Identify which dimension of this true shape is the true length. Project that to the front view and top view. This will give you an idea of the cutting plane line.
Thanks for asking. The cutting plane bisects the axis into two halves. In the front view, you have the true length of the axis of the cone. You can bisect and then make the cutting plane pass through this point in the front view. The cutting plane is a line in the front view. 👍
Thanks for asking. I am not sure if I have understood your question. Point 3 can be identified on the generator of O3 in the top view. I guess your question might be for points 4 and 10 whose generators lie on the axis of the cone. If I am right then please watch from time 11:17. The intersection point in the FV is first projected to the right most generator O3 (the point m') and then brought to the O3 generator on the top view (point m). Then you use a compass to bring this intersection length back to the generator O4 and O10. Kindly let me know if my understanding of your question was wrong.
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Thank you for the great video. Great technique!
You are most welcome!
Thanks
👍
I have been given that the true shape is isosceles triangle. How will the cutting plane be?
Identify which dimension of this true shape is the true length. Project that to the front view and top view. This will give you an idea of the cutting plane line.
Question. = How to section in solid boll ?
You will always get a circle as the sectional view. 👍
Thank you very much…
I will pass my wassce
👍
how do you determine the height of the cut?
Thanks for asking. The cutting plane bisects the axis into two halves. In the front view, you have the true length of the axis of the cone. You can bisect and then make the cutting plane pass through this point in the front view. The cutting plane is a line in the front view. 👍
How do you plot the the middle point (3) in the top view?
Thanks for asking. I am not sure if I have understood your question. Point 3 can be identified on the generator of O3 in the top view. I guess your question might be for points 4 and 10 whose generators lie on the axis of the cone. If I am right then please watch from time 11:17. The intersection point in the FV is first projected to the right most generator O3 (the point m') and then brought to the O3 generator on the top view (point m). Then you use a compass to bring this intersection length back to the generator O4 and O10. Kindly let me know if my understanding of your question was wrong.
God bless you thank you
👍👍
Circle have devide 8 equal part any problem
12 is preferred for more precise sectioning and projections.
Thanks a lot for your video
You are welcome!
Thanks......
👍
Good job sir
Thank you! 👍
admin plz yar ise awaz k sath btao virtually trace kaise lenge to thik se smjh aiyegi
Thanks. Nice advice for the future!👍
I think it should be better with voice 👍👍
Sure, will do for future videos.
It would be if u teach by ur voice than heading it will be understand for us
I can't change the older videos now but I will add voice for all the future ones. Your comment is appreciated. Thanks!
Sir ji plz audio ka sath 5 star rhega👂
Sure, for the future.
light b achi rakha kro sir
Sure ✔
Klaboo sah me duh zing-do
meaning please!👌
Clear ga theesi pettandi Sir for next video
?
Tnx sir
u r welcome!
Sound undha ledha doubt ga undhi
క్షమించండి, ఈ వీడియో కోసం ధ్వని లేదు.
I like more video .
You are welcome and there will be more, thanks.
Semmmmmaaaaaaa understand
Explain sir
Sure, for the future.
Thank but not thank
✔
Use the proper light
✔
Poor lighting
👍
Sir voice ke sath better rahega
Thanks for your comment. I am adding voice in the newer videos. I will try to update the older ones too, time permitting.
Are bhai kuch bol bhi liya karo...🤣🤣🤣
👍 I will keep your suggestion for the future!
@@1styearengineeringdrawing182 👍
PTA he nhi lga
Kindly clarify your query. Thanks.