Not at all... Please watch the video again to understand how I got to the answers. Or watch the entire Playlist to see how I explained the electrolytic cell
Sir I'm a bit confused in why water wouldn't be reduced at electrode q for question9.2 because it's an electrolysis cell and water has a higher E (v) than Sodium
I think you’re referring to the Chloro-Alkali industry. This is the electrolysis of anhydrous Sodium Chloride And Oxygen is produced in the extraction of Aluminium.
Srr Mr Nkosi I am getting confused on your 9.2... the solution is concentrated and aqueous your half reaction for Q is contradicting my understanding because sodium ion is more stable than Hydrogen ion. How can sodium get discharged over hydrogen in a solution? plz help 🙏🙏
You are absolutely correct... I tried to shy away from those details in my expla for this cell but I do provide that detail when I explain the Chloro-alkali industry... Please check out that video for more clarity. However, you are absolutely correct in your assertion.
That 4 cell B hw will u identify which one is cathode and which one is anode what i see is just a DC charge so how will i know which one is which plss🙄
I can't find the video anymore. On that video you said water has a higher oxidizing ability than sodium. This time you're saying sodium will undergo reduction. Why?
For 9.4 for the last one sir may I please ask why (NO3) ^- is not included in the half reaction because when Cu(NO3)2 dissociates it dissociates as shown in the video(like for the first question) . Ngaze nga lost🥺💔. Please do more past papers on this section because I failed it in P2😭💔
Thanks you are the only teacher i understand😊
Thank you... Keep up the good work.
Couldn’t agree more
I couldn't understand a thing in an electrolytic cell, thanks a lot Sir, your videos are very helpful.
You’re welcome ☺️
Am watching from Zambia and I find your videos really helpful
Your literally the best 🥺🥺🥺❤️
You say so... And I'm grateful 🤗♥️
This must be the most followed channel in a day😭👍
We hope it is so…
Your videos are extremely helpful! Keep it up 😁
Thank you for your kind comments
Good way of teaching
For question 9.2. The memo shows a different answer.. they show water as the one reacting
Yes true because they used concentrated NaCl ..I think sir made a mistake there
@lancelotbuthelezi1988 if they say it's concentrated it means we use H20 ?
Its because Na are spectator ions
@@ntokozomahlangu396no,we use it when there is Na
@LihleSiwela how do you notice that Na is an spectator ion?
This really helped my brother, thank you so much
You’re most welcome 🤗
Thank you sir ❤
Sorry sir as for number 9.4 ain’t half reaction for electrode A be that of Nitrate?
Not at all... Please watch the video again to understand how I got to the answers. Or watch the entire Playlist to see how I explained the electrolytic cell
On 9.2 how did the memo come with the answer of water, basically what is half reaction
how would you know which cu half reaction to use ?
if you have time sir , can you please explain :D
Will do,,, For Cu, examiners will indicate. I will explain this well in a video
Sir I'm a bit confused in why water wouldn't be reduced at electrode q for question9.2 because it's an electrolysis cell and water has a higher E (v) than Sodium
The memo even says water so Im not sure
I might have made error there. Thank you for pointing it out
When do you form equations involving hydroxides or oxygen
I think you’re referring to the Chloro-Alkali industry. This is the electrolysis of anhydrous Sodium Chloride
And Oxygen is produced in the extraction of Aluminium.
Hi sir, which Cu do we use because it wasn't clearly stated in this video?
The examiner has to show it somehow.... When in doubt, use Cu2+| Cu half cell
how could you know which cu reaction to use?
There will be an indication
@@MlungisiNkosi okay thanks
Srr Mr Nkosi I am getting confused on your 9.2... the solution is concentrated and aqueous your half reaction for Q is contradicting my understanding because sodium ion is more stable than Hydrogen ion. How can sodium get discharged over hydrogen in a solution? plz help 🙏🙏
You are absolutely correct... I tried to shy away from those details in my expla for this cell but I do provide that detail when I explain the Chloro-alkali industry... Please check out that video for more clarity.
However, you are absolutely correct in your assertion.
Thank you 😊
You’re welcome
So during purification does the colour of the electrolyte change as the impurities fall to the solution?
No colour would occur… oxidation and reduction occur at equal rates
@@MlungisiNkosi OK tnx
❤❤
Thank you sir 🙏💯.sir i have seen in most of previous question papers memos they hydrogen ion instead sodium .WHY
Because there is water… I’ll explain the Chloro-Alkaline Industry
Water is the strongest oxidizing agent than sodium ion. Look at table 4b
-the only problem I have is I don't understand how do we come up with which element is gonna have a +/- (NaCl for ex.). I'm confused sir.
Sorry bout the scratch 😭
Please go to the full lesson first
@@MlungisiNkosi yes sir
That 4 cell B hw will u identify which one is cathode and which one is anode what i see is just a DC charge so how will i know which one is which plss🙄
Sir, What reaction for electrolytic Cell? Exo or Endo...am lost.
Endothermic
@@MlungisiNkosi Thanks
I can't find the video anymore. On that video you said water has a higher oxidizing ability than sodium. This time you're saying sodium will undergo reduction. Why?
I’m not sure I follow. Did you understand the gist of the lesson though?
@@MlungisiNkosi Yes sir!
Water is reduced not sodium ion. Please let's correct.frombtable 4B water is the strongest oxidizing agent than sodium ion.
Is Na gaining electron or loosing electron🤔
Na is always an electron donor,so its loses 1 electron since its in group 1
Sir why do you use Cu* +e- =Cu
Watch the intro you will understand bra
86K🥳🥳🥳🥳🥳🥳
May you please help me get to 100K this year please
Hi sir
Yeyiphi I province lo 2018 andiboni kakuhle?
This DBE
Sir i really didnt understand well im 9.3 can u please explain another way 🙏
For 9.4 for the last one sir may I please ask why (NO3) ^- is not included in the half reaction because when Cu(NO3)2 dissociates it dissociates as shown in the video(like for the first question) . Ngaze nga lost🥺💔. Please do more past papers on this section because I failed it in P2😭💔
NO3- is a spectator ion… It doesn’t undergo any chemical change
Oh😩. Thank you so much
The answer in 9.2 is incomplete we must add (aq) 💓
Kansiime Sharon
U r a start
👍🏽✊🏽
I understand everything until I do a question paper ay it flush all away .
Star
Don't understand a thing here💔😭
Please start with the full content video before watching this.
I think it's because you don't like chemistry or you don't want to understand
Thank you sir🎉