Mam first I didn't understand this one but now I understood clearly coming Thursday chemistry public exam so mam you clear my dought in this vedio thanks you mam
Mam தயவு செய்து 11th std book la oxidation number method la .. Evaluate yourself .. Sum podungaa mam 😩😩 Mam sulphur +6 potu As-9 vachu antha sum ma poten .. Ana yenaku kolaputhu... As2S3+ HNO3 + H2O →H3AsO4 + H2SO4 + NO
I'm sorry that I can't fully understand what are you trying to say, so best I can do is balancing the chemical equation for you : 4H2O + 28HNO3 + 3As2S3 -> 9H2SO4 + 28NO + 6H3AsO4
Very well explained mam. Very good effort. Appreciate the handwriting
Poi padi da lussu
mm yes
This is the Best chemistry channel. Hats off mam!!
Mam gain of electro reduction thana
Ama ..... Sis
Yes sis
Amaa
Romba nalla puriyithu
Great job mam...
Please continue your effort mam...
Expecting more video mam...
I could understand this concept very well now. Thankyou for your explanation mam.
Doubtless expaination mam thank you so much
Great teaching keep rocking mam
Very good explanation mam.Thank you !
Mam your teaching skill very good
Super mam I understood clearly
Thank u mam u r the one who is always helps me to understand my concept of learning very well
Thank you mam for your clear explanation.
Vera maaru dedication 🎉
Thanks man super
Hard way of teaching 😅😅😅
Nice explanation thanks mam👍
Thank you Mam 🙂
Thanks mam for teaching us my miss not at all giving like this explanation ❤❤❤
Mam first I didn't understand this one but now I understood clearly coming Thursday chemistry public exam so mam you clear my dought in this vedio thanks you mam
This yearum chemistry exam coming thursday thaan😂
Simple mudunchu pochu i like it 😂
Super mam. Tq
super mam nice explanation
Excellent handwriting
Best explanation. Thank u
Super madam
Clearly understood mam....it's not boring because of your rapid explanation and good editing..... thank you soooooo much 🙏
Mam thank you mam......
.
Thank you so much mam
Very much thanks mam
Excellent work done by you madam we are expecting more solvi problem from you thanks
Is it not necessary on which medium this reaction is happening mam i.e acidic or basic
It is happening in acidic medium only.
Sulphuric acid is given on the reactant side.
@@SDChemistry what should be done for basic medium ma'am?
Thank you mam it is very clear...
Mam 1st KI la eruka I ku -1 poduringa then nxt eruka product side la yen 0 varuthunu doubt ah eruku mam plz clear my doubt
Iodine is formed as product and it is in elemental state. So oxidation number is 0
Thank you mam🙏😊
Thank u sooo much mam❣️🔥
Thank you
Thank you very much mam❣️
Supper very nice
Finally i found it😭😭😭
Cr2 (so4)3 epdi mam
Take cr as x as we know for so2 =-2
2x + 3(-2)=0
2x - 6=0
2x = 6
X=6/3
X=3.
Correct Cr value ana mam
Thank u mam ❤️
Thanks a lot
Very good explanation
Mam please mam you can use black pen only
😮
Mam really good teaching
Even k is getting oxidised why mam u didnt consider that
No...
Oxidation no of K does not change
That's why
Thanks so much mam my name is dhashu 😊
God bless you Dhashu💞🎉🎉🎉🎉💕
Now Iam thoroughly understand😌
Thanks to god because I got a perfect chemistry channel and teacher
Doubt! Athu Y mam 1st step la Ella atom ooda oxidation number neengha 2 aala divide panningha, pannama answer kandupudika mudiyuma🤔
Very nice teaching mam I could understand easily and Ur voice so nice mam
Thanks for putting a video mam
Clear explanation mam 🤗 thank you so much
Super mam ✨😍
Mam தயவு செய்து 11th std book la oxidation number method la .. Evaluate yourself .. Sum podungaa mam 😩😩
Mam sulphur +6 potu As-9 vachu antha sum ma poten .. Ana yenaku kolaputhu...
As2S3+ HNO3 + H2O →H3AsO4 + H2SO4 + NO
I'm sorry that I can't fully understand what are you trying to say, so best I can do is balancing the chemical equation for you :
4H2O + 28HNO3 + 3As2S3 -> 9H2SO4 + 28NO + 6H3AsO4
thanks 😄
Good morning mam .very uesful teaching. Iam soundari tr in theni dt, thank u mam,
So glad to hear...
Thank you so much 🙏
Mam super aa solitharinga
Super mam
6:23 the moment i know the chart color is white .......
EN REACTANT SIDE LA ( i -1) NU IRUKU BUT PRODUCT SIDE LA i is 0
Because adhu element eppomae element oda oxidation number 0 dhan but in reactant side it is KI which is a compound adhanala -1
@@ak57604 THANKS MAM..
@@ritikff3177 hey I am also a student
@@ak57604 sry for bother you...😅... Iam just read the reply from you but i didn't notice your account...so i thought that was the mam who taught...🤝
@@ritikff3177 okay
Means a lot mam❤
Thank you mam
Mam plz clear my doubt mam..
Ungala la mattum than yennoda doubt clear panna mudiyum..😭😭😥🙁😳😩😕
Sure ma...
But please wait...
@@SDChemistry sure mam . I will wait .. Thank you mam for your kindly reply
I don't understand Cr2 (SO4)3
Always SO4 oxidation no - 2 thats it here (SO4)3 so -2 ✖️3 = -6
😊😊
Thanks mam
Ennum easy method solli thaka mam
Mam ennaku ithu konjam purila mam
♥
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Thookam varudhu🥱🥱
Who were in 2024
Waste teaching mam
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Super madam
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Thank you mam
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Thankyou mam 😊❤
Thank you mam
Thank you mam 😊😊😊
Thank you🎉
Thank you mam 😊