Thank you so much! I attempted my FE exam after 15 years of my Bachelor in Civil engineering and passed at the first attempt. Your videos were so helpful. Thanks, truly.
Mark, just want to say a huge thank you for all of your videos, I passed the FE today. One of the problems on this video popped up finding area of a coordinate plane so just wanted to leave this comment here. I hope all is well and thank you so much!!!
Honestly, I would recommend any entry engineering student to make it through your series after completing prerequisite mathematics. All your tricks and explanations are great! I'm 2 years out of school and a structural engineer studying for my FE. Thank you for passing down your knowledge!!!
In case anyone else was wondering or curious.. In question 3, typically people don't weight the corrections applied to each lat and dep. It's an even split across them. However, YOU DO in this problem because the Bowditch-Compass rule :)
Hello, Mark based on the the calculations you have done, the last question's final answer is 513.64. However, there is no option for that answer from A to D.
Not sure if you saw, but someone asked a similar question below. His answer was "I had this question solved correctly in my notes and initially solved it correctly in the video, but when it didn't match the answer on paper, I second guessed myself. The correct elevation should be 513.64. I've reposted the pdf with the correct answer. Sorry for my confusion, I should have drawn a better diagram. I cut out the section where I wrote down incorrect information. Thanks!"
Just read further comments. His pdf is updated and the 513.64 is answer choice A. Just that in this video he had the older version of his sheet and it didn't have the correct answer we got
hi mark! for question 5 i just wanted to let you know I have an easier way to solve it (although it is completely geometric so maybe that defeats the purpose of a surveying question) basically I drew an outer rectangle connecting all my points (this one is 300 x 350). Then I subtracted each of the triangular areas (there are 3 for this problem). so : (Arec = 300 x 350) - (A1 = .5*200*150) - (A2 = .5*100*250) - (A3 = .5*300*100) = 62500 ft^2
Good, but I think you should train yourself on practicing the HB formula, maybe he includes it in the exam in another format in which your geometric tricks would not help :D.
Hi Mark! thank you for these videos. Quick question on problem 2, are we not supposed to subtract 90 degrees from the value found from tan(phi) since we are taking the degrees from the north axis instead of the x-axis? Thanks again
In question 4 it states from PI to PT, not PC to PT. Your answer is from PT to PC. I understand all the arithmetic but the question is confusing. I would be looking to find values from PI which is the midpoint according to the wording of the question.
Thank you for the class! I do have a question: for problem # 14, I don’t find why I’m getting: sin(1.7167) * 61.25=60.599 and you get 1.835 and basically the same for H2. What am I missing? Do I need to substract the h1 and the h2 value to some other value to get h1=1.835’ and h2=2.82’
Hey Mark, Can you elaborate on the rules for your method on question 5 (#5)? Unless you go around the plot CCW, you end up with a different answer. I'm wondering why that is.
This is a non-problem after watching other videos. The points should be labelled in numberical order on the test, which tells you which direction to go.
Hi Mark, I see you use control F often in these videos. Is this function permitted while taking the FE? It seems like using ctrl F would be quite an advantage.
For Q10, why do you have to divide it into 2 blocks? Cant you just add 1875 and 2500 for the area and divide the sum by the avg of the six heights? which actually I tried and got a different answer from yours:( Thank you in advance!
In this case, the grid method typically requires that you find the average area for each section. Each measurement is weighted more appropriately by dividing into two blocks.
I attempted without watching solution. I broke it into 3 sections and the areas matched but had trouble finding average depth for top triangle section. Is there a way to find the avg depth? Videos are a huge help
Question 5 can also be solved by area of trapezoid formula. It’s much more faster approach. Get the length of each side with coordinates (200’, 200’, 300’, 250,) Trapezoid = (200+300/2) x 250 = 62500 sq. Ft
The question asked the bearing ( which is only an angle ) but your answer was for the coordinate system Northing and Easting >>> Can you check, please ??
Not sure if you saw, but someone asked a similar question below. His answer was "I had this question solved correctly in my notes and initially solved it correctly in the video, but when it didn't match the answer on paper, I second guessed myself. The correct elevation should be 513.64. I've reposted the pdf with the correct answer. Sorry for my confusion, I should have drawn a better diagram. I cut out the section where I wrote down incorrect information. Thanks!"
Thank you so much. I passed my FE.
Thank you so much! I attempted my FE exam after 15 years of my Bachelor in Civil engineering and passed at the first attempt. Your videos were so helpful. Thanks, truly.
How long do you prepare for the exam?
Mark, just want to say a huge thank you for all of your videos, I passed the FE today. One of the problems on this video popped up finding area of a coordinate plane so just wanted to leave this comment here. I hope all is well and thank you so much!!!
Your videos was so helpful. I just pass my FE…
Congrats!
Honestly, I would recommend any entry engineering student to make it through your series after completing prerequisite mathematics. All your tricks and explanations are great! I'm 2 years out of school and a structural engineer studying for my FE. Thank you for passing down your knowledge!!!
Did you pass?
In case anyone else was wondering or curious.. In question 3, typically people don't weight the corrections applied to each lat and dep. It's an even split across them. However, YOU DO in this problem because the Bowditch-Compass rule :)
Hello, Mark
based on the the calculations you have done, the last question's final answer is 513.64. However, there is no option for that answer from A to D.
I think the last question should be 518.3+4.75-4.75+1.84-2.82 = 517.32'. the video cut for some reason
Take a look on the pdf , he attached in bellow. There you will get the updated options.
So the answer to question 14 is skipped in the video? I got 513.637 feet
I got that too, none of the answer choices though. I think it might be an error
Not sure if you saw, but someone asked a similar question below. His answer was "I had this question solved correctly in my notes and initially solved it correctly in the video, but when it didn't match the answer on paper, I second guessed myself. The correct elevation should be 513.64. I've reposted the pdf with the correct answer. Sorry for my confusion, I should have drawn a better diagram. I cut out the section where I wrote down incorrect information. Thanks!"
same here, so I'm confused
Just read further comments. His pdf is updated and the 513.64 is answer choice A. Just that in this video he had the older version of his sheet and it didn't have the correct answer we got
hi mark! for question 5 i just wanted to let you know I have an easier way to solve it (although it is completely geometric so maybe that defeats the purpose of a surveying question)
basically I drew an outer rectangle connecting all my points (this one is 300 x 350). Then I subtracted each of the triangular areas (there are 3 for this problem).
so : (Arec = 300 x 350) - (A1 = .5*200*150) - (A2 = .5*100*250) - (A3 = .5*300*100) = 62500 ft^2
Good, but I think you should train yourself on practicing the HB formula, maybe he includes it in the exam in another format in which your geometric tricks would not help :D.
Great videos! Do you think we could have PE Civil- Transportation reviews soon too?
Hey Mark,
Thank you, really enjoyed and learned a lot.
Hi Mark! thank you for these videos. Quick question on problem 2, are we not supposed to subtract 90 degrees from the value found from tan(phi) since we are taking the degrees from the north axis instead of the x-axis? Thanks again
I think he forgot to do so. I believe you are correct reysoriano
For a bearing? I'm confused...so minus 90 from phi?
I think this is right.
yeah ur right he didnt do that
no, he flipped opp and adj so you don't have to subtract anything
Great series!
However, I did not find the answer to question 14. Would you please say to find the revelation for point 2?
Thanks
Maybe A-517.32?
What's the difference between a central angle and a deflection angle in a simple curve?
Hello. Question 4 why is PT not Pc + lc
it’s not the correct way. Lc won’t be the chain length. the station length will go through curve instead of straight line.
Question 14 cuts off before the answer is given and jump cuts to you jumping to the beginning page. :(
In question 4 it states from PI to PT, not PC to PT. Your answer is from PT to PC. I understand all the arithmetic but the question is confusing. I would be looking to find values from PI which is the midpoint according to the wording of the question.
I agree with you. I would think that the angle would be 40 in that case, but then I got confused with Mark's answer.
QUESTION: On the 2nd question, why did we consider the distance from AB (hypotenus of the triangle) as the Easting value?
Thank you for all the help. Will you have a session on Chapter 7 Materials?
Glad the videos help! I will probably add materials... but don't have a date scheduled yet.
Thank you for all the Help and amazing Class.
What happened to the last question? Shouldn't we add h1 and minus h2 ? I mean 518.30+1.84-2.82? Thanks for the response in advance.
Hi Mark, how do you know the units are originally in feet for question 5, is feet usually assumed when units aren't given?
for the 5th problem i just found the area of the large rec and subtracted out the triangles and got the same answer.
is it safe to say fill problems = use prismoidal eq and cut problems = use average end eq ?
These are very useful. Thanks very much for your videos here.
Thank you for the class! I do have a question: for problem # 14, I don’t find why I’m getting: sin(1.7167) * 61.25=60.599 and you get 1.835 and basically the same for H2. What am I missing? Do I need to substract the h1 and the h2 value to some other value to get h1=1.835’ and h2=2.82’
Sorry!! I found out that my calculator was in Radians… not degrees… :)
Perfect. Thanks Mark
Hey Mark, Can you elaborate on the rules for your method on question 5 (#5)? Unless you go around the plot CCW, you end up with a different answer. I'm wondering why that is.
This is a non-problem after watching other videos. The points should be labelled in numberical order on the test, which tells you which direction to go.
Hi Mark, I see you use control F often in these videos. Is this function permitted while taking the FE? It seems like using ctrl F would be quite an advantage.
Yes it’s allowed
"hopefully these session are helpful"
this is literally about to help me pass my FE tmo, but ill get back to yall on how it goes
How was your test? MADISON, Was it good?
For Q10, why do you have to divide it into 2 blocks? Cant you just add 1875 and 2500 for the area and divide the sum by the avg of the six heights? which actually I tried and got a different answer from yours:( Thank you in advance!
In this case, the grid method typically requires that you find the average area for each section. Each measurement is weighted more appropriately by dividing into two blocks.
@@MarkMattsonPE thanks a lot, you're the best! I've been watching ur lectures for the last few weeks and they're so helpful👍
I attempted without watching solution. I broke it into 3 sections and the areas matched but had trouble finding average depth for top triangle section. Is there a way to find the avg depth? Videos are a huge help
Is Compass Rule not even the FE handbook?
Question 5 can also be solved by area of trapezoid formula. It’s much more faster approach. Get the length of each side with coordinates (200’, 200’, 300’, 250,)
Trapezoid = (200+300/2) x 250 = 62500 sq. Ft
I don't think it is considered a trapezoid. Maybe it's a coincidence with the result.
The question asked the bearing ( which is only an angle ) but your answer was for the coordinate system Northing and Easting >>> Can you check, please ??
I can check the wording, but which question? Thanks!
@@MarkMattsonPE i believe Q.2. take the angle from the north. i believe you took it from the x-coordinate
How did you find the angle of 2.7667 in question #14?
The zenith angle for A minus 90 degrees since it is below the horizontal
For question 6 and 7 why were the last two -.5 on the Top, bottom and width?
Hi @Naviita Ramro, I'm not sure I follow your question. Can you elaborate? Thanks!
Hello. Please for question 14 , should the correct answer be option C ?
Not sure if you saw, but someone asked a similar question below. His answer was "I had this question solved correctly in my notes and initially solved it correctly in the video, but when it didn't match the answer on paper, I second guessed myself. The correct elevation should be 513.64. I've reposted the pdf with the correct answer. Sorry for my confusion, I should have drawn a better diagram. I cut out the section where I wrote down incorrect information. Thanks!"
thanks Mark
getting ready!
Thank you!!
In Qs 6 and 7, u used 1.5 and 7.5 but at the question is 1.6 and 7.6 ?
Check units... 1 foot 6 inches is 1.5 feet. Does that help?
@@MarkMattsonPE i hv not get u
@@MarkMattsonPE could u explain more?
In US Imperial, 1.5 feet is 18 inches (12 inches/ft). Or you could say 1 foot and 6 inches if mixed inches and feet.
@@MarkMattsonPE thank u , I got it
Too many ads...
Thanks for the feedback... whether I put ads on a video or not, YT will put them there. I've limited the ads to only skippable ones.