Solid Angle Tutorial

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  • เผยแพร่เมื่อ 5 ก.พ. 2025
  • Solid angle explained using integral calculus.
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ความคิดเห็น • 8

  • @owen7185
    @owen7185 3 ปีที่แล้ว +6

    Dr Remillard you're an excellent teacher, thank you

  • @jatingarg1375
    @jatingarg1375 2 ปีที่แล้ว +3

    thank u so much sir love you too much.. ☺️☺️
    after visiting so many videos and searches on google I got what i wanted to know about solid angle..
    Love from india thank u much sir again ...🇮🇳🇮🇳🇮🇳

    • @stephenremillard1
      @stephenremillard1  2 ปีที่แล้ว

      Thank you. That's very encouraging for me to hear.

  • @timothynguyen4305
    @timothynguyen4305 ปีที่แล้ว +2

    Thanks for the clear explanation!

  • @guitarttimman
    @guitarttimman 2 ปีที่แล้ว

    R d(theta) is the arc. It can also be derived using the Jacobean to convert from rectilinear to polar coordinates. Oh!

  • @evolforever7448
    @evolforever7448 2 ปีที่แล้ว +2

    thank you so much !

  • @guitarttimman
    @guitarttimman 2 ปีที่แล้ว

    This is great, but I have a question for you: Is this analogous to using double integration with surface area in rectilinear coordinates and then transposing it to polar coordinates? I am thinking of surface integrals where, when the function is equal to one, you get the surface area of a swept out patch.

    • @stephenremillard1
      @stephenremillard1  2 ปีที่แล้ว +1

      Along the lines of what you just described, solid angle is what you get when you integrate the area element without a function, or rather with the function equal to unity, and then divide the result by the radius of curvature, Omega=[Int(dA)]/R^2.
      As for rectilinear versus polar, since the area that Int(dA) gives is part of a sphere, it is considerably easier to work in spherical polar coordinates when finding solid angle. If you integrate in rectilinear coordinates, then the integral probably isn't being evaluated on the surface of a sphere. (Ah, good, I just saw your 2nd post and see that you made an additional comment about converting to spherical before integrating. Great point!)