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i mean dis in da best way...u sound like dwight schrute but also tyvm v helpful 😁
Very clearly explained this better than my own teacher thanks!!!!!
Lmao my life is much clearer thanks to you. No more suicidal thoughts💭
Same.
Lol same
Excellent video
I am indian watching this ,,helpful
thank you very much sir, this helped me dismiss my confusion of the quadratic recipricols
reet
Very thorough explanation. Helped me understand the concept a lot better
How did he know that the two ones on the right and left don't approach 0? I thought the horizontal asymptote of the whole function would be -1/4.
You could only get a horizontal asymptote of -1/4 if the original function also had an asymptote of -4, which isn't the case.
Thank you very much, very clear and easy to understand!
Shouldn’t Y
Thank you sir
why did you not find the zeros in the second example?
No zeros, since it doesn’t cross the x axis
At like 6.10 min why isnt there another y asymptote =-1/4 because of negative part of the function?
Hi mr. Brian
thank you mister
You literally saved my life. Thank you so much.
Thank you for your video
Fat. . . Blunt. . . Hahaha. . . In all seriousness, thanks. This helped with my Calculus20H final.
c
this helped so much!So clear, I get it now
Thank you so much.
THANKKK UUU SM
Thanks!
Gosh the voice though
Very helpful, thank you!
King
very helpful, thank you so much!
love you
so helpful thank you!
Helpful but you should play it at 1.5 speed lol. It's kind of slow.
chirtd
i mean dis in da best way...u sound like dwight schrute but also tyvm v helpful 😁
Very clearly explained this better than my own teacher thanks!!!!!
Lmao my life is much clearer thanks to you. No more suicidal thoughts💭
Same.
Lol same
Excellent video
I am indian watching this ,,helpful
thank you very much sir, this helped me dismiss my confusion of the quadratic recipricols
reet
Very thorough explanation. Helped me understand the concept a lot better
How did he know that the two ones on the right and left don't approach 0? I thought the horizontal asymptote of the whole function would be -1/4.
You could only get a horizontal asymptote of -1/4 if the original function also had an asymptote of -4, which isn't the case.
Thank you very much, very clear and easy to understand!
Shouldn’t Y
Thank you sir
why did you not find the zeros in the second example?
No zeros, since it doesn’t cross the x axis
At like 6.10 min why isnt there another y asymptote =-1/4 because of negative part of the function?
Hi mr. Brian
thank you mister
You literally saved my life. Thank you so much.
Thank you for your video
Fat. . . Blunt. . . Hahaha. . . In all seriousness, thanks. This helped with my Calculus20H final.
c
this helped so much!
So clear, I get it now
Thank you so much.
THANKKK UUU SM
Thanks!
Gosh the voice though
Very helpful, thank you!
King
very helpful, thank you so much!
love you
so helpful thank you!
Helpful but you should play it at 1.5 speed lol. It's kind of slow.
chirtd