Biochemistry | Enzyme Inhibition
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- เผยแพร่เมื่อ 25 เม.ย. 2017
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In this lecture Professor Zach Murphy will present on enzyme inhibition. We hope you enjoy this lecture and be sure to support us below!
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Slight correction: for a competitive inhibitor higher km = decreased affinity for substrate
you are essentially saying the same thing....in the last video he talked about how at 1/2vmax [s]=km so the km is basically telling you the concentration of substrate required to reach vmax....he talked about how basically increasing km results in decreased substrate affinity i.e you need to increase [s] to reach vmax
thank you i was just wondering this!!
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Thanq for preking up the learning process😊.I have a doubt :disulfiram used to treat chronic alcoholism is an example of what type of inhibitor?
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I think something is off about the Competitive Inhibitor. If the Substrate Affinity goes up, the KM decreases, but as the Substrate Affinity goes down the KM increases. You explained that to beat the Competitive Inhibitor the Substrate Affinity must go up thus the KM will increase. No, I think the correct explanation is because the Competitive Inhibitor beat the Substrate's Affinity, the Substrate Affinity goes down hence the KM goes up. Because the effect of Competitive Inhibitor is KM goes up but Vmax unaffected. That's all from me, anyway amazing video! Really helps me understand difficult concepts!
Why does the Km decrease of 'uncompetitive inhibition' then? How has the substrate infinity increased?
yes, it's true the rise in Km means that there is a lower substrate affinity for the substrate and enzyme to make ES complex due to low km it takes for inhibitor as well as the high affinity for the inhibitor. So because enzyme has high affinity for the inhibitor it must be fixed. To fix it he has to increase the substrate concentration.
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I agree! but awesome video still...
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Lehninger takes 3 pages to explain this. you make life easier bro. love you
Very thankful … saved my marks in university
At the end of the non competitive inhabitation, how is the inhabitant released and the pocket fixed or removed?
Sir plz make a video on metabolic acidosis and alkalosis...and buffer system
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very helpful
Great explanation, nice job! But I am a bit confused here..... does this mean that in the presence of an irreversible inhibitor no catalysis will occur? I mean not at all? No matter the amount of substrate there is, non will bind to the enzyme? No effect on Km or Vmax?
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Hey I have a question, at 9:00 you said that the Km or the affinity that the enzyme has for the substance is increasing but if the Km increases due to increase in substance concentration shouldn’t the affinity decrease; sorry if I have any writing errors, English is not my native language 😅
Hi Ninja nerds. Do you know the exact order on how to view this playlist? Im ready to unlearn and relearn biochemistry.
careful! at 8:56! from what i understand, km has an INVERSE relationship with affinity. what's written on the board looks fine but when you say "km, or affinity, increases" is not!
Km increases , it increases the substrate(S) concentration and decreases the substrate affinity
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good explanation but I've got one question or one thing I don't understand. You said that when the substrate concentration will increase the Km will increase to and so the affinity. In the first part of the video you said that a high Km means that the enzyme has low substrate affinity. So how can the affinity become high in competitive inhibitor when the Km and substrate concentration increases?
This , i am confused as well
Their website is up and running with all these videos and extensive notes on them, so I guess more extensive than the videos are already, I’m going to check it out to seek clarification
So good
For the longest I thought the active site changes shape when the inhibitor bind to the allosteric site.
Will it change shape? Or I got that totally wrong during my university lecture.
amazing
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Perfect
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