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Would x=log base 6 of 36/43 be an acceptable answer to this problem
Different question between your thumbnail and your expalanation
I will tryLet 6^x=u=> u/6+u+6u=6=> u+6u+36u=36=> 43u=36, u=36/43---> please recall u=6^x 6^x=36/43 43×6^x=36 Approached by logarithm-----> x log 6 + log 43= log 36-----> x log 6 + log 43 = log 6^2-----> x log 6 + log 43= 2 log 6-----> x log 6= 2 log 6-log 43Both sides divided by log 6-----> x= 2 log 6/log 6-log 43/log 6-----> x = 2-log 43/log 6
Would x=log base 6 of 36/43 be an acceptable answer to this problem
Different question between your thumbnail and your expalanation
I will try
Let 6^x=u
=> u/6+u+6u=6
=> u+6u+36u=36
=> 43u=36, u=36/43
---> please recall u=6^x
6^x=36/43
43×6^x=36
Approached by logarithm
-----> x log 6 + log 43= log 36
-----> x log 6 + log 43 = log 6^2
-----> x log 6 + log 43= 2 log 6
-----> x log 6= 2 log 6-log 43
Both sides divided by log 6
-----> x= 2 log 6/log 6-log 43/log 6
-----> x = 2-log 43/log 6