Your explanation was very smooth and I applaud you for not removing obvious reductions such as the divide by 2 early on, and keeping to the path of most resistance. The checking/conformation of your value for k was also very good. I do hope that many young people get to watch your channel, and not just old guys (I'm 60) like me. Thank you.
Your explanation was very smooth and I applaud you for not removing obvious reductions such as the divide by 2 early on, and keeping to the path of most resistance. The checking/conformation of your value for k was also very good. I do hope that many young people get to watch your channel, and not just old guys (I'm 60) like me. Thank you.
Glad you liked it! It's good to keep students engaged.
way way overcomplicated
Why Log10 not replaced by 1
Yes, that was an option.....
k=1+1/(log9)
k=1+1/log(9), dis one result, or k=1+log9(10), 9 is base off log. Dis more simple den your solution?
way too complicated. k=[1+Log(9)]/Log(9)
K=ln90÷ln9=2.045
9^（k-1）=10
(k-1)=1/log(9）
k=1+1/log(9)
k=1+1/2log(3)
much easier