Set associative mapping

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[@hassansyed5661]

You are a good teacher and I learned many things from you. Respect for you.

[@prateeksahni2923]

@8:12 Shouldn't direct mapping require only a single comparator?
Our search space is just a single line

[@neocyndaquil]

Very clear! Thank you!

[@wildglorypsn]

very very helpful!thank you!

[@jenliang5292]

Super good explanation, thank you Sir.

[@tadassatafarra7484]

@7:03
the tag is represented with 2 bits (give us 4 options for tag), where the set size is 2. do we use modulus?
i.e. if we want to map 11 10 11, which will be mapped to the same set as the given example
will it be mapped to first cell in the 2nd set? if so - it means we can't map 01 10 11 and 11 10 11 without override ?
thanks!!

[@svssukesh1170]

thank you sir....the way you explain is very clear

[@m.chavoshi1091]

This video should be added to "computer organisation" playlist

[@puneetchugh4769]

Super teacher with super knowledge

[@BiranchiNarayanNayak]

Excellent tutorial.....nice explanation.

[@amithanilgeorge4956]

Straight to the point..no BS

[@rutujasanjekar6105]

Nice explanation....thank u very much

[@evilmulle4228]

I'm not sure if I just didn't hear this because of your accent, but when you say that only 2 comparators are needed is that because you use the same two comparators for each set, like for example with a multiplexer choosing which set is the input?

[@nirabraj4477]

Thank U !!

[@sabamunawar9267]

sir how we take 16 number of block in memory??

Thanks!

[@drashtigaradharia2270]

If you give example in which bit required for tag and lines are different then it would be more easy to understand... please make this video again.... thank you for doing noble cause.

[@akashdeepbohra9717]

No of sets in set associative mapping,is equal to(or say congruent to) , No of lines(blocks) in direct mapping .

[@AbhishekMishra-nx5ql]

Your videos Helped a lot during my semester exam prep. Thank you very so much for making these videos.

[@gbdhal3804]

could not get a clear idea about hardware level implementation of set associative mapping.
Is here any one to help by just inserting a link !!!
Thanks in advance......

[@michaelszczech9829]

Do all two-way set associative cache have four sets within them? If a two way set associative cache has 256 slots and 16 words per block? Would the total number of blocks be 1024 and number of words be 16,384?

[@acreddysreedharreddy2067]

good explaination and examle

[@shellongchow99]

So there must be an address mapping table for cache memory translation?

[@sabamunawar9267]

a set-assocative cache consist of 64 lines or slots , divided into four-lines sets. main memory contain 4K blocks of 128 words each . show the format of main memory addresses?????????
can u plz solve this question

[@sudiptaguria]

Sir I'm not confident whether I'm right or wrong, is the size of main memory 64 B?? I think it would be 64 KB.

[@abdelrhmanahmed1378]

why tag need 2-bits is only 2 tag in each set so 1-bit can represent it 0 or 1 !!?

[@rkbshiva]

Because the cache memory can store only 32B it seems like we need only 1 tag bit.
But remember our address must be capable of mapping the main memory which is 64B.

[@madetigowtham2880]

sir, at starting.... you have written that no of lines= CS/BS ; then the lines should be 32B/4B right?? then how it is 8 lines??

[@a2zuser1]

Dear Ravindrababu, In the 6 bit physical address we have 2 bit block offset. What is the use? Tag bits are for associating 2 lines in a 2-way set. what is the purpose of 2 bit block offset

[@tensor2586]

What determined the size of the physical address to be 6-bits?

[@tensor2586]

+tensor2586 oops! never mind, 2^6 = 64B

[@smitapv8520]

very nice explanation..thank you..

[@akhilalli5332]

Super

[@Gameplay-pq6hk]

sir pls explain once how u are taking 4-4 bytes in one block ? in main memory .

[@nehal2502]

All the sizes are in B - bytes . since main memory is 64 B --- no of bits should be 6+3 =9 . please explain

[@gayathryhari6958]

Thank you

[@anitaafraz8822]

V good teacher

[@user-cm9qb4xy7c]

nice

[@pardhucool209]

Sir,i have a query about the Number of cache lines.
According to me, No of cache lines=No of blocks/Blocksize but you said Cachesize/blocksize.Can you clear my confusion here..??

[@viablevikas2750]

no of blocks is same as no. of cache lines

[@deepachatterjee6001]

Is block and line same ?

[@vinaytigadi7991]

Thx sir, tommorrow is my exam

[@tapanjeetroy8266]

thank you sir...

[@ebertrodrigues]

INDIANO!!!

[@bellekiller]

lol, showing off your tri-cepts

[@gina1525]

REMAINDER OF WHAT

[@rangaraogujja8948]

Hi bro where are u from

[@shwetazala6422]

You should take main memory of 256B. Which gives 64 blacks in main memory and hence address binding of 2bit tag, 2 bit setoffset and 2 bit line offset. With 64B main memory, number of tag bits turns out to be 0

[@jinalpanchal8258]

Either your concepts are not clear or you don't know the proper way of explaining this topic.

[@shivamjalotra7919]

Not good. bakwas. Mapping toh batai hi nahi.

[@gayathryhari6958]

Thank you

[@anitaafraz8822]

V good teacher