Short circuit fault level - Fault current calculation. Tutorial 9

In this tutorial we solve a power system network having a 3 phase symmetrical fault on one of the Bus bar. The Principle approach is to determine the impedance diagram and then use it to apply basics circuit theory to trace the path taken by the short circuit current.
Master the essentials of short circuit fault level calculations in this detailed tutorial. Perfect for electrical engineers and power system analysts, this video provides a comprehensive guide to understanding and calculating the fault levels in electrical systems. Learn the principles, methods, and practical applications to ensure effective and reliable power system design and protection.
Topics in this tutorial include.
- Transmission lines Impedance
- Delta star transformers
- Short circuit current limiting
- Per unit system
- Impedance diagram
🔧 What You’ll Learn:
Introduction to Short Circuit Faults
Importance of Fault Level Calculations
Step-by-Step Calculation Methods
Practical Examples and Applications
Ensuring System Safety and Reliability
📌 Key Topics Covered:
Understanding Short Circuit Faults
Significance of Fault Level Calculations
Step-by-Step Guide to Calculating Fault Levels
Practical Calculation Examples
Application of Fault Level Calculations in System Design
Best Practices for Accurate Calculations
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[@CMTEQ]

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[@domingosmanuel9376]

you are brilliant salut

[@CMTEQ]

Thank you so much 😀

[@domingosmanuel9376]

@@CMTEQ I have a test on those topic and your videos have been helping a lot

[@yusuphataal023]

Your videos are really helpful. Can you please do a video on fault current analysis when the system is loaded. I learned that all what you solving is an unloaded system.

[@CMTEQ]

Hi, thank you for your input, if you are refering to load flow analysis for power system planning, I have those tutorial in the pipeline, stay tuned.
If you want me to assist you with some specific, feel free to contact me privately, or Join my channel membership that way I can release a video for your need.

[@MathiasOzah-wc8mt]

Good day, I noticed when solving for the Xpu(new) of generator G1 the Kvb old and Kvb new was not considered, unlike the formula you stated, could there be a reason for this?

[@CMTEQ]

Hi Mathias, are you enquiring about Zpu(new) = 0.4jpu?
If yes, the values of Vb(old) and Vb(new) where actually used in the formally but they did not affect the answer because they canceled out.
Vb(old) = 13.8kV and Vb(new) = 13.8kV for G1 and T1 calculation.
I hope that clarifies your concern.

[@MathiasOzah-wc8mt]

@@CMTEQ thanks for the timely response, it doesn't really clarify because the Vb (old ) is 13.8 and Vb (new) is 20 as stated, so they don't cancel out

[@CMTEQ]

Hi Mathias, actually Vb(old) and Vb(new) are the same for G1, please watch my earlier video where I only focused on per unit, this video is more about fault calculation.
Sb(new) = 1000MVA, yes it is true the problem statement states that Vb(new)=20kv which actually only apply to G3 zone.
You can not impose a base voltage for the entire system, each zone have its own voltage as you will have Step up and step down transformers along your transmission line.
So, on G1 zone Vb(old) is 13.8kV and Vb(new) =13.8kV you cannot inject another voltage there unless you change the Generator design and its output voltage.

[@MathiasOzah-wc8mt]

@@CMTEQ thanks for the clarification, I'll watch more of your videos for better understanding.

[@user-fr9qn9hn2s]

Good Video, but I have a doubt: G2 is 13.8 kV and T2 is 18/500, if Vbase = 18, then Xg2 would be 0.141, I do not understand why you got 0.24?

[@CMTEQ]

Hi, thank you for spotting the typo.
The parameters for G2 should be : 750MVA, 18kV, Xpu:0.18jpu.
Generator 2 voltage must match the low voltage side of the transformer to maintain the same base voltage on that section, so Vbase = 18kV from generator not 13.8kV.
Let me know if there's amything else you need clarification.

[@mthethowakhentombela8702]

@@CMTEQ thank you

[@CMTEQ]

You are welcome 😊