classical solution: after inspecting the equation we found that x = 1/3 must be a solution. Find the other solutions by using one of the following factorizing methods: Method 1: (x - 1/3)(x² + ax +4/9) = 0, find a by comparising left and right sides Method 2: use polynomial division to find the quadratric equation Solve the quadratic equation with the abc formula.
Because we have 4/27 i would try x = 1/3 and test yo see whether it is correct. If it is correct then 3x-1 is a factor. By division i hope to find the second factor. Factorize this trinomial. Etc. etc. etc😂
X^3=4/27-X^2 X=-2/3=-0.6 recurring X=1/3=0.3 recurring
classical solution:
after inspecting the equation we found that x = 1/3 must be a solution.
Find the other solutions by using one of the following factorizing methods:
Method 1:
(x - 1/3)(x² + ax +4/9) = 0, find a by comparising left and right sides
Method 2:
use polynomial division to find the quadratric equation
Solve the quadratic equation with the abc formula.
Thanks for contributing
Thanks for your efforts.
Remainder and factor theorem ❤. Excellent explanation
Thanks
JJ,
you are a talented math teacher.
Thanks
Because we have 4/27 i would try
x = 1/3 and test yo see whether it is correct. If it is correct then 3x-1 is a factor. By division i hope to find the second factor. Factorize this trinomial. Etc. etc. etc😂
👍👍
Very difficult to follow