IR spectra practice | Spectroscopy | Organic chemistry | Khan Academy
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- เผยแพร่เมื่อ 8 ก.ค. 2014
- Practice with identifying the compound that corresponds to an IR spectrum. Created by Jay.
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Organic Chemistry on Khan Academy: Carbon can form covalent bonds with itself and other elements to create a mind-boggling array of structures. In organic chemistry, we will learn about the reactions chemists use to synthesize crazy carbon based structures, as well as the analytical methods to characterize them. We will also think about how those reactions are occurring on a molecular level with reaction mechanisms. Simply put, organic chemistry is like building with molecular Legos. Let's make some beautiful organic molecules!
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Damn this video was awesome. Wish this guy would do practice problems like this for like an hour straight on video while explaining them
Those questions are easy... ..
Do you know how to identify the molecule bonds in the raman spectra?
Amazingly amazing. Thanks. As a food scientist ( not chemist) who needs to understand FTIR I enjoyed your videos. Keep making fantastic videos.
Do you know how to identify the molecule bonds in the raman spectra?
i understand better now than when i was taught in class... i love this
i can understand very well with this video...Thanks
clearest explanation i've seen so far, good approach to take 3 spectra in a row to reinforce the points you were making.
hey Khan Academy, I appreciate the work you do. it has helped me alot. The only thing that drives me crazy is that I constantly have to figure out the order of the videos. I never know which one comes before which. could you please put numbers on them? thanks
+saphire ty if you press the link the description box thats after more free lessons you would see the exact order :)
+saphire ty These videos are uploaded in their respective series in khan academy's website.
Hi khan academy, these videos were so usefull for me and i wish the best for you, thanks a bunch
Amazing video, thank you doctor 🌹
Life saver!!!!! Keep it up Sal khan
easy to understand. keep it up
great vid TONNES of help :)
heh. that last one tied me up well and good. forgot about resonance d'oh.
great insight, best yt video on the topic
Wonderful!
that was so understandable
This was really really helpful. simple and direct. However, the translation seemed to cover bottom half of the graph every time I paused the video to analyze the marks. Nevertheless, great video! more power to your elbow.
You made this look so easy.
Good video. Now I understand this topic better. Just one question though, why must the wavenumber be 1500cm-1 to separate diagnostic diagram from fingerprint diagram?
vedio is helpful
Thx
thank uuuu
…..it all makes sense now omg
At lectures this seems like shit .. thanks khan academy you are a life saver
I need more difficult problems, any links anyone?
Correct me if I am wrong, but in the second spectra, should there have been a group of bands (around 4) in the 1450-1600 range to show the presence of an arene? Also, on the last spectra, you have the 4 bonds in the 1450-1600 range but it isn't the ring (even though the alcohol is clearly absent). My thing is, why are these 4 peaks showing up or absent when they should/shouldnt be?
+Zach Jodoin It wasn't an arene.
How do you identify the different molecules in graphs?
can please somebody tell me .... what will be the range for peak of FeCl3 ... please rply fast 😥
Sir, I have doubt in the last example of this. It is more than 1700 so I think it will be conjugated carbonyl
I agree, we read the frequency from the right. So since the peak is before 1700, it should be the conjugated carbonyl
how do we define a double-bond region or triple-bond one? also i wonder why we set 1500(1/cm) to divide the diagnostic and footprint region?
Check out part one of this video
question...for the last one how do you know that it's a conjugated ketone? do you have to test with resonance?
2:55 On my chart it says that the carbon carbon triple bond should be less than 2200, why did you say that the triple bond should be located near 2500?
Hello,....What related to the intensity of absorption in the infrared spectroscopy..... Please answer me
The intensity is related to the frequency at which electromagnetic radiation can simply propagate through space and can be categorized by it's wavelength or frequency in a given functional group.
fuck, this was helpful! thnx!
what is a conjugated ketone?😐
+Okay Bye when you have a double bond near a carbonyl group C=C-C=O
A conjugated ketone is when a ketone, or simply put in any molecule can undergo resonance. When it can undergo resonance, it will actually lower the value of peak.. So if I were to say ketone occurs around 1715 cm^-1 due to conjugation, I can simple assume 1690 - 1700 would be a conjugated ketone!
how to know where to separate the fingerprint and dagnostioc region? please help my final exam is within few days
The diagnostic region is left of 1500cm-1. We ignore the Fingerprint region to the right.
this video doesn't teach us the basics; it only teaches us how to recognize the molecules and it seems like there is a lot of background knowledge that you need to know in order to solve these problems, like the wavenumber of the molecules for instance
can you please make a video about how to actually solve these without background knowledge?
i am given nearly illisible rmn h , rmn C , UV , IR and mass spectrums , no formula and i have to find the molecule ...
it s much more difficult than having to guess between 3 ...
fuck me
Does anyone else think he sounds like Jacks FIlms
this video shows you to how to identify a molecule but doesn't teach you the ground rules and basics
+Karol Aaron that is what the other videos are for. The title of this video is "IR spectra practice" not "Basics and ground rules of IR spectra"; try a different video.
+Karol Edward Look at the first video of this series "Introduction to infrared spectometry"
Take a given molecule, then go in importance
C=O
O-H
N-H
C-O
C=C
C triple bond with C
C-H
C triple bond with N
Any miscellaneous details like that NH2 has to peaks in the alcohol region, etc. Then it comes down to process of elimination.
This is ridiculous, why do not you explain how to know which functional group supposed to be where in the IR so that we can follow? None of what in the video makes sense to me, but thank you for the video anyway.
I don't mean to be offensive in any way, and I absolutely LOVE khan acad and what they're doing, a huge help to all of us around the world. But for me, the person teaching this sounds very exhausted and fails to maintain my attention and interest in learning (everytime I watch any of his videos.) it's a shame because the information is gold
Bruh you never use X as a variant in chemistry. X indicates halides, X-H is a hydrogen halide.
the sound is not good I am quite disappointed