homework answer 55:50 : we can make pairs of consecutive terms in sequence (1^2 - 2^2) + (3^2 -4^2)...............(99^2-100^2) this will give -3 -7 -11 -15 .. . . . . -199 as this is an ap so its sum is -5050
When the sum of first n terms of an A.P.'s formula is given in form of quadratic equation in terms of n then it's common difference = 2(coefficient of n²). Hope guys it will help you.
@@Abdul_36638 bhai sir ne 2 ko divide kiya jisse 2a ka 2 cancel ho gaya But sir ka dhyan nahi hoga aur sir ne (n-1)d ko divide nahi kiya jo ki ultimately sir ke equation ke according --- n²d/2 - nd +na ho jata
yes you are right but when the quadratic equation is divided by 2 , which is constant is doesn't matter and dosent change the power of the quadratic equation.
@@shivamarora2969 arre Yaar😂😂....... It means Geometric Progression... Where instead of constant adding you constantly multiply... I hope you get the difference 🙂
sir apki videos me hi mujhe sabse jada maja ata hai after alakh pandey sir, alakh sir hamesha padhate waht hum logo ka dhyen khich lete hai focus karne ke liye and sir aap dhyan bhatane nhi dete "tujhse baat kar raha"," i know tumhe meri baat samajh me arahi hai"," yaha dhyan do"sir mujhe apki ye line badi achi lagti hai sir iske wajah se mera focus bana rehta hai and aisa feel hi nhi hota ki ye ek recorded session hai hamesha lagta hai ki live and aap muhi se baat kar rahe hai
Maine ap gp kuch bhi notes nhi kiya tha...aur ab physics wallah mein sir ne itne acche se samjha diya... Mujhko mere bhaiyya ke alawa aaj tak itni aasani se kisi ne nhi smjhaya,,😭🥺🙌🙌 thnx PW,❤️
*Homework answer* Given series is 1²-2²+3²-4²+....100 terms By grouping the terms,we get (1²-2²)+(3²-4²)+(5²-6²)+..... upto 50 terms (1-4)+(9-16)+(25-36)+.... upto 50 terms (-3(+(-7)+(-11)+..... upto 50 terms Since we can see that, this is an A.P Here,a=-3,d=-7-(-3)=-4,n=50 S=50/2[2×(-3)+49×(-4)] S=-5050 Shayad sahi h sir☹️😅😅
@@OmNamahShivaya810 See friend , The given AP is 1²-2²+3²-4²+....100 terms You make pairs of Two numbers for example ( 1²-2²) and (3²-4²) till ....100 terms So you will end up to 50 pairs , and let first term be (1²-2²) after solving you get common difference as (-4) and then put the valuse in the formula [Sn = n/2{2a +(n-1)d}] and you get the answer which is *-5050*
55:48 ans To find the sum of the given series: 1 2 − 2 2 + 3 2 − 4 2 + … + 9 9 2 − 10 0 2 1 2 −2 2 +3 2 −4 2 +…+99 2 −100 2
We can see that this is an alternating series where each term alternates between addition and subtraction. 1 2 − 2 2 + 3 2 − 4 2 + … + 9 9 2 − 10 0 2 = ( 1 2 − 2 2 ) + ( 3 2 − 4 2 ) + … + ( 9 9 2 − 10 0 2 ) 1 2 −2 2 +3 2 −4 2 +…+99 2 −100 2 =(1 2 −2 2 )+(3 2 −4 2 )+…+(99 2 −100 2 ) We can also see that each pair of terms can be represented as the difference of consecutive squares: 1 2 − 2 2 = ( 1 − 2 ) ( 1 + 2 ) = − 3 1 2 −2 2 =(1−2)(1+2)=−3 3 2 − 4 2 = ( 3 − 4 ) ( 3 + 4 ) = − 7 3 2 −4 2 =(3−4)(3+4)=−7 … … 9 9 2 − 10 0 2 = ( 99 − 100 ) ( 99 + 100 ) = − 199 99 2 −100 2 =(99−100)(99+100)=−199 So, the sum of the given series is the sum of these differences: ( − 3 ) + ( − 7 ) + … + ( − 199 ) (−3)+(−7)+…+(−199) This is an arithmetic series with the first term � = − 3 a=−3, the last term � = − 199 l=−199, and the common difference � = − 4 d=−4 (since each term decreases by 4). We can use the formula for the sum of an arithmetic series: � � = � 2 ( � + � ) S n = 2 n (a+l) Where � � S n is the sum of the series, � n is the number of terms, � a is the first term, and � l is the last term. Now, to find � n, we use the formula for the nth term of an arithmetic series: � = � + ( � − 1 ) � l=a+(n−1)d Substituting the known values: − 199 = − 3 + ( � − 1 ) ( − 4 ) −199=−3+(n−1)(−4) Solving for � n: � − 1 = − 199 + 3 − 4 n−1= −4 −199+3
� − 1 = − 196 − 4 n−1= −4 −196
� − 1 = 49 n−1=49 � = 50 n=50 Now, plugging � = 50 n=50, � = − 3 a=−3, and � = − 199 l=−199 into the sum formula: � 50 = 50 2 ( − 3 − 199 ) S 50 = 2 50 (−3−199) � 50 = 25 ( − 202 ) S 50 =25(−202) � 50 = − 5050 S 50 =−5050 So, the sum of the series is − 5050 −5050.
hw que : -50 1²+3²+5² ------------ 99² is sum of 1st 50 odd no.s i.e n²=2500 -(2²+4²+6²------------- 100²) is the sum of 1st 50 even no.s i.e n(n+1) = -2550 Their sum= -50
G.O.A.T (greatest of all time ) teacher of India 🇮🇳 aman sir. This is my feelings from my heart if anybody have the same feeling for Aman sir please hit the like button
Respected sir The answer of the last homework question is -5050,by taking 1^2-2^2 as one term. n term is 50, a is -3, difference is -4 .I am studying in 8 standard learning 11 physics and maths from physics wallah ,really awesome teaching
****HW**** 1. take first two terms and form an AP __ -3 , -7 ,-11...... ( we can observe that "d= -4" , "a= -3) 2. now that we have took two terms to form an AP , so we have 50 terms now 3. find S^50 to evaluate the first 50 terms we just made and the resulting solution must be *-5050* "25(-202)"
Sir my Answer for the HW qt. is 19900. Sir maine kal raat ko yeh lecture dekha. Phir lecture hone ke baad khana khate khate thoda socha kaise hoga. Par Answer nahi mila. Aaj subah try kiya toh ekdum bhannat🔥🔥🔥 tareeke se solve karne ka method mila...Answer correct ho ya incorrect magar maza bahit aaya!!
Sir in the Sn find ques if we let three terms of A. P be (a-d),a, (a+d) then we easily calculated the value of Sn sir apne hi to padaya tha before lecture me
Sir me apki video jaldi nhi dekh pati hu Mera phone me net nhi he esliya me hamseha picha hi rahti hu 1,2video lakin app ka lecture dekh kar muje padne ka man karta h😃😃😃😃
Physics wallah sir is spreading his army...
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This video is 3 years old still helping students for preparation oF JEE
AT 44:10 the correct ans is n2d/2 - nd/2 + na (b'coz 2a and (n-1)d are two diffrent terms and thus u have to multiply n/2 with both seperatly )
You are right bro but no reply from respectible sir
Yes you are right even I thought this
same here bro i also thought this
Yes u r right and by solving it we will get
2Sn = n2d-nd+2an
Yes
homework answer 55:50 :
we can make pairs of consecutive terms in sequence
(1^2 - 2^2) + (3^2 -4^2)...............(99^2-100^2)
this will give -3 -7 -11 -15 .. . . . . -199
as this is an ap so its sum is -5050
-4^2 = 16 not -16
-2298
babby thats wrong
yes bhai
@@shreyanmohapatra1511 you are wrong. - square se bahar h.
the visualization which he gave for sum of odd numbers was nxt level
When the sum of first n terms of an A.P.'s formula is given in form of quadratic equation in terms of n then it's common difference = 2(coefficient of n²). Hope guys it will help you.
th-cam.com/video/eedlES1B8iM/w-d-xo.html
Thanks
And first term (a) is the sum of coefficients of n^2 and n
Sir samjo ki 63 ka nikalna hai
To ksze
Starts 1:34
Sum of n terms of an AP 7:24
Sum of first N-natural numbers 19:44
Sum of First Even & Odd 21:40
Properties of an AP 29:54
Thanks yr
Thanks bro
Thanks bro
thnx 👍
44:46
Sir it shouldn't be : n²d-nd-an
It should be : (n²d-nd+2an) / 2
Fhir sir ne pehle hi 2 ko divide kue kiye
Nic Bro bit sir just want to convey that it's a quadratic expression.
@@Abdul_36638 bhai sir ne 2 ko divide kiya jisse 2a ka 2 cancel ho gaya
But sir ka dhyan nahi hoga aur sir ne (n-1)d ko divide nahi kiya jo ki ultimately sir ke equation ke according --- n²d/2 - nd +na ho jata
sum of roots taken 2 at a time is _b/a
yes you are right but when the quadratic equation is divided by 2 , which is constant is doesn't matter and dosent change the power of the quadratic equation.
Aman sir is looking like Great Mathematician Ramanujan in his fancy moustache.🔥🙏🏻
Yes👍❤❤
Yeah
th-cam.com/video/2QwXonW_Bs0/w-d-xo.html
th-cam.com/video/GvMtPtnQGdA/w-d-xo.html Alakh Sir on Hud Hud Dabangg 😂😂😂😂
@@sanamaryam690 th-cam.com/video/GvMtPtnQGdA/w-d-xo.html Alakh Sir on Hud Hud Dabangg 😂😂😂😂
At first it seemed like Alakh Pandey(A.P.) Sir's graph of greatness🙏
Same bro❤️
His graph is not A.P, it's G.P.
No bro, that graph is Exponentially increasing 😘😎
@@AAhamed007 GP means great person?
@@shivamarora2969 arre Yaar😂😂....... It means Geometric Progression... Where instead of constant adding you constantly multiply... I hope you get the difference 🙂
I just donno what would I do without this teacher ❤️ please continue these sir
he has left physics wallah months ago
@@aaravbhardwaj261 why
Best teacher and teaching method makes maths a fun in learning
46:20
Yes sir, ab tak ka samajh aa gaya hai ekdam bhannat tariké Se
Arithmetic progression is looking very easy because you Aman sir.😊😊
At 44:10 as n/2 [2a + (n-1)d], here 2a & (n-1)d both are different terms then it will be an + n²d/2 + nd/2 and further simplified. 🤖
Exactly mei bhi itni deerr sei yahi soch raha tha 🤝
I too confused on this time
How interactive sir's lecture is!!! 👍👍👍👍👍👍👍👍👍👍
PHYSICS WALLAH(at door) : Knock knock 😎
VEDANTU : Kon aaya hai.🤔
UNACADEMY : Mai dekhta hu🙄
PHYSICS WALLAH : TERA BAAP AAYA😈😈
@@jiteshbansal4145 yeah bro
But that was just for fun and for appreciating our faculties😎😎
@@hostelers18 o bhai bhai 😂😂😂😂
@@akshay_anand360 😅😅😅
Cutie pie question
Answer: -5050
Can you explain it bro!
@@ShivamKumar_077 bro take a²-b² formula from start and ending you will get the result
Awesome , understand each Nd every concept related to this session 👍👍👍
sir apki videos me hi mujhe sabse jada maja ata hai after alakh pandey sir, alakh sir hamesha padhate waht hum logo ka dhyen khich lete hai focus karne ke liye and sir aap dhyan bhatane nhi dete "tujhse baat kar raha"," i know tumhe meri baat samajh me arahi hai"," yaha dhyan do"sir mujhe apki ye line badi achi lagti hai sir iske wajah se mera focus bana rehta hai and aisa feel hi nhi hota ki ye ek recorded session hai hamesha lagta hai ki live and aap muhi se baat kar rahe hai
Sir Aap or Pandey sir ek dam BHANNAAT GANG
46:23 yes sir all the concepts are clear ❤️
Ya bro
46:00 Sir answer is
S = [5n² - 7n]/4
❤️❤️
Bhai n(5n-7)/4
Aage expand karge toh wahi aayega na 5n²-7n/4
आपके जैसा आसान maths पढाना सबके बस की बात नहीं होती।
Very very thank you sir
Sir poora samagh main aa gya thanks sir😁😉
And by the way nice moustache.
Amazing... Description of arithmatic progression .... Which gives me knowledge and be knowledgble
🙏🙏🔥💥Let's request Alakh Sir and his team for 🔥Accelerate🔥batch 2021for PCM students for IIT JEE 2022🙏🙏💥🔥🙏🙏
Shi hai bhai
Yes
Mail kro
Yes sir plzzzzzzzzzzzzzzzzzzzzzzzzzzz
Yes.......but 2 year course for jee 2023 also
Maine ap gp kuch bhi notes nhi kiya tha...aur ab physics wallah mein sir ne itne acche se samjha diya... Mujhko mere bhaiyya ke alawa aaj tak itni aasani se kisi ne nhi smjhaya,,😭🥺🙌🙌 thnx PW,❤️
In the first n even no.
2+4+6+8.........2n
2(1+2+3+4......n) = 2[n/2(n+1)]
=n(n+1)
Missing those "Note kr liya mitar de" , "Copy or pen nikal lo or chuha khana band kro" , "Turram Turram turr turrr😂😂" .
😂
👌👌👌👌
🤣
Bro dil ki baat boldi tune 🙌🙌🙌
True
Answer of homework question= -5050😊😊😊😊😊
6:39 Agar aman sir ko math me laga daala to life jhingaalaala 😆😆😆😅😂😂😂🤣🤣🤣
Hula lala 😂😂😂🤣🤣🤣 didi
🤣🤣🤣
Are yaar tum teeno hamesha mujhe ek hi comment dikh jata ho😁
@@commentmatkrpadhaikr9922 We are brothers and sisters
@@pratikgoswamiiitbombay8767 yes 🥰☺🤗🤗
H.w question is an decreasing A P
First term = -3
Last term = -199
Total no. Of terms =50
SUM= -5050
(Common difference =-4)
Best teacher for class 11 maths on you tube.
Thankyou sir.. for this nice lecture..
PHYSICS wall change poor family and provide good quality education thanks sir 🙏🙏🙏🙏🏼 🙏🙏🙏 🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼
46:20 yes sir ekdum ache se smjh aa gya
*I just got goosebumps at the starting 😂*
th-cam.com/video/kanKMEiMXX8/w-d-xo.html
@@chhagansuthar2956 sahi batt bro😂
@@arpitaadideo4852 😉😘
sir all properties and all about A.P is clear
Iss safar main sab samajh main aa gaya sir bhannatly!!
*Homework answer*
Given series is 1²-2²+3²-4²+....100 terms
By grouping the terms,we get
(1²-2²)+(3²-4²)+(5²-6²)+..... upto 50 terms
(1-4)+(9-16)+(25-36)+.... upto 50 terms
(-3(+(-7)+(-11)+..... upto 50 terms
Since we can see that, this is an A.P
Here,a=-3,d=-7-(-3)=-4,n=50
S=50/2[2×(-3)+49×(-4)]
S=-5050
Shayad sahi h sir☹️😅😅
Yes -5050 I also got
I too
same answer i got
may I pls know why you grouped and how it became upto 50 terms please
@@OmNamahShivaya810 See friend , The given AP is 1²-2²+3²-4²+....100 terms
You make pairs of Two numbers
for example ( 1²-2²) and (3²-4²) till ....100 terms
So you will end up to 50 pairs , and let first term be (1²-2²)
after solving you get common difference as (-4) and then put the valuse in the formula [Sn = n/2{2a +(n-1)d}]
and you get the answer which is *-5050*
Sir main apki video dekhta hu taki baccho ko prah saku.....Bada maza ata hai....😀😀😀
46:14 sir sb ek dm bhannaaatt tareeke se samajh aa gya ap tension na lo.🥰😀.
Bilkul 🥰
55:48 ans
To find the sum of the given series:
1
2
−
2
2
+
3
2
−
4
2
+
…
+
9
9
2
−
10
0
2
1
2
−2
2
+3
2
−4
2
+…+99
2
−100
2
We can see that this is an alternating series where each term alternates between addition and subtraction.
1
2
−
2
2
+
3
2
−
4
2
+
…
+
9
9
2
−
10
0
2
=
(
1
2
−
2
2
)
+
(
3
2
−
4
2
)
+
…
+
(
9
9
2
−
10
0
2
)
1
2
−2
2
+3
2
−4
2
+…+99
2
−100
2
=(1
2
−2
2
)+(3
2
−4
2
)+…+(99
2
−100
2
)
We can also see that each pair of terms can be represented as the difference of consecutive squares:
1
2
−
2
2
=
(
1
−
2
)
(
1
+
2
)
=
−
3
1
2
−2
2
=(1−2)(1+2)=−3
3
2
−
4
2
=
(
3
−
4
)
(
3
+
4
)
=
−
7
3
2
−4
2
=(3−4)(3+4)=−7
…
…
9
9
2
−
10
0
2
=
(
99
−
100
)
(
99
+
100
)
=
−
199
99
2
−100
2
=(99−100)(99+100)=−199
So, the sum of the given series is the sum of these differences:
(
−
3
)
+
(
−
7
)
+
…
+
(
−
199
)
(−3)+(−7)+…+(−199)
This is an arithmetic series with the first term
�
=
−
3
a=−3, the last term
�
=
−
199
l=−199, and the common difference
�
=
−
4
d=−4 (since each term decreases by 4).
We can use the formula for the sum of an arithmetic series:
�
�
=
�
2
(
�
+
�
)
S
n
=
2
n
(a+l)
Where
�
�
S
n
is the sum of the series,
�
n is the number of terms,
�
a is the first term, and
�
l is the last term.
Now, to find
�
n, we use the formula for the nth term of an arithmetic series:
�
=
�
+
(
�
−
1
)
�
l=a+(n−1)d
Substituting the known values:
−
199
=
−
3
+
(
�
−
1
)
(
−
4
)
−199=−3+(n−1)(−4)
Solving for
�
n:
�
−
1
=
−
199
+
3
−
4
n−1=
−4
−199+3
�
−
1
=
−
196
−
4
n−1=
−4
−196
�
−
1
=
49
n−1=49
�
=
50
n=50
Now, plugging
�
=
50
n=50,
�
=
−
3
a=−3, and
�
=
−
199
l=−199 into the sum formula:
�
50
=
50
2
(
−
3
−
199
)
S
50
=
2
50
(−3−199)
�
50
=
25
(
−
202
)
S
50
=25(−202)
�
50
=
−
5050
S
50
=−5050
So, the sum of the series is
−
5050
−5050.
hw que : -50
1²+3²+5² ------------ 99² is sum of 1st 50 odd no.s i.e n²=2500
-(2²+4²+6²------------- 100²) is the sum of 1st 50 even no.s i.e n(n+1) = -2550
Their sum= -50
29:10 very nice explanation done practically thanks
Using formula (a^2 --b^2) = (a-b) (a+b )
(1-2)(1+2) + (3-4)(3+4) + (5-6)(5+6) ......+ (99-100)(99+100)
-1(3) - (7) - (11) ......- 199
Taking -1 as common
-1 ( 3+7+11+.....199)
Then Sn = - 5050
Hence solved BhannatlY
😊😊😊😊
Good
Your teaching style is amazing sir ❤❤❤❤❤🙏🙏🙏🙏🙏
Sir my answer is -5050 :)
Due to your great teaching I can solve these question while being in 9th
BRO 6TH STANDARD STUDENT HERE
I just born now, I am here now (•‿•)
@@grinjow4u hello from heaven 😌
Bro 7th student
Mai to kg 1 me hu
Welcome alakh sir to Delhi ❤️❤️
Sir in points no 8 . You not divide by 2 in (n²-n)d 44:23
Bilkul main bh yahan confuse hua
Sum of first n- natural numbers
S=n(n+2)/2
Sum of first n- even natural numbers
S = n (n+1)
Sum of first n- odd natural numbers
S = n²
Aman sir is unique mathematician...
Mai vi west bengal ka youngest mathametician hu😊
@@arnabstudy professor Neena gupta ma'am hai😅
God of teaching is back😎
Kon gadhe unlike karte kya malum... Bina dekhe hi like Marne Ka man karta he sir ko😘
46:18 i UNDERSTOOD EVERYTHING SIR.... NO DOUBTS
Best faculty is Mr ⭐⭐⭐⭐⭐
40:54
Sir here we to have write 6 terms but you have only mentioned 5terms .
In this a-3d will also come after a-5d
Hii
Nice 😍
G.O.A.T (greatest of all time )
teacher of India 🇮🇳 aman sir. This is my feelings from my heart if anybody have the same feeling for Aman sir please hit the like button
Now not. !! 😭😭
Thank you so much sir 🙏🏻🤗😎
29:00 box method😍🔥👍
Respected sir
The answer of the last homework question is -5050,by taking 1^2-2^2 as one term. n term is 50, a is -3, difference is -4 .I am studying in 8 standard learning 11 physics and maths from physics wallah ,really awesome teaching
Aur bahi
From were u brings such great teachers alakh sir
Yes
Earth
46:12 Sir ekdum mast samajh mein aaya hai
At 44:10 It Is (+a.n)
Please check the six terms in A.P 🙏
Also bro at 49:40 sir takes -D/a in product of roots whereas it was c/a??
I am very lucky beacause i am studying India's best math teacher.😊
46:20 yes sir A.P. ke sare funde crystal clear hai👍👍
Sir your teaching is just amazing.
55:30 the answer is -5050
Kaise aya can you please help me
mera to -2550 aa raha ahi
aapka kese aaya???
can you explen me
plz......
Yes sir all the concepts are clear....
****HW****
1. take first two terms and form an AP __ -3 , -7 ,-11...... ( we can observe that "d= -4" , "a= -3)
2. now that we have took two terms to form an AP , so we have 50 terms now
3. find S^50 to evaluate the first 50 terms we just made and the resulting solution must be *-5050*
"25(-202)"
Sum = -404 / 404
Cutie pie ans. =-5050 I did it by formula (a-b)(a+b)=a^2-b^2
Sir anwer of cutipie question is -5050 here's the explanation
drive.google.com/file/d/1yKMeAHi_x73lkeDnUSUZsQs_HRjGowDX/view?usp=drivesdk
Thank you sir🙏🏻🙏🏻🙏🏻
I thought that I was starting CARRYMINATI's video
🤣🤣🤣
To kaise he aap log👍👍
Shi entry thi sir ki 😂😂😂
Alakh panday is great teacher
Check property 8 , "dn^2-nd-an" or "na+(dn^2-dn)/2" is true check property numbre 8 again
Sir my Answer for the HW qt. is 19900. Sir maine kal raat ko yeh lecture dekha. Phir lecture hone ke baad khana khate khate thoda socha kaise hoga. Par Answer nahi mila. Aaj subah try kiya toh ekdum bhannat🔥🔥🔥 tareeke se solve karne ka method mila...Answer correct ho ya incorrect magar maza bahit aaya!!
46:04 sir last wale question m a=2 and d=5/2 se bhi sattisfy hora h
agar hum roots ko a-d , a , a+d lenge toh
Question me bola gya hai first 3 term
@@letslearn1086 😉😘❣️
29:06 kya smjhaya sir aapne, bhannat tareeke se smjh aa gyaaa !!!!!
Sir cycle par bike ka majha utha rahe hai🥳🥳😂
Op style "plate ke jore do"👍👍👍
40:45 here it is a-3d
A.P (Alakh Pandey) 😊😊
46:20 .. YES BHANNAT SAMAJ AA RAHA HAI JIII .... EKDAM MAST
Palat gyi guru ji 😂😂❤️
Sir in the Sn find ques if we let three terms of A. P be (a-d),a, (a+d) then we easily calculated the value of Sn sir apne hi to padaya tha before lecture me
But bro usme toh answer different aa rhaa h
I love this chapter in entire syllabus
Sir the answer of Homework Question is = 171700
At last i applied n(n+1)(n+2)/6 and the answer came..!!!
@Amit Kumar bro it will be -5050
55:40 Home work question answer
Sum = -5050
bro isnt it negative
Thanx
Sala lag hei nhi raha hei ki online padh rahe hei pura appna pan wala feeling aa gaya aur phele bar math me maja bhe aa raha hei 😎😎😎💕
Sir I am in class 10 and I understanded this lecture and I love ❤️ it
Thank you sir 🙏🙏
Please visit my channel one time for class 10th 🙏🙏🙏
eyy me tooo man👀💖
@@skepticalpodcasts why???🙂
Kia khubsurat method of teaching hey sir i am from pakitan regularly listening your lecture. God bless you ❤❤
Which competitive exam?
Sir me apki video jaldi nhi dekh pati hu Mera phone me net nhi he esliya me hamseha picha hi rahti hu 1,2video lakin app ka lecture dekh kar muje padne ka man karta h😃😃😃😃
Best explanation ever sir ...thank you so much sir 👍👍👏👏
Nazre badliye , nazare badl jainge👍
answer of the question is -5050
PW all teachers ❣️ are best of one teacher ,now yet pw is best
40:46 Sir ji ' a-3d ' miss hogya
Yes
Don't teach teacher
40:19 sir i didn't understand sixth property of A.P that how did you assumed formulas to get 3 4 5 and 6 terms of AP