Sir you are the bestest teacher i have ever found in my life. And your quality of teaching is excellent. Sir please don't get disheartened by someones bad comment.
wait so if we have infinite letter(tending to atleast)we send them randomly hence we have n! ways then the number of ways we mess up so bad that no one get their letter is 1/e??? cause that would be e^-1 's expansion
Sir in envelope question Why cant we choose 1 number out of 5 number and do the derangement of remaining 5 digits but in that case the answer will be different why???
Derrangement means none of the elements is in its original position. When we put card 1 in envelope 2, the remaining 5 elements has derrangement 5!(1 - 1/1! + 1/2! - 1/3! + 1/4! - 1/5!) = 44. But when we calculate this we assume that original position of card 2 is envelope 1. Now in derrangement we have 5 cards and correspoding 5 envelopes and derrangemnt formula works when we have n elemnets and exactly n corresponding place for them. But cards are 2, 3, 4, 5, 6 and envelopes are 1, 3, 4, 5, 6. If we use the derrangement of 5 elements then we have assumed that original position of card 2 is envelope 1. So, in this derrangement answer (44) those only those cases are counted in which card 2 is certainly not goining to envelop 1, which we have considered its original location in the ansewr 44. So, we have to consider those cases when card 2 goes to envelope 1. Then we have derrangemnt of four elements, which is 9. So, actual answer is 44 + 9 = 53.
nakul sindhwani I think your rank must be within 40000 This is not that good but even not so bad. Have u taken Bits test? That is also good option. There is big list of colleges just below some IITs. If u get somewhere u should take it. Dropping is not bad idea but then u have to be ready for desperate performance. If u r confident and can take that challenge u can drop. We don’t know what destiny has decided for us.
Sir how did u deduced this part.......that no.of permutation in which atleast one element is in its original position is equal to n(A1U A2 U A3 U A4......U AN)....SIR PLZ HELP
Sir why haven't you included chapters: sets and relations in calculus book? I know they are basic chapters but need some good practice first . Thanks!!
Sir i want to Buy Your Trigonometry Course available on cengage platform , i am amazed by your teaching , But plz tell that will i be able to watch lectures on my laptop , Or only on Cengage Mobile app ??
Cengage Digital app is also always for windows version. Install the windows application and you can easily watch videos in the windows app on your laptop. The windows application can be downloaded from www.cengage.co.in/cengagedigital
When I had started it my Aim was Getting into IITS,
Now, My Aim is to achieve Excellence in mathematics like Sir.
Sir you are the bestest teacher i have ever found in my life. And your quality of teaching is excellent. Sir please don't get disheartened by someones bad comment.
Sir your books from cengage are just awesome. Specially the book of co ordinate is just awesome. Thanks for helping us in maths
the production setup is just amazing
This class is so helpfull and clear that i have now seriously gained alot of confidence on this topic. Thankew sir for ur kind efforts. 🙏🙏🙏
Patiently explained. Continue the lectures you are helping a lot of people.
Dear Sir aapse pyar hogya........aap humesha khush rahe ... U. R a true legend
You are precious sir
Jewel of mathematics
difficult topic can change to easily possible only one person tewani sir .
Excellent explanation...selection of the questions is too good...tnq u so much sir....
Thank u sir do continue these lectures
You really aced it sir.Simply superb
Thanks sir is topic pe hi mujhe kaafi doubt tha. Now i am able to solve problem on this topic
Sir you and your book is to the point and best.
Sir can you please explain circlular permutations
The Best Teacher For JEE Maths in the world..
Thank you, it was very clearly explainded.
Thanks a lot sir I become confused in this but you make easier
A legend 😍
wait so if we have infinite letter(tending to atleast)we send them randomly hence we have n! ways then the number of ways we mess up so bad that no one get their letter is 1/e???
cause that would be e^-1 's expansion
Avi bro
Sir how do you make these type of transparent board teaching videos
Sir, I want to buy your video lecture.
Call : 7814166606
Sir you are the god father of mathematics.
sir really enjoyed it.😊
In the function q 6c6 has 0 dearrangement then why did u add it?
awesome explanation...thank you
I want to be just as you sir!
Jee main ke liye to bohot channels hai including sir's but jee advance ke liye he is the best
i prefer mohit tyagi
Thank you Sir!!
Sir please make one vedio on multinomial theorem
Nice and conceptual video
How this technology is working ?
Ai should be number of permutations in which i elements are in its original position
Sir Can we write D(n) = (n ! ) .e^(--1) when n approaches infinity ? DrRahul Rohtak
@@jdeep7 थैंक्स
Sir please upload more such videos 🙏
Sir pls video upload katre rehna
Cengage hai mere paas maths ki❤️❤️❤️sir ki book😎
Love from Bangladesh!!
best hai sir thanksss a lot
Sir in envelope question
Why cant we choose 1 number out of 5 number and do the derangement of remaining 5 digits but in that case the answer will be different why???
Ananya Mahato
Let me reply in sometime
Ananya Mahato
Can u explain a bit in detail
Sir i mean if 1 is always with 2 then can the remaining digits 2,3,4,5,6 can be deranged with derangement of 5 and 1 with 2 is chosen in 5c1 ways
Derrangement means none of the elements is in its original position. When we put card 1 in envelope 2, the remaining 5 elements has derrangement 5!(1 - 1/1! + 1/2! - 1/3! + 1/4! - 1/5!) = 44. But when we calculate this we assume that original position of card 2 is envelope 1. Now in derrangement we have 5 cards and correspoding 5 envelopes and derrangemnt formula works when we have n elemnets and exactly n corresponding place for them. But cards are 2, 3, 4, 5, 6 and envelopes are 1, 3, 4, 5, 6. If we use the derrangement of 5 elements then we have assumed that original position of card 2 is envelope 1. So, in this derrangement answer (44) those only those cases are counted in which card 2 is certainly not goining to envelop 1, which we have considered its original location in the ansewr 44. So, we have to consider those cases when card 2 goes to envelope 1. Then we have derrangemnt of four elements, which is 9. So, actual answer is 44 + 9 = 53.
Ghanshyam Tewani JEE Maths Video Lectures Thank you sir for the explanation
Lajawaaaab sir
sir jee advance waale ques me 5 times nhi keval 5 number jayada tha na toh minus kr dena tha usme
Sir you are awesome
Great sir
Sir isnt recursive method easier for formula of Dn?
Sir I didn't do well in jee advanced
Should it take a drop and try again or else go to some low ranked college
Pls help
nakul sindhwani
How much u scored in jee main and where u were taking coaching?
Sir i scored only 122 marks
I was in vmc dwarka
nakul sindhwani
I think your rank must be within 40000
This is not that good but even not so bad. Have u taken Bits test? That is also good option. There is big list of colleges just below some IITs. If u get somewhere u should take it. Dropping is not bad idea but then u have to be ready for desperate performance. If u r confident and can take that challenge u can drop. We don’t know what destiny has decided for us.
awesome videos you are the best teacher in the world
2014 agar ham esa soche ki 1 already put in 2 now derrange of 5 which 44.. What wrong with it??
Sir in envelope ques 265/5=53
Sharda Pathak
👍
Sir, I am curious to know how you make this videos? Which software you use
Science for Students is just a glass on which he writes, this method is used in foreign too..
Thanks I had a doubt too.
Tell me too
i didnt understand that why in the second quest did you divide 265 and 5 ...
sir i want to meet you first and then want to buy your lectures.. is this possible?
Sir how did u deduced this part.......that no.of permutation in which atleast one element is in its original position is equal to n(A1U A2 U A3 U A4......U AN)....SIR PLZ HELP
Pls also explain logically why are we actually using Inclusion exclusion principle.
thanxxx sir for give me great learning
How is sir writing backwards?????
Camera trick bro
Sir why haven't you included chapters: sets and relations in calculus book? I know they are basic chapters but need some good practice first . Thanks!!
Nachiket Kanore 👍👍
Sir i want to Buy Your Trigonometry Course available on cengage platform , i am amazed by your teaching , But plz tell that will i be able to watch lectures on my laptop , Or only on Cengage Mobile app ??
Cengage Digital app is also always for windows version. Install the windows application and you can easily watch videos in the windows app on your laptop.
The windows application can be downloaded from www.cengage.co.in/cengagedigital
@@gtimeducation ok sir thank you so much 🙏
sir please make more videos please
your teaching is perfect but there's a mistake in atleast 3 self images problem as that would be 95 sir
Sir aap se badhiya teacher aaj tak maine nahi dekha.
Answer is 53
Sir will you teach me know....?...I am a dropper ..??
For jee 2021
This topic came in jee advanced 2018
Abel C Dixon
It is jees favourite topic
Sir plz do not waste time in changing marker
Plz use only one marker
Correct i totally agree
It helps to make us understand and make the lecture interesting.
Sir ek request hai pls thoda smile karke padhaiye itni seriousness nai rakhni chaiye 😅