Reciprocal Functions - Basic Introduction
ฝัง
- เผยแพร่เมื่อ 4 ก.พ. 2025
- This algebra video tutorial provides a basic introduction into reciprocal functions. It explains how to graph them using the vertical and horizontal asymptotes.
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What is the differentiation of y=1/{(3t²)^⅓(t-1)½}
Hmm, before I say anything I’d say that your question perhaps has some ambiguity, for you most likely mean 1/(3t^2)((t-1)^(1/2)), and for that the answer would be ((-6t^3)(t-1)^(-1/2))-((1/2)((3t^2)^(-1/3))((t-1)^(-3/2))), but technically it really is 1/((3 times t^2) to the power of (1/6)(t-1)), therefore we would have to use logarithmic , then getting an horrifying answer of (1/(18t))((t-1)^2)(ln(3t^2))+(1/36)(t-1)((ln(3t^2))^2), I’d say those are completely different answers, so could you be a little more specific please?
good video
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