Jazakalllah bache..share with all students..also share our online session.for registration to our online google meet classes contact 03339278922 Whatsapp
Assalamualaikum Sir i hope you are fine I have no words to describe your teaching method, but I've learned so much from this channel. Thank you for sharing your knowledge.
Sir g for change in kinetic energy aik formula hy chahiye koii bhi value dii hooo, for increase in kinetic energy due to increase in momentum. We have K.E = 2P+P²÷100 AND FOR DECREASE WE HAVE K.E=2P-P²÷100 SIR G TRY THIS IT WORKS For example agr mcq aisa ho ky THE INCREASE IN MOMENTUM IS 20% WHAT IS THE INCREASE IN K.E SO WE HAVE K.E= 2(20)+(20)²÷100 =40+400÷100 =40+4 =44%
Sir I don't have money to join any mdcat session sir your mdcat leactures give me great support ❤❤❤
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@@afnanbakhtSir how can we get registration.....
Very helpful
Jazakellah sir
A funny and very lovely teacher I've never seen in my life❤love u sir
Sir plz keep it up and upload lecture contiously it is very helpful for us
Respect❤
Jazakalllah bache..share with all students..also share our online session.for registration to our online google meet classes contact 03339278922 Whatsapp
U r really really the great long live sirji..aapki wja se mere physics k problem clear hoe. Khush raho❤❤
Ameen jazakalllah..share our online classes with friends...for registration contact 03339278922
Amazing 😍👌
please sir keep it up ❤
Jazakallah❤❤
King of physics ❤
Mash Allah ❤
The best and greatest teacher ever❤
Assalamualaikum Sir
i hope you are fine
I have no words to describe your teaching method, but I've learned so much from this channel. Thank you for sharing your knowledge.
Walaikum salaam jazakalllah dear
Great Sir
please continues upload the Mdcat lecture it will be very helpful for students
Alot of thanks dear sir ❤
Nice sir
Mashallah...Sir had am pi wakoo
Aw da nor
سر شکریہ ادا کرنے کیلئے الفاظ نہیں ہیں ❤❤
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Sir Mashallah sir MDCAT classes me force and motion kab karoge
Sir g continue da lectures plzzz
Zabr 10
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Sir g . Sequence ke upload kwa videos
Sir bio بھی share krin plz
Sir g for change in kinetic energy aik formula hy chahiye koii bhi value dii hooo, for increase in kinetic energy due to increase in momentum.
We have K.E = 2P+P²÷100
AND FOR DECREASE WE HAVE
K.E=2P-P²÷100 SIR G TRY THIS IT WORKS
For example agr mcq aisa ho ky THE INCREASE IN MOMENTUM IS 20% WHAT IS THE INCREASE IN K.E SO WE HAVE
K.E= 2(20)+(20)²÷100
=40+400÷100
=40+4
=44%
Sir g ocillation chap highly needed
Inshallah it will be done after 1 week in our online mdcat classes on Google meet...For demo class and registration contact 03339278922
Sir why KE depend on velocity square why not velocity cube ?plz explain
Sir where is first lecture ????
Sir all nmdcat lecture share plzz
Feel physics now
sir plz saree mdcat classes add karein plxz sir plz i cant affford the accadmey charges plz asir
Physics Lectures Recorded Hain ? Mujhi Chahye Sir G ? me Kesy Acces Hasil kr skta hu Online
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Da 2 da kam side raga
Sir aap ka WhatsApp no mil sakta hai?
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