Test Your Coordinate Geometry - 12 Questions: graphing absolutes, coordinate ratios, pythagoras ...
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- เผยแพร่เมื่อ 10 ก.ย. 2024
- 12 questions ordered roughly from easy to difficult, covering missing coordinates, graphing absolutes, distance between two points, picking numbers on graphs, quadrant analysis, x and y intercept and much more!
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10:54 Lets take a moment to appreciate that straight line he drew with the tick!!
That's how psychologists measure a persons attention to precision and details. He is good!
Hi Phillip, can we please have an 'ULTIMATE' video on Word Problems alone? I have my GRE exam in the next 2 weeks. Your videos help a lot. Thank you! 🙏🏼
Hey Ashish, How did your GRE exam go?
@@aniketsingh4953 Not good brother. Will attempt again after TOEFL.
Please, continue doing such difficult questions for Geometry. Thanks a lot for the videos.👍🏻
I almost cried that explanation for q15 was so beautiful
for number 7 i used the distance between two points formula and it worked just as well FYI.
Square root ( (Y2-Y1)^2 + (X2-X1)^2 ) is a little more straight to the point if there is no diagram!
Also, for 14. I set a ratio of 1.5/x = 5/4 and the answer when cross multiplying was exactly 1.2
Pls make more videos on Reading Compression practice
Yes I have GRE in one month and I am fearinf for verbal esp RC
@@pubgtencent4436 same bro😅
Same man scores for RC are not improving less than a month to go ✨
You know I focused so much on learning vocabulary for verbal with little improvement, when I started looking into strategy, patterns, knowing what to look for when they ask certain questions , practicing reading difficult content etc helped me Improve a lot
Come on man how many times u will win one heart I just need this particularly at this time thanks ❤️
I really found this very helpful, can we get more?
Thank You, it was very helpful. These practice questions actually cover the possible aspects
Question 15: From the graph, we see that the line goes through (0,0). So we can find the slope and the equation shows -m=1.5n, which is answer A. What I am missing here? Slope: -2/3-; so, y=-2/3 x -> n = -2/3 m -> -m = 3/2 n.
i got the same answer by the same method, i think it should be A as well
Your final answer is right but the conclusion is wrong. If (-m) is negative and is equal to 3/2 (1.5) of n. For the equation to tally, n must be negative. So if n=-2, -m =1.5(-2) =-3. Negative -2 two is greater than -3.
He did it perfect.
Thank you, Phillip. Absolutely great and simple to comprehend
In the question with the slope as -13/12 we can clearly see that the rise is greater in magnitude than the run, so without calculating intercepts the answer is clear that since a0 is the rise and ob the run, ao has to be bigger. since both ao and ob are in first quadrant, they are both positive and values can be compared directly, if they were to be in any other quadrant, we'll do the same by first calculating which has a greater magnitude then seeing which is bigger after considering signs as well.
i am so good at this part, but I need to focus more on the requirements😅😅, thanks for solving a variety of coordinate problems
the last question , how is it not d?
we cant be sure about the values of B
Won't the answer of Question 12 and 15 be "D"? Little bit confused.Can you please explain it ?
Is the standard of the questions that are going to be asked in the gre quant advanced section or the one before?
Also is this is the highest level of questions asked in the GRE ? I’ll be appearing in 2022.
Thanks Philip:)
Not quite the highest but close
Excellent Philip Thank you so much :)
Hii Philip..
Quick question, in question no. 9.. following graph equation y = -|-x|..
Why not option A ??.. because if considered y=mx+c and c is zero which means line is passes through origin and slope must m must be in negative direction =>which give {y=-x}
So why not A ?
Alt. method for question 14: (1) Find the slope of the line by using the point (0,0) as the second point--> m = 1.25 (2) -3.5 / x-4 = 1.25 (3) Work out x = 1.2
Alt. method for question 11: (1) Derive the equation of the line by using a second point (e.g. 10,-10)- which is the reflection (2) Write out the in-equality: Y> -1X (3) Test the answer choices
Hey really grateful for the wonderful videos.
A small doubt. For Q11- the shaded region lies in quadrant IV, a coordinate lying there shouldn't it be (-x,-y). Why are we taking x as positive.
Great work! For last question, earlier you said if both qtys are -ve we cant say for sure about their value, as we dont know exact location of points. Will it not make the ans D?
at 20:40 it should be D na as m is negative and n is also negative and it can be anything
Hi Philip, quick question. Aren't the coordinate geometry questions drawn to scale in GRE? So we will kind of know the positioning in Q8 or am I missing something here- this is with respect to Q8
Also in Q11 why is the endpoint 9,-9 like we did in the later questions to maintain the symmetry of moving 10 points to the left shouldn't we have moved 10 points to the right and then 10 points down to get (10,-10)?
Thank you so much for these Phillip! Btw, I feel like there's something wrong with the last question.
Please for the first example why wasn't the area of the quadilateral calculated like a square. Like 13 ×13
It could have also been a rhombus... we don't know of the all the angles are 90 degree.... the figures definitely confirms that
Hey Philip! Loving the videos so far, just a question: In Question 14 and 15, you'd mentioned the ratio of coordinates of 2 points on the same line have to be the same. I'd noticed that these two lines pass through the origin. So, is the point about consistent ratios valid only for lines passing through the origin or any line in general?
Just those going through the origin. But for any line the ratio moving between coordinates will stay the same, even if not thr actual coordinates.
@@TheTestedTutor Thanks for the quick reply Philip. Ohh, ohkay so for a line passing through the origin, the ratio of coordinates on that line is the same, i.e if (a,b) and (c,d) are two points on a line going through the origin, a:b = c:d. Would that be correct?
PS: I quite didn't get the second sentence of your reply 😅
Hi, Can someone confirm the answer for the question 12 is D or B? And whether we can assume values for coordinate geometry if graph is given with unknowns.I know Geometry diagrams are not drawn to scale but what about Coordinate geometry with a diagram?
It’s D brother
Hello Philip can you make playlists of the different relevant topics? It will be more helpful. And how to attend your online classes?
thanks philip
Loved it
1:40 - The area of the shaded region will be 240 and not 120 according to me. Can you please check?
Hi Phillip, they is a mistake on question 10 according to values you picked d=3 and b-3, if we multiply the 2 we get -9 therefore (-bd, bc) is (-9,-6) making quadrant 3 the answer
You, Sir, are doing the Lord’s work, can’t thank you enough, Philip. But I was wondering what the question 15 suggested that the point B is exactly a mirror image of point A. Couldn’t it have been any point before or after (3,-2) , granted that it’s not drawn to scale, making the answer D instead?
Exactly what I'm thinking, it's nowhere mentioned in the graph that it's extending the same distance into the IV quadrant as well, so as far as we know, it could be (2,-2) as well, or it could be (3,-2) too, making the answer "Option D"
phil does it mean |ab| is different from ab? cos you did multiple them but didn't find the distance. why?
Hey in question num 10:
They dont even mention abcd are negative or positive. there will be multiple possibilities right? any points can be in all coordinates right?
Could you do one on sequences and series please? @TheTestedTutor
For the first example with the Perimeter= 52 and Area= 120 would the final answer be D. The relationship cannot be determined?
But the relationship can be determined..? Isn't 120 bigger than 52 :)
19:00 Q14
Can you make more geometry videos?! For the GRE =(
Hey Philip. I'm struggling to know what the question is asking. For question 8, seems we needed to multiply the variables (I thought they were asking for the length of the line segment). For question 13, I thought aha, multiply the variables (each variable multiplied by O means they're both equal to zero), but it was asking for the length of the segment! How do you know what the GRE is asking for?
i have the same doubt di you figure it out?
@@vineetsaddi3177Points are denoted by capital letters and coordinates of a point are denoted by small letters. So in question 13, you cannot just multiply 2 points A and O so that's how you know they are asking for the length and in question 8 you can multiply the value of the coordinates b&d to get the value of bd
oh thanks a lot, it's clear now. sweet
Question 14: Why not just cross multiply the ratio?
You missed the negative sign in front of 'bd' for question 10.....the resulting coordinate was suppose to be (-9,-6)
Sorry for the late response but you’re wrong
In question 9 if Y=-X then the graph must be option A, Y=-l-X|=-X right Philip?
That's what I got too...
we need x and also y values ,so to find y values u can assume any number and substitute in x ,so its always the same (negative ) "y" can never be positive (since you should substitute the value of x inside the mod rather than outside ) ,feel free for pointing errors and other queries .
Yeah yeah I got it mate, thanks
@@xiction but don't ignore the fact that "x" has 2 values for the given "Y". that's called Modulus operation
@@prajwalpatil7036 oh I see - thanks!
Actually i think that 13 th question : slope=rise/run
Rise = -13 and run= 12 that's why answer could be B . Guys am I right ? If not pls write comment.
I'm afraid you are wrong. you are right to guess the Negative slope, but you should calculate the coordinates
@@prajwalpatil7036 Wouldn't the answer be C since coordinate O is 0,0, effectively making any number A and B are multiplied by equal to 0?
@@alfarix No, this is where you getting this wrong.
For Q no 15, how could we be sure about coordinates of b(m,n) . Question doesnot say, it goes through origin. How could we assume that. So, I thought ans to be D.
@@amirman6531 exactly same thought
the last question , how is it not d?
we cant be sure about the values of B