In Step 2, you mixed up the value you determined in Step 1 which is correctly 0,276 °C. As a result the amount of NaCl in gramm is 0,141 g in the end. Other than that it's a good video and it helped me a lot to learn and understand tonicity. Cheers, keep up the great work.
You are required to make a sodium cromoglicate ear drop of 60mL. You are provided with the product formula below BP. Product formula: RX Na cromoglicate 1 %W/V Sodium Chloride q.S Purified water a.d to 60 mL Make isotonic solution. Sig. use in the eye Assuming sodium cromoglicate dissociated by 80% and its Zions compound, Sodium chloride has the dissociation factor, i of 1.8 (RMM of Cromoglicate is 172 and for sodium chloride is 58.5) Isotonicity value of NaCl is 0.9%w/v Instructions: Calculate the quantities of the above ingredients and develop your working formula
Hello, the freezing point of NaCl is -0.576 for a 1% solution. So you can use 1% and 0.576 in your calculations. However, 0.9% and 0.52 tends to be used more frequently since 0.9% NaCl solution is isotonic. Hope this helps.
Hi there! thank you very much for your video. It has really helped me with my question... HOWEVER, I've encountered a question which gives me the information of BOTH freezing points of a 1% nacl solution as well as an isotonic question. I'm following every step you have said in the video and I assumed that I ignore the 1% nacl information as it was only added to confuse me. Would you agree? thanks!! (If you're interested, the question is below): you are required to make a 50ml dose of a morphine sulfate 2% solution isotonic. 1% w/v morphine sulfate solution freezes at -0.08oC while 1% w/v sodium chloride solution freezes at -0.576oC and isotonic solution freezes at -0.52oC What is the mass of sodium chloride in mg required to make a 50ml dose of morphine sulfate 2% solution isotonic?
You can use either the 1% w/v and -0.576oC or 0.9% and -0.52oC information for the calculation. So you can ignore the 1% nacl information provided if you used the 0.9% and -0.52oC information for your calculations. I hope this helps.
hello thank you sir for very clear explanation. i d like to ask question but i couldnt understand your e mail spelling so i will ask my question here the dr. in the class gave us question which asks: in which concentration procaine HCl will be isotonic? and her answer was 0.52= x.0.122 = % 4.26 i couldn t understand this will please help me sir? thank you so much
1. It is important to recall that the freezing point depression for an isotonic solutions (e.g., plasma) is 0.52. 2. Now, you will find from tables that the freezing point depression for procaine HCl is 0.122. However, this value of 0.122 is for procaine HCl with a concentration of 1% 3. So to determine the concentration of procaine HCl that will be isotonic you can set up a proportion as follows: ( 1%)/0.122=( y)/0.52; where y is the unknown therefore, y = (0.52 x 1%)/0.122 y = 4.26%
Thank you Humanic Genes for watching and for the comment. You could also use the 0.009 in step 3 instead of the 0.9%. When using that approach, then in step 4 you would multiply the answer obtained in step 3 by the volume and not do the proportion at all. Hope this helps.
Yes. The 100 mL comes from the definition of percentage strength (%). See the percentage concentrations calculations video (th-cam.com/video/rThjXRh7Qtg/w-d-xo.html) for further clarity if needed. Hope this helps. Let me know if you have additional questions.
We know 0.9% of NaCl is isotonic because it has the same osmolarity as bodily fluids. You can verify this using the osmolarity equation. However, it is generally known that 0.9% of NaCl is isotonic and you can find this information in reference books. Hope this helps. Let me know if you have additional questions.
Hi pharmaceutical calculations, I was wondering whether you please have an email I could email you on regarding some calculation questions. I have some topics I don’t understand at university but I’m unsure what the corresponding videos are on your channel. If I send you the questions would you please be able to direct me towards the correct videos/video titles as I’m finding your channel really helpful. Many thanks
Hello Nayla, you may email questions to profmdanquah@rxcalculations.com . Also, check www.rxcalculations.com/video-tutorials/ for most of the videos. Let me know if there are other topics you would like covered as well.
In Step 2, you mixed up the value you determined in Step 1 which is correctly 0,276 °C. As a result the amount of NaCl in gramm is 0,141 g in the end.
Other than that it's a good video and it helped me a lot to learn and understand tonicity. Cheers, keep up the great work.
A slight mistake..0.122×2 gives you 0.244 not the 0.224 used..this helped me alot..thank you
You are correct @user-ol6nn1jx4b. Keep up the good work.
I realy love your chanel its the best on TH-cam a lot of love for you dr
Glad you love the channel. Thank you for watching and for supporting the channel.
You are required to make a sodium cromoglicate ear drop of 60mL.
You are provided with the product formula below BP.
Product formula:
RX
Na cromoglicate 1 %W/V
Sodium Chloride q.S
Purified water a.d
to
60 mL
Make isotonic solution.
Sig. use in the eye
Assuming sodium cromoglicate dissociated by 80% and its Zions compound, Sodium chloride has the dissociation factor, i of 1.8 (RMM of Cromoglicate is 172 and for sodium chloride is 58.5)
Isotonicity value of NaCl is 0.9%w/v
Instructions:
Calculate the quantities of the above ingredients and develop your working formula
The video content is so excellent, congratulations
A mistake in step 2 it is 0.244
Thank you Sulochana for watching and for the comment. You are correct. That is a typo.
thank you so much
Glad you found the video helpful Thelma. Thank you for watching and for the comment.
Thank you :)))))
Thank you for watching and for the comment.
Hi, Thank you very much for these videos!
Just one question: why would you do 0.9%/0.52°C , rather than 0.9%/0.576°C (as NaCl freezes at -0.576°C)?
Hello, the freezing point of NaCl is -0.576 for a 1% solution. So you can use 1% and 0.576 in your calculations. However, 0.9% and 0.52 tends to be used more frequently since 0.9% NaCl solution is isotonic. Hope this helps.
Pharmaceutical Calculations Thank you very much, that really cleared it up!
BRO. 0.520 - 0.244=0.276
Thank you Abhishek for watching and for the comment. You are correct. That is a typo. Welcome to the pharmaceutical calculations community.
Thanks
I need more sample questions for practice
You can find more isotonicity practice questions at www.rxcalculations.com/isotonicity-calculations-practice-quiz/
Hi there! thank you very much for your video. It has really helped me with my question... HOWEVER, I've encountered a question which gives me the information of BOTH freezing points of a 1% nacl solution as well as an isotonic question. I'm following every step you have said in the video and I assumed that I ignore the 1% nacl information as it was only added to confuse me. Would you agree? thanks!!
(If you're interested, the question is below): you are required to make a 50ml dose of a morphine sulfate 2% solution isotonic. 1% w/v morphine sulfate solution freezes at -0.08oC while 1% w/v sodium chloride solution freezes at -0.576oC and isotonic solution freezes at -0.52oC
What is the mass of sodium chloride in mg required to make a 50ml dose of morphine sulfate 2% solution isotonic?
You can use either the 1% w/v and -0.576oC or 0.9% and -0.52oC
information for the calculation. So you can ignore the 1% nacl information provided if you used the 0.9% and -0.52oC information for your calculations. I hope this helps.
@@PharmaceuticalCalculationsEasy did indeed! cheers
hello thank you sir for very clear explanation. i d like to ask question but i couldnt understand your e mail spelling so i will ask my question here
the dr. in the class gave us question which asks: in which concentration procaine HCl will be isotonic? and her answer was 0.52= x.0.122 = % 4.26 i couldn t understand this will please help me sir? thank you so much
1. It is important to recall that the freezing point depression for an isotonic solutions (e.g., plasma) is 0.52.
2. Now, you will find from tables that the freezing point depression for procaine HCl is 0.122. However, this value of 0.122 is for procaine HCl with a concentration of 1%
3. So to determine the concentration of procaine HCl that will be isotonic you can set up a proportion as follows:
( 1%)/0.122=( y)/0.52; where y is the unknown
therefore, y = (0.52 x 1%)/0.122
y = 4.26%
+Pharmaceutical Calculations 0.52 degrees / 0.122 degrees = the number of percent solution of procaine HCl to yield freezing point depression of 0.52
Sir am little bit confused on 0.9% cause our lecturer changed it to 0.009 and in your videos you were just using it direct......
Thank you Humanic Genes for watching and for the comment. You could also use the 0.009 in step 3 instead of the 0.9%. When using that approach, then in step 4 you would multiply the answer obtained in step 3 by the volume and not do the proportion at all. Hope this helps.
What is freezing point depression of oxymetazoline hcl
freezing point depression for a 1% solution is 0.12
Is that 100ml in the ratio and proportion set up constant?
Yes. The 100 mL comes from the definition of percentage strength (%). See the percentage concentrations calculations video (th-cam.com/video/rThjXRh7Qtg/w-d-xo.html) for further clarity if needed. Hope this helps. Let me know if you have additional questions.
Pharmaceutical Calculations
thanks this helps me a lot. ☺
Hi can you make videos on parenteral and enteral nutritions as well as TPE calculations please huhu
Thanks for the feedback. Sure, I will make some videos on parenteral nutrition.
Pharmaceutical Calculations thanks a lot!!
hello Dr. i would like to know how we figured out that 0.9% of NaCl is isotonic, is that also given in tables?
We know 0.9% of NaCl is isotonic because it has the same osmolarity as bodily fluids. You can verify this using the osmolarity equation. However, it is generally known that 0.9% of NaCl is isotonic and you can find this information in reference books. Hope this helps. Let me know if you have additional questions.
Pharmaceutical Calculations thank you so much!
In first step you value come 0.244 and in second step it become 0.224 how plz just checked the video and make it correct but good
Thank you for watching and for the feedback.
Hi pharmaceutical calculations, I was wondering whether you please have an email I could email you on regarding some calculation questions. I have some topics I don’t understand at university but I’m unsure what the corresponding videos are on your channel. If I send you the questions would you please be able to direct me towards the correct videos/video titles as I’m finding your channel really helpful. Many thanks
Hello Nayla, you may email questions to profmdanquah@rxcalculations.com . Also, check www.rxcalculations.com/video-tutorials/ for most of the videos. Let me know if there are other topics you would like covered as well.
Hi sir I did email but received no response unfortunately :(
Are you from Nigeria
no hes ghanaian
is it 0.122 or -0.122??????
the freezing point is -0.122 but the freezing point depression is 0.122 (i.e., 0 - (-0.122)).
Here because of L
make calculations correct....
Take down this video, too many errrors
Thank you Yayra for watching and the comment.