dear sir your videos are really great and helps in understanding, but when we open the question everything seems as they are very complicated so I request you if you may please upload typical examples and how to solve them, it would be a great way then to understand
Doubt:- @7:03 Given as (-1,0) U (0,-1). Which is not correct. Then replaced Symbols in Video Description UNION-U with Intersection and -1 with +1 :- (-1,0)^(0,1). But intersection only gives common value So, only value 0 But not other +ve or -ve values + 0.1,0.2,0.3...+0.9 or -0.1,-0.2,-0.3...-0.9. Hoping operation symbol might have to be ∆ A∆B = AUB -A^B So, (-1,0)∆(0,1) ^ means Intersection. If Any mistake kindly correct me.😉
Case 2, I don't understand. why have you multiplied by 0.5 and then divided by 0.5 this is the same as multiplying or dividing by 1. why not just multiply by 0.5 and get the 4 initially? Is it something that will become more relevant when things get complicated and you have to isolate t before you can divide by it alpha?
In the example for |a|>1 you have assumed x(t)=0 for t not in interval [0,2]. When you explain about x(2t) you have made function value 0 after t=1 while it has to be 0 after t=2. What you have told can happen only when x(t) is original signal. Please do make it clear.
divide domain in original ex. by alpa as he said , when you divide 0/2 you get 0 and when divide 2/2 you get 1 ...this the method as he said , note : we make time scaling so time should be changed .
Sir, may I ask what book are you using in this lecture? I know in your analog electronics playlist uses the Boylestad book and it really helped me follow through the lesson. It would be highly appreciated if you provide the textbook for this lecture. Thank you
In case-I you showed us what will be the graph if we take the value for t=0 and t=1. But the value of t=2 also. Then what will be the graph if we take the value for t=2?
in the case I ,signal is defined at x=0 and x =2 but in the case 2 , signal is defined at x=0 but how it is defined at x =1 rather than at x=2. on wat basis x=1..
Did somebody noticed that the ∪ in α ∈ (-∞,-1)∪(1,∞) kept changing to ∩ again and again throughout the video, why is this happening? can somebody explain?
does anyone know what is the book's name or author of the book that the video is saying towards the end of the video? video+book in front of me would be the ideal combination :)
Why is he dividing by alpha? Not clearly understood Also, in example two, if alpha is not equal to zero, how does it belong in (-1,0) U (0,1)??? doesn't make sense
Mod Alfa is greater than zero only when alfa is not equal to zero right...for the union of two given sets gives all values expect zero for alfa... Then both are same right...
I love people who write "x" like two letters c, and number "1" is in a full way, not just a stick. Very few people do that.
Koi sense h es baat ki?
I will do like that only... 😅😅😅
@@amankumargiri3163 ??
@@Noble_Isaac he is asking in a humorous way that this thing has any sense?
@@nitigyajoshi4658 tum to bade heavy explainer nikle 😂😂
The lecture is very nice, only point I think will make this videos to next level is, Telling why this concept is important and practical application
Love how you explain the topics and repeat what u just said to reinforce us , just as good if not better than my college professor 👍🏽
dear sir your videos are really great and helps in understanding, but when we open the question everything seems as they are very complicated so I request you if you may please upload typical examples and how to solve them, it would be a great way then to understand
Your explanation is too good sir😃😎
Doubt:- @7:03 Given as (-1,0) U (0,-1).
Which is not correct.
Then replaced Symbols in Video Description UNION-U with Intersection and -1 with +1 :- (-1,0)^(0,1).
But intersection only gives common value So, only value 0 But not other +ve or -ve values + 0.1,0.2,0.3...+0.9 or -0.1,-0.2,-0.3...-0.9.
Hoping operation symbol might have to be ∆
A∆B = AUB -A^B
So, (-1,0)∆(0,1)
^ means Intersection.
If Any mistake kindly correct me.😉
In the first case why we find the amplitude at t=1 and not at t=2
cuz you make 0
Bcz we can't change the original signal so we want amplitude 2 so by which value multiple to get 2 that t=1
ty i was also confused
@9:18 sir can you explain that for case ii, the x(t)=0 when t=0 ,still you've plotted x(t)=2 when t=0 kindly exp thtin case kf expansion i.e. case ii)
first case divede and second case multiply. got it
2:34 the plot shouldn't have the vertical line at t=2. Correct me if iam wrong?
Thank you for the video.
On what basis did u take t=1 for the 2nd graph sir??
exactly same doubt i too have
By dividing it with (alfa=2)
Loved it!!!!
it will be still better if you take examples of discrete time signals also
Its good to have straight A's.
4:27 why were you trying to find x(2) at time=1?
thanks dear sir
21 hours before my endsem exam I'll complete the playlist today before that
How did you do? :)
@@aaronsandlin6277 I did complete it. Still got c+.
i don't understand how to get the range of alpha?
How this set declarations are made at 7:03
Sir pls explain about time scaling for discrete signal.
Which text book is more preferable to u'r lectures
It will be far better if you teached us why we do time scaling
7:15 how is it 0, -1? it should be 0, 1 right?
I didn't get the case 2
can you explain the case 2 as you explained case 1??
Brilliant
thanks for making so many useful lectures...could you make time scaling for discrete signal ? request...:)
Case 2, I don't understand. why have you multiplied by 0.5 and then divided by 0.5 this is the same as multiplying or dividing by 1. why not just multiply by 0.5 and get the 4 initially? Is it something that will become more relevant when things get complicated and you have to isolate t before you can divide by it alpha?
Sir in the 1st case why you took t=1 instead of t=2 to find the amplitude
How do you solve this, for t = -3 and t =+3 plot the signal of x(t)=t^2+3 and x(t)=2t?
I watched it..
In the example for |a|>1 you have assumed x(t)=0 for t not in interval [0,2]. When you explain about x(2t) you have made function value 0 after t=1 while it has to be 0 after t=2. What you have told can happen only when x(t) is original signal. Please do make it clear.
Tutorial point much better for signal system
Thanks...super
In case 1,why did you take only till t=1 in the terms of the x(2t), why not till t=2?As the range of t was from 0 to 2.
divide domain in original ex. by alpa as he said , when you divide 0/2 you get 0 and when divide 2/2 you get 1 ...this the method as he said , note : we make time scaling so time should be changed .
@@RahmaElsaeed-cf6ru perfect man
thx man
Sir, may I ask what book are you using in this lecture? I know in your analog electronics playlist uses the Boylestad book and it really helped me follow through the lesson. It would be highly appreciated if you provide the textbook for this lecture. Thank you
Idk if it helps now but you can use this book called 'SIGNALS AND SYSTEMS' by A.Anand Kumar. Cheers!
In case-I you showed us what will be the graph if we take the value for t=0 and t=1. But the value of t=2 also. Then what will be the graph if we take the value for t=2?
Safayet Islam for t=2
x(2.t)=x(2.2)=x(4)=0
and similarly amp. of x(2t)=0 for all t1
@@EmManuel-xw4xp thank you brother. 💯
Thank you
Thank you so much about the lesson
in the case I ,signal is defined at x=0 and x =2 but in the case 2 , signal is defined at x=0 but how it is defined at x =1 rather than at x=2. on wat basis x=1..
Rohit Kumar yes i am also so much confused
in the second case how have you taken the value of alpha to be 0.5?
I have a doubt in case 2 that y don't u multiply 2 nd 0 with alpha i.e 0.5 as u wrote the formula as alpha multiplied with t nd whole div by alpha
Can someone explain me on what basis we select the alpha value?
He's taking random values, according to the two cases obviously
in the first case you multiplied 2*0 how come you got 2 instead of 0?
What about signals like x (2t-1)
Did somebody noticed that the ∪ in α ∈ (-∞,-1)∪(1,∞) kept changing to ∩ again and again throughout the video, why is this happening? can somebody explain?
There is a slight mistake in the set declaration in case II
how do you find alfa ?
sir i didn't understand second one and range of alpha is not clear
How to get the notes any one tell me??
sir expansion wale main apne aplha*t/alpha likha hai. phir sir apne 0.5/0.5 yeah kha se aaya.sir yeah topic thorda dubara karwado bahut se doubt hai.
does anyone know what is the book's name or author of the book that the video is saying towards the end of the video? video+book in front of me would be the ideal combination :)
Book Name - Signals and Systems
Author Name - Aanand Kumar
3rd Edition
Speed thoda kam रखो definition ke sath vedio laya kro.
case i: [alpha]>=1 ?? or is there right?
if alpha equal to one .. this won't be any time scaling
if alpha is less than 1, we cant take values like -2,-3 etc
it is mod of alpha
is it sufficient for gate ee
union sign to intersection and again to union ......hmmm
No compression sir....
U hav just taken till 1......after scaling
How to find alpha can you please tell me
Saurav Sikarwar the no. which is scaled to time t is alpha itself except no.0
and |alpha|>1 for compression of time signals and |alpha|
Why is he dividing by alpha? Not clearly understood
Also, in example two, if alpha is not equal to zero, how does it belong in (-1,0) U (0,1)???
doesn't make sense
Alfha is assuming air
I did not understand the second case
I think its wrong
in case2
(-1 to 0) U (0 to 1) aayega
which book you use in this video
Who is the teacher here
It's not clear 😕 😢 😔..not in clear
why do we need time scaling in real world?
Did nt understand the second case
This is little complicated
How that |α|>1 can be written as α€(-infinity, -1)u(1, infinity)
Mod Alfa is greater than zero only when alfa is not equal to zero right...for the union of two given sets gives all values expect zero for alfa...
Then both are same right...
Jor se bola. Kar bhai koi galat kaam thodi karra hai tu
Sir alpha 2 kg Liya hai