Just a thought of mine, E2 reactions are also favored if the base is large and the steric hindering prevents a direct E1 reaction, at the same time. Moreover SN2 reactiosn are also very unlikely to happen nor an SN1 due to that fact.
For the first E1 reaction wouldn't in this case E1 actually be the major product and the SN1 the minor since you have heat (the delta symbol) present in the reaction? Great videos by the way and I wish we had more professors like you. Thank you.
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No it wasn't due to inversion - it was just re-drawing the exact same molecule in a different way so that it would end up looking just like the alkene above it (top right)
E1 should be major and SN1 minor, because you added heat/delta. If you hadn't added heat/delta, then SN1 would definitely be major. Apart from that this is a great video. thanks
It's when the two biggest groups are furthest away from each other. I think it's only when you look at it under the Newman projection. All I could remember is that it's the most stable as there's the least serif strain. plz correct me if I'm wrong.
Only for alcohols, because the OH is not a good enough leaving group by itself - it must be treated with acid to make OH2+ . On the other hand halides like Cl, Br, and I will leave by themselves without acid
The dehydrobromination of isopropyl bromide requires several hours of reflux with alcohol KOH whereas in t.BuO-K+ / DMSO, dehydrobromination can be carried out in less than a minute at room temperature. Why this is so?
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Great teaching and clear handwriting. You, sir, deserve a cookie
Indeed and you actually deserve a heart from the uploader.
Just a thought of mine, E2 reactions are also favored if the base is large and the steric hindering prevents a direct E1 reaction, at the same time. Moreover SN2 reactiosn are also very unlikely to happen nor an SN1 due to that fact.
forever greatful! with your intuitive and easy to grasp form of teaching. Much appreciated :)
For the first E1 reaction wouldn't in this case E1 actually be the major product and the SN1 the minor since you have heat (the delta symbol) present in the reaction? Great videos by the way and I wish we had more professors like you. Thank you.
Yeah, I believe he made a mistake there. Once heat is added to the (Weak base/Weak Nuc.) then the major product favors E1.
Amazing demonstration, thank you so much.
Glad you found it useful!
They typically will not form on primary carbons unless they are stabilized by resonance.
how is the solvent for the E2 reaction H20? Shouldn't E2 reactions have aprotic solvents?
Yeah actually a strong base such as NaOH should be used ,i think he wrote it like NaOH solution
Best teacher ever
I've been struggling with this so much and this video made it all easy for me now. thank u so much !!
Excellent video!! Keep up with the good work!
great video, using this during my summer ochem course. Thanks!!!!!
2:24 why sn1 major . Heat should favour E1 .please answer
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Great video! Hits all key points well!
it was reeeeeeeeeeally helpful to me thanks a lot
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E2 if strong base (alcoholic alkali) is present
Else E1
(hope it saved some time)
The best explanation!
Why is E1 the minor product in the first rxn? Doesn't heat favor the beta elimination?
English ain't my first language but i understand this better than my teacher who teaches in my language
super helpful! Thank you
I have a question.
Why do you need a strong base to deprotonate the C-Atom in E2, but only a weak base in E1?
Thanks a lot!
Lukas Nussbaumer strong base would result in E2
Because to remove both in one step you need a nucleophilic
Why is the E1 minor? Clearly, there is heat...
You are amazing! Thank you so much.
very very nice discription,you are wonderfull
For the E2 reaction why did you change the position of chlorine was this due to inversion
No it wasn't due to inversion - it was just re-drawing the exact same molecule in a different way so that it would end up looking just like the alkene above it (top right)
E1 should be major and SN1 minor, because you added heat/delta. If you hadn't added heat/delta, then SN1 would definitely be major. Apart from that this is a great video. thanks
I can't seem to get my mind around what antiperiplanar means. Help?
It's when the two biggest groups are furthest away from each other. I think it's only when you look at it under the Newman projection. All I could remember is that it's the most stable as there's the least serif strain. plz correct me if I'm wrong.
This anti elimination is what it means in one line
Thank you soooo muchh!! Veryy helpfull
What about Methyl Shift ? Or Rearrangements ?
Doesn't E1 need to be under acidic conditions?
Only for alcohols, because the OH is not a good enough leaving group by itself - it must be treated with acid to make OH2+ . On the other hand halides like Cl, Br, and I will leave by themselves without acid
keep it up good work stay blessed
The dehydrobromination of isopropyl bromide requires several hours of reflux with alcohol KOH whereas in t.BuO-K+ / DMSO, dehydrobromination can be carried out in less than a minute at room temperature. Why this is so?
tq
awesome
Life saver
I don’t get it! There is no difference in reaction process
Thankasssssssssa
Would the Sn2 mechanism compete with the E2 mechanism in your example? or would the E2 major product be the only product produces?
It shouldn't, since the substrate is tertiary and SN2 reactions generally do not occur on tertiary carbons.
hye..im here bcoz i cant focus on my online class..2020 is shittttt..4 days bfore 2021
👍
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خطه يجنن مع اني ما فهمت شي
ممكن اترجمولي🙂💔
keep it up good work stay blessed