You are literally the reason as to why I understand chemistry. My professor has made these concepts out to be so difficult and you make it so simple and explain it so well! You are a LIFESAVER! Definitely coming back for Organic chem help! Thank you!
I could never get a good grasp of acids and bases, even throughout college, but the way you explained this has been extremely helpful. I wish I had teachers like you when I was learning chemistry basics in school
I wish I could have you as my professor. Out of all the chemistry professors I have delt with. you seem informed, organised, and able to communicate effectively...As a student that is all i am asking for.
Hey Dhruv! If you explore the channel you'll see an old Gen Chem playlist with buffers and titrations covered in chapter 17. This lesson is part of an updated playlist and I'll be remaking and releasing these analogous chapter 17 videos week after next. But the old ones are also embedded in a free course on my site often with some extra content and organized with a dropdown menu that you might appreciate. You'll find the lessons here: www.chadsprep.com/chads-general-chemistry-videos/buffer-chemistry/ www.chadsprep.com/chads-general-chemistry-videos/titration-curves/ www.chadsprep.com/chads-general-chemistry-videos/titration-calculations/ Lots of extra content for titration calculations on that last page. Hope this helps!
Thank you so much for the amazing lesson! I was just wondering if you have any plans on teaching inorganic or analytical chemistry and making videos in those fields? Because you're the best teacher i've EVER had
Hi Chad, can you explain why acids only donate 1 H+ to become a base? For example, why isn't the base of acid CH3COOH then CH2-COO- for example, or why not donate all the H to become C(3negative)COO-? Or NH4+ then N(4negative) instead of NH3?
Not all of those H's in CH3COOH are acidic. The H-C bonds are not polar so it is not easy to break the bond and lose the H. The O-H bond in a carboxylic acid is much weaker due to high polarity of the O-H bond and further charge delocalization from the carbonyl group which stabilizes the conjugate base CH3COO- making that H acidic (dissociation occurs in solution). In order to break the C-H bond we would have to put energy in, it wouldn't freely dissociate in solution. Hope that helps!
sir may you please assist in solving the following problem A 25ml sample of 0,10M sodium benzoate is titrated with 0,10 M of HCl what is the pH of after the addition of of 32,0ml of HCl (kb of C6H5CO2- =1,6X10^-10)
I cover titrations in this playlist in chapter 17. I specifically cover weak acid/strong base and weak base/strong acid in this lesson: th-cam.com/video/3Y9TaxwcQGs/w-d-xo.html Tune in around 21:16 for how to calculate the pH when you are past the equivalence point. Hope this helps!
Trust in the Lord with all your heart and lean not on your own understanding. In all your ways acknowledge Him and he shall make your paths straight. Proverbs 3:5+6
The NH3 + CH3COOH = NH4+ + CH3COO- Example makes no sense to me as to why the acids are the acids, and the bases the bases. (based off what I learned from the previous info from this video) So lost!
So the acidic species are NH4+ and CH3COOH because they both have a 'donatable' proton, forming the conjugate bases NH3 and CH3COO-... can you let me know what you are strugglinig to understand particularly?
You are literally the reason as to why I understand chemistry. My professor has made these concepts out to be so difficult and you make it so simple and explain it so well! You are a LIFESAVER! Definitely coming back for Organic chem help! Thank you!
Glad the channel is helping you - Happy Studying!
You just took my love for chemistry to a new high,thank you for the lesson Chad
That is great to hear - you're welcome!
I could never get a good grasp of acids and bases, even throughout college, but the way you explained this has been extremely helpful. I wish I had teachers like you when I was learning chemistry basics in school
Glad the channel is helping you now.
not LSD 😭 this man is gold
Glad you think so!
Studying for MCAT rn and your vid are amazing!! you are single-handedly helping to boost my score. Thank you!
You're welcome and Happy Studying!
You made comprehension of my lectures easier. Thank you, Chad; you are the GOAT.
You're welcome - and Thank You!
the best channel to learn sciene!
Thanks for saying so!
I am a chemistry student and your explanations helped me so much. Thank you!
Excellent!
You made my day when you mentioned HF can dissolve dead bodies like in Breaking Bad
Yeah Science!
I wish I could have you as my professor. Out of all the chemistry professors I have delt with. you seem informed, organised, and able to communicate effectively...As a student that is all i am asking for.
Thank you!
I think you are by far the best Professor I've come across. Thank you for your work!
Greetings from Cyprus!
You're welcome and Thank You from USA!
your videos save my AP chem grade you make it so logical and simple!! God bless you
Glad to hear that and Thank You!
Dear Chad. I am overwhelmed to see Trust in The Lord along side Acids and Bases. Be blessed bro
Right back at ya!
You are amazing. And hopefully your channel will grow.
For now I will do my part by sharing it to my mates
Thank you - Appreciate that!
Yehey! I found the best explanation about these concepts. I haven't taken Chem in my entire life, so thank you soo much. 🙏👍😊
You're welcome - glad it helped!
wish you were my chem professor... Thanks for this lesson!
You're welcome!
Thank you for your explanation. It has saved me so much time reading books and trying to figure out how to analyze the information.
You're welcome!
I hope you have a good day chad. Thank you very much ♥️
Thank you - have an awesome day yourself :)
From Ghana and I completely understood it thank uuu
Excellent!
Your videos are so helpful. Thanks!
You're welcome, F.P. - and thank you!
Great work sir.
Thank You
Beautiful explanation! Cant wait for next video to come out
Awesome! It's coming in the morning and another Thursday morning.🙂
@@ChadsPrep please do a video on buffers and titrations
Hey Dhruv! If you explore the channel you'll see an old Gen Chem playlist with buffers and titrations covered in chapter 17. This lesson is part of an updated playlist and I'll be remaking and releasing these analogous chapter 17 videos week after next. But the old ones are also embedded in a free course on my site often with some extra content and organized with a dropdown menu that you might appreciate. You'll find the lessons here:
www.chadsprep.com/chads-general-chemistry-videos/buffer-chemistry/
www.chadsprep.com/chads-general-chemistry-videos/titration-curves/
www.chadsprep.com/chads-general-chemistry-videos/titration-calculations/
Lots of extra content for titration calculations on that last page. Hope this helps!
Thank you so much for the amazing lesson! I was just wondering if you have any plans on teaching inorganic or analytical chemistry and making videos in those fields? Because you're the best teacher i've EVER had
You are a wonderful Teacher
Thank you for the kind words!
super easy and useful, thank you Chad
You bet!
Thank you for explaining things so well, so thoroughly:)
Glad it was helpful!
NIce simple explanation! Thank you!
You're welcome!
What is the difference between MCAT prep video and this?
great as always
Thank you
Thank you so much, Chad.
You're welcome.
love the video + the shirt! thanks for all your help :)
Thank you + thank you - You're Welcome!
Absolute legend, thank you so much!!!
Very welcome!
thank you
You're welcome
Super helpful! Thank you!
Very welcome!
I think more examples would have done it but it was great
Thanks.
i just didn't enjoy and learned from your video but also loved seeing you rock in "TRUST IN THE LORD..." tee. God Bless!
Thanks and same to you!
Hi Chad, can you explain why acids only donate 1 H+ to become a base? For example, why isn't the base of acid CH3COOH then CH2-COO- for example, or why not donate all the H to become C(3negative)COO-? Or NH4+ then N(4negative) instead of NH3?
Not all of those H's in CH3COOH are acidic. The H-C bonds are not polar so it is not easy to break the bond and lose the H. The O-H bond in a carboxylic acid is much weaker due to high polarity of the O-H bond and further charge delocalization from the carbonyl group which stabilizes the conjugate base CH3COO- making that H acidic (dissociation occurs in solution). In order to break the C-H bond we would have to put energy in, it wouldn't freely dissociate in solution. Hope that helps!
@@ChadsPrep yes that helps, thank you
But did you mean to say the C-H bonds are not polar? Instead of H-C?
Thank you Chad!
You're welcome!
Im back to thank you again Chad :) the breaking bad comment made me check comments so..
Thank you for this ❤
You're welcome and Thanks!
sir may you please assist in solving the following problem
A 25ml sample of 0,10M sodium benzoate is titrated with 0,10 M of HCl what is the pH of after the addition of of 32,0ml of HCl (kb of C6H5CO2- =1,6X10^-10)
I cover titrations in this playlist in chapter 17. I specifically cover weak acid/strong base and weak base/strong acid in this lesson: th-cam.com/video/3Y9TaxwcQGs/w-d-xo.html
Tune in around 21:16 for how to calculate the pH when you are past the equivalence point. Hope this helps!
you’re everything
Glad the channel/videos are helping you!
@@ChadsPrep In my prayers you’re 🤍
@@mahra855 Thank you.
What does your shirt say?
Trust in the Lord with all your heart and lean not on your own understanding. In all your ways acknowledge Him and he shall make your paths straight. Proverbs 3:5+6
this man is literally Heisenberg. Didn't know he was still living.
Ssshhhhh - no one needs to know!
19:28 this part caught me off guard because the Super Bowl just happened and this video was filmed one year ago
What timing!
w chad
Happy Studying!
The NH3 + CH3COOH = NH4+ + CH3COO- Example makes no sense to me as to why the acids are the acids, and the bases the bases. (based off what I learned from the previous info from this video) So lost!
So the acidic species are NH4+ and CH3COOH because they both have a 'donatable' proton, forming the conjugate bases NH3 and CH3COO-... can you let me know what you are strugglinig to understand particularly?
Avvont wwnasoon