered forever. Please see black pen red pen for details on any a^b vs b^a as the base closest to e is the winner. We can know this for a fact without have to do much thinking based on the proof provided.