Can you please help us with this problem: Emily's piggy bank contains twice as many dimes as nickels. It contains two more quarters than nickels. Emily calculates that if instead of the money she actually has, she has as many quarters as she has nickels, as many dimes as she has quarters, and as many nickels as she has dimes, then she would have $1,50 less than she actually has. How many nickels, how many dimes, and how many quarters are actually in Emily's piggy bank ?
Let x be the smallest number (the number of nickels). Then 2x = number of dimes x + 2 = number of quarters. We have to assume that the number of nickels remains the same, but that is not specifically stated in the problem. Then (x)(5) + (2x)(10) + (x+2)(25) - (x)(5) - (x)(10) - (x)(25) = 150 Solve for x. Then x = 10 10 nickels 20 dimes 12 quarters
Thank you. It is very helpful for me.~!! (My son brought some word problem. {There are twice as many less ten dimes as quarters...... total 30.95 .....} At first time I didn't understand what this meant. Anyway, I solved it. You gave me a crucial hint.
We multiplied both sides of the equation by 100, which doesn't change the equation at all, because we applied it to both sides. for example if 4 = 4 then 400 = 400 We do that here in order to get rid of the decimal.
Can you please help us with this problem: Emily's piggy bank contains twice as many dimes as nickels. It contains two more quarters than nickels. Emily calculates that if instead of the money she actually has, she has as many quarters as she has nickels, as many dimes as she has quarters, and as many nickels as she has dimes, then she would have $1,50 less than she actually has. How many nickels, how many dimes, and how many quarters are actually in Emily's piggy bank ?
Let x be the smallest number (the number of nickels). Then 2x = number of dimes x + 2 = number of quarters. We have to assume that the number of nickels remains the same, but that is not specifically stated in the problem. Then (x)(5) + (2x)(10) + (x+2)(25) - (x)(5) - (x)(10) - (x)(25) = 150 Solve for x. Then x = 10 10 nickels 20 dimes 12 quarters
Thank you. It is very helpful for me.~!! (My son brought some word problem. {There are twice as many less ten dimes as quarters...... total 30.95 .....} At first time I didn't understand what this meant. Anyway, I solved it. You gave me a crucial hint.
Great! Glad you found our videos. 🙂
why did you multiply the problem by 100
We multiplied both sides of the equation by 100, which doesn't change the equation at all, because we applied it to both sides. for example if 4 = 4 then 400 = 400 We do that here in order to get rid of the decimal.
Hey