How to Balance C6H6 + O2 = CO2 + H2O (Combustion of Benzene)

In order to balance the combustion reaction C6H6 + O2 = CO2 + H2O you'll need to watch out for two things. Visit www.Breslyn.org for video guides on balancing equations and more!
First, be sure to count all of C, H, and O atoms on each side of the chemical equation. Once you know how many of each type of atom you have you can only change the coefficients (the numbers in front of atoms or compounds) in order to balance the equation.
Be careful when counting the Oxygen atoms on the product side of the equation. Don't forget the O in H2O!
Drawing/writing done in InkScape. Screen capture done with Camtasia Studio 4.0. Done on a Microsoft Dell Dimension computer.

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Thank you so much I am in Chemistry class right now and I didn’t understand the teacher but after watching a few of your videos I actually understand how to balance thank you again

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[@wbreslyn]

You are most welcome! --- Dr. B

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[@wbreslyn]

Thanks for the kind words!

[@asmaahmed316]

Why you divided by 2 when you multiply by 15?

[@Fictional_Bubble007]

Sir what if we put 7.5 after balancing before o2 then ? Please answer

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[@wbreslyn]

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[@wbreslyn]

Glad you like them! --- Dr. B

[@friendFriend-px9lt]

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[@erbio7984]

You have to multiply all the coefficients by 2 after the fraction step, you can’t leave the fraction there.

[@ajdl3255]

Erbio Yes, in fact you can, because, you can use mol instead of molecules

[@idonthaveaname847]

@@funshoakeredolu2655 idk our teacher told us if there are two atoms for example O2 you can keep the fraction

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He did that

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[@wbreslyn]

You're welcome 😊

[@user-gj2tk6om9x]

May i know how do get 15 in the reactants and also how you get that 2×15 ÷2

[@user-gj2tk6om9x]

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[@wbreslyn]

Shakra! --- Dr. B

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Hey please help me to solve this redox
V+H2O GIVES H4V6O17+H2 HOW TO SOLVE THIS REDOX

[@wbreslyn]

This might be a place to start although I've not checked their work:
answers.yahoo.com/question/index?qid=20090526180720AAWM2oE
This is pretty awesome too!
www.periodni.com/balancing_redox_equations.php
--- Dr. B

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[@wbreslyn]

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[@wbreslyn]

Glad I could help with C6H6! --- Dr. B

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[@wbreslyn]

Thanks!

[@swarnanilbera6738]

Which type of reaction is this??

[@wbreslyn]

You have a hydrocarbon combining with oxygen and end up with carbon dioxide and water. That's the general format for combustion reactions. --- Dr. B

[@harshidasandesara8763]

Thank you so much for video

[@wbreslyn]

Most welcome!

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Tysm it helped me a lot sir

[@wbreslyn]

Ywsm! --- Dr. B

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[@wbreslyn]

Excellent!

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[@wbreslyn]

No problem 😊

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I didn't expect anyone to make a video on this one.......

[@wbreslyn]

It is oddly specific...

[@nuzhatshakeel2775]

Thank you 😊

[@wbreslyn]

You're welcome 😊

[@aar0n222]

can you help with C6H6 + HNO3 C6H5NO2 + H2O please

[@wbreslyn]

For this equation, the challenge is correctly counting the atoms on each side. You should have 7 Hydrogen atoms on both sides. On the product side of the equation (the left) you should have 3 Oxygen atoms. See if that helps...
--- Dr. B

[@niko6931]

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[@tegyla1274]

The answer is 2C6H6 + 15O2 -> 12CO2 + 6H2O
The video is unnecessary complicating and confusing.

[@wbreslyn]

Yes, that would the be whole number ratio for C6H6 + O2 = CO2 + H2O. Often teachers will have you multiple the coefficients to get whole numbers. I'm not sure why I didn't do that in this video. Either way is correct from a stoichometric standpoint.--- Dr. B

[@victorhalskov1660]

@@wbreslyn I've legit never seen any example of using "half" coefficients. Is this ever correct, and is it even possible in a practical scale, like you can't have half molecules, can you?

[@mohamadghannam4324]

You can have half of O2 because half of O2 is simply O. However, it is not written as O in the chemical equation because O does not naturally exist by itself in nature. People usually prefer whole numbers to avoid confusion, but both are correct.

[@banjalynesynshiang1170]

Can u help me one thing ....I don't understand how that 15/2 appear ....

[@user-df6ip8ic7c]

Because oxygen is a gas, it is placed next to the number two, and when it is multiplied by 2/15, the number two is abbreviated with the number two, leaving 15 atoms of oxygen.
Greetings from Iraq

[@Lovely_Maths750]

Tq so much sir ji ji ji 🙏🙏🙏

[@VijayKumar-rc2sw]

Sir, I have a doubt, can we leave the equation here, I mean in a fraction form, isn't it wrong?

[@wbreslyn]

The ratio is correct. But you have to check with your teacher. Some want only whole numbers.

[@Yuvrajjj29]

Bruh u can multiply by 2 . So that to make equation balanced by using ABCD METHOD answer come correct . If u don't know hot to do it just go for physics wallah . He can teach u with both methods . And u are Indian u can understand Hindi language . And u can understand easily. BTW I am not saying this channel is bad this channel helps me to check whether I have done correct balancing or not.
Thank you Dr. B

[@VijayKumar-rc2sw]

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[@wbreslyn]

You are most welcome!

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[@wbreslyn]

Any time!

[@a.e07]

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[@wbreslyn]

No problem, glad I could help with C6H6 (one of my favorite molecules)! --- Dr. B

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[@wbreslyn]

No problem! --- Dr. B

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[@wbreslyn]

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[@suchet714]

Is 2C6H6 + 7O2 -> 4co2 + 6H2o correct?

[@wbreslyn]

Close, but not quite:
Reactants: C=12, H=6, O=14
Products: C=4, H=12, O=14
The number of carbon atoms are different on each side of the chemical equation.
--- Dr. B

[@vasusrivastav1447]

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[@wbreslyn]

Glad I could help with C6H6! --- Dr. B

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[@wbreslyn]

You're welcome 😊

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So much CO2 produced by benzene

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[@wbreslyn]

You are welcome! --- Dr. B

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[@wbreslyn]

Glad I could help with C6H6! --- Dr. B