Absolutely! He said at the beginning its like grass grow. But he still does it and continues to which is why its awesome! Thank you for your huge patience!
Thank so much. You make it very simple to understand by going through each step and not just assuming we know the steps. Very informative and a life saver. Keep up the good work and thanks.
I wish I could find you much more earlier to learn everything clearly.Seriously dude you are rock! Unfortunently my exam is tomorrow so I am gonna need luck very much :D Thanks for your clear expression :)
@Gytax0 Systems have either a) No solutions (parallel or skew lines/planes/hyperplanes) (I dont believe is possible in a homogeneous system, since they all pass through the origin), b) One solution (a single intersecting point between lines), c) Infinitely many solutions (either equivalent lines, or the intersection of planes or hyper-planes)
So geometrically (lets assume R3 - my mind cant cope with more dimensions, at least visually) this could be 2 planes that slice through each other with both also intersecting the origin, they have infinite points of intersection along that line (the line is infinite).
what is the reason that we turned this system into RREF from but ones in the previous videos were not? They were upper triangular systems ANybody explains for me?
The variable you make equal to the constant/parameter depends on the number of *non pivot variables* in the matrix (also called the FREE variable, as mentioned in 7:00). That is, all the variables that are NOT associated with a pivot position will be made equal to the constant. This of course means that in some cases, you can get situations where there are multiple parameters (i.e non pivot or free variables) from the matrix when writing out all possible solutions. Note that when we are finding the linear independence of a set of vectors, this situation where we set a variable equal to a constant (e.g x4 = k) ONLY occurs in a *dependent set* of vectors.
Dear profesor ,Thanks to help me for this video could I ask a question ? I think nontrivial solution is: if a lineer algebric system's coefficant matrix determinant is equal zero if the system's rigth sides are NOT zeros can we say it has nontrivial ?
well if lambda is an unknown constant, just combine whatever it was previously into one unknown constant. such as if the last line is b(lamda)x1 + c(lambda)x2 = 0 then set b(lambda) to a value, say r. do everything like said in the video and lambda would equal r/b. hope that helps.
Essentially, yes we do have to calculate rref, unless you choose a different method to solve for each variable. We need the solution to determine if it is trivial or nontrivial one. Note: When there is a free variable (like in this example), you cannot, by definition, use elementary row operations (or any other operation) to calculate the final rref. By definition, Reduced Row Echelon Form, must have a leading entry (1) as the only non-zero entry in its column. Knowing the definition of Echelon and Row Reduced Echelon form is important (esp. if you are studying linear algebra).
variable that is not the leading term of any line, has no relationship to the others, hence that free variable is assigned a free parameter like, when solving you would write: Let x1 = s1, x2 = s2, xn = sn, where s is an arbitrary letter and n is the number of free variables. then you backtrack to solve.
This is late but reduced usually makes it easier and if you have a ti-84 calculator (not sure if the older models do that as well) you can have it solve that matrix for you
Hey I have got a problem, how did you notice that the first can be changed into that? Could someone please explain why? And also "If a linear system has four equations and seven variables, then it must have infinitely many solutions." Is this true or false? Can you exlpain why?
What if the number of variables is greater than the rank of the matrix by 2 (Number of nonzero rows in the echelon form ) in this case I will be having 2 free variables how Can I solve the system in this case?
+TheSummarizer Yes, he is. It's reduced because the pivot entries are 1, and the other entries in the pivot columns are 0. In (row) echelon form the pivot entries can be any number not equal to 0, and only the numbers below the pivot entries have to be 0.
@kai23430 thanks, more linear algebra coming. thumps up if you like them! it helps me : )
patrickJMT = youtube legend...
TheCireMC F**king right.. He is the holy water for the devil math..
He has helped many students pass their math classes
Agree
I have been watching your videos lately, you are a great instructor as you can explain such topics easy and clear. You're amazing.
my pleasure :) thanks for subscribing
Absolutely! He said at the beginning its like grass grow. But he still does it and continues to which is why its awesome! Thank you for your huge patience!
Thank so much. You make it very simple to understand by going through each step and not just assuming we know the steps. Very informative and a life saver. Keep up the good work and thanks.
I wish I could find you much more earlier to learn everything clearly.Seriously dude you are rock! Unfortunently my exam is tomorrow so I am gonna need luck very much :D Thanks for your clear expression :)
12 years and still very helpful!!🫡
THIS GUY ALWAYS COMES CLUTCH !!!
YOU'RE A LIFE SAVER omg thanks a lot man
PATRICK please post about non-homogeneous systems of linear equations also .....thanks
Great Work! You'll be a Professor in no time.
you explained this better in 10 minutes then my prof in 45 minutes
Thanks for the video! Helps a ton!!!
My handout made sense with your tutorial. Thanks 😊
Very well explained! Didn't have to read the book. Thanks a lot! :)
thank you man...wouldn't have understood this for my test without your help. it's just right to appreciate you. God bless you man
Used Khan Academy til I found this. Both were Godsend, but prefer this =) Helping me pass difficult first year Math! Thank you
amazing, i learned in just one session, just subscribed
. thanx
THANK YOU, YOU'RE A LEGEND
Dude you are so much better than my professor!
Wow this video helped me so much. Thanks Patrick
@Gytax0
Systems have either a) No solutions (parallel or skew lines/planes/hyperplanes) (I dont believe is possible in a homogeneous system, since they all pass through the origin), b) One solution (a single intersecting point between lines), c) Infinitely many solutions (either equivalent lines, or the intersection of planes or hyper-planes)
@Gytax0 well, this example did
i love the sound of a sharpie on a fresh piece of paper
Clear and easy to understand. Excellent!
Saved my life
that is the third time i have read that today :)
as i told the other two people: in that case, you owe me one!
Patrick I love you. alot.
6 b 4^&__^???*(&5€_=
Watching grass grow 🤣
Thanks Man
@HaidenDaggett happy to help : )
Excellent explanation! Your videos have helped me from cal 1
THANK YOU SO MUCH!!! I'm not really a fan of my professor's lectures, so this is so helpful!!
very nice tutorial ! Thank you Patrick !
its still hard for me to control the nontrival solutions .
But this video help me a lot!
THX!
thank you
that's so helpful. Much better than my uni 's professor who can barely speak english jesus!!!
This is a good review in linear algebra for me
good work and keep it up :)
very easy and clear
l love your channel it is really a good explanation you are the best
Glad you think so!
Mathematician Patrick SMART thank you
Thank you very much for that awesome video! It helped me a lot! Best greetings from Switzerland :-)
Great work and thanks
So geometrically (lets assume R3 - my mind cant cope with more dimensions, at least visually) this could be 2 planes that slice through each other with both also intersecting the origin, they have infinite points of intersection along that line (the line is infinite).
Thank you sir!
Could you make a video on solving systems of linear equations with parameters in?
Thank you so much
woooow good teacher i had lean a lot
Thanks 😊
what is the reason that we turned this system into RREF from but ones in the previous videos were not? They were upper triangular systems
ANybody explains for me?
subbed and liked. thank you good sir
At 7:17 do you always make x4 equal to a constant or does it depend on the matrix? Thanks
The variable you make equal to the constant/parameter depends on the number of *non pivot variables* in the matrix (also called the FREE variable, as mentioned in 7:00). That is, all the variables that are NOT associated with a pivot position will be made equal to the constant.
This of course means that in some cases, you can get situations where there are multiple parameters (i.e non pivot or free variables) from the matrix when writing out all possible solutions.
Note that when we are finding the linear independence of a set of vectors, this situation where we set a variable equal to a constant (e.g x4 = k) ONLY occurs in a *dependent set* of vectors.
Very helpful! Thankyou!
Thanks for the help
great video
Impressive 👍👍👍👍👍👍
Thanks Good Explanation
Thank you sir 😊
For this video
thanks for your help patrick :)
Thanks for the video! it helps a lot~~~~
good job! bless you!
Great work!! Thank you so muck :$
u deserve 100m
Dear profesor ,Thanks to help me for this video
could I ask a question ?
I think nontrivial solution is: if a lineer algebric system's coefficant matrix determinant is equal zero
if the system's rigth sides are NOT zeros
can we say it has nontrivial ?
What induce you to convert last row to zero, if you lefy non zero elements there, then solution could be trivial, what you say?
Because you are not supposed to leave the numbers like that when they can be reduced to zero maybe?
otherwise its not row echelon form
Did we have to reduce the matrix to RREF or could we have left it at REF?
Awesome!
great... thank you...!
thx a lot that helped..
Hey quick question, can a homogeneous system with a trivial solution also have a nontrivial solution? assuming there are no free varibles
"You can pick your fav value for K, I'm going to pick +1 to make the arithmetic easy" - y you no pick 0 and make it even easier? XD
You can teach math even who has a lower than 70 IQ
Hey Patrick tell me if an unknown constant is given such as lambda in the fourth equation then how to solve it
well if lambda is an unknown constant, just combine whatever it was previously into one unknown constant. such as if the last line is b(lamda)x1 + c(lambda)x2 = 0 then set b(lambda) to a value, say r. do everything like said in the video and lambda would equal r/b. hope that helps.
thanks dude
In this semester , we took four subjects in our math : PDE , Matrices, Complex and Laplace transformation .
We literally die 😭
@xmarin7x ha : )
Thanks :)
thanks😊😊😊😊😊
how to know when to reduce it to row echelon form or reduced echelon form?
thank u sir
when dealing with homogeneous systems, do you have to put it into rref? can't be do the same w ref?
Essentially, yes we do have to calculate rref, unless you choose a different method to solve for each variable. We need the solution to determine if it is trivial or nontrivial one. Note: When there is a free variable (like in this example), you cannot, by definition, use elementary row operations (or any other operation) to calculate the final rref. By definition, Reduced Row Echelon Form, must have a leading entry (1) as the only non-zero entry in its column. Knowing the definition of Echelon and Row Reduced Echelon form is important (esp. if you are studying linear algebra).
since we have the last row = Zeros .. then we can say " inf. many Solutions " , right ?
thanks
making math easy
thanks
doing my best!
What does Choosing the free variable stand for?
you put your pivot variablle in terms of the free variable. The free variable stands for any number
How do you know which variable is the "free variable"?
variable that is not the leading term of any line, has no relationship to the others, hence that free variable is assigned a free parameter like, when solving you would write: Let x1 = s1, x2 = s2, xn = sn, where s is an arbitrary letter and n is the number of free variables. then you backtrack to solve.
This video just saved my ass.
first we have to convert it into echelon form or reduced echelon form?
This is late but reduced usually makes it easier and if you have a ti-84 calculator (not sure if the older models do that as well) you can have it solve that matrix for you
Hey I have got a problem, how did you notice that the first can be changed into that? Could someone please explain why? And also "If a linear system has four equations and seven variables, then it must have infinitely many solutions." Is this true or false? Can you exlpain why?
but what if we pick k=0? wouldn’t that turns out to be trivial too?
How do you decide if it's nontrivial or trivial by inspection only? You have a system, that's it.
If one of the equations can be eliminated by row reduction, then the system of equations was not linearly independent.
What if the number of variables is greater than the rank of the matrix by 2 (Number of nonzero rows in the echelon form ) in this case I will be having 2 free variables how Can I solve the system in this case?
+Amr Wael let one variable equal to some arbitrary constant and then find the other variable in terms of this constant
is k starts from zero?i-e k=o is possible???
Nice
why did not you plug k=0 ?
But if k=0 then wouldn't it be trivial?
nice
is he doing reduced row echelon form?
+TheSummarizer Yes, he is. It's reduced because the pivot entries are 1, and the other entries in the pivot columns are 0. In (row) echelon form the pivot entries can be any number not equal to 0, and only the numbers below the pivot entries have to be 0.
(im here jut for fun)but this looks like matrices on steriods!
long last this video
good job , subscribe :D
is all 0 be one of the solution for this question?
yes! a trivial solution (all zeros) is always a solution to a homogeneous system of equations.
Left hand