These explain the method very clearly, but it would be great to include some sources of error / limitations for each experiment, which would explain why our experimental value is never the same as the standard value.
I find it strange that you go to the bother of making such a helpful video and some of the comments ask you to provide more information. WTF?! Thanks for taking the time to do this. It was extremely useful for me.
Its a really good experiment. I like the open circuit board where you can see all the components. Makes it less "black box" physics. Where did you buy the circuit board?
The apparatus is not well explained. Each LED in the kit has its own dropper resistor. They aren't in parallel. If they were'nt separately fed and all the LEDs were in parallel, the red LED would clamp the voltage and the other LEDs would never light.
Do we have enough information to reverse engineer what the LED application board actually does? I'm thinking the 4-Bit DIP switch must make some for of digitally weighted resistance network, and the momentary SPST provides voltage in place of the pot. Is the other black component on the right side of the board a transistor? I notice the DIP switch is not moved during the experiment.
Hi @Physics Online! Where did you find/buy that circuit board? I manage a University lab and I think we could use this to improve our current physics lab on Planck's constant!
I have another suggestion here. We can directly plot the graph of energy(E=eV) vs frequency ,so the gradient of the graph will be equal Planck constant ,h.
+A Level Physics Online What's the purpose of the potential divider circuit here? It doesn't seem to be splitting the output voltage with another component. Thanks in advance
I do have a question. If you know you will get a straight line, why not only do the test with the highest voltage LED, that should give you a V and lambda and you can use his last blue formula, what is the point of finding the gradient?
To reduce an experimental errors and uncertainties - what if your result for the blue was significantly different, you wouldn't know that was an anomaly if you only had one data point.
HOLD ON. Now they make LEDs that turn on at a lower voltage. If you video is true how does LEDs turn on at a lower voltage? Now a days TV are made for LED and other stuff and the turn on voltage is lower each year, so is Plank con wrong? Or does Plank con just gets smaller each year? Please help me to understand.
What sort of graph would you get if you plotted the voltage to the wavelength instead of the reciprocal wavelength? Also is there a way of calculating planks constant without doing 1/wavelength and just doing wavelength?
The only problem here is that the wavelength of the LED's, as given in the datasheets are calculated from planks constant. You are using circular logic!
but this got me wondering.. why when we increase the voltage, the wavelength (the color) remains the same for the same LED !! When we increase the voltage, we actually increase the potential energy for each electron, and since E goes up, so should be the frequency! The color is supposed to change !!!
Light is emitted from the diode when an electron from the conduction band drops down into the valence band. In other words, when an electron transitions to a lower energy level, it releases energy as a photon. The energy of this photon (and by extension its wavelength) depends on the size of this gap between energy levels, and that depends on the type of material from which the semiconductor is made. Because the material remains the same, the wavelength remains the same as well. Increasing the voltage doesn't change the wavelength, because it can't change the chemical composition of the diode, but it does allow a larger number of electrons to make this transition per unit of time. This means that photons are emitted at a higher rate, which raises the intensity of the light, making it look brighter.
+jamal masarwa Best way to calculate planck's constant is if you have a Ek and frequency graph, the max kinetic energy Ek = q(electron charge)V and frequency which is f=c/wavelength, or at least that is what i used
@@williamdavis2505 It is a constant, just search it up online, there's no need to measure it, but if you want to find out how it was measured search up: oil drop experiment
@@Kris-cm6vf exactly. The video is about measuring h, not e. If you wanna be pedantic and do everything from scratch, just go repeat the oil drop experiment, albeit it's much much harder to do (especially to do it precisely), and requires much much more calculations
These explain the method very clearly, but it would be great to include some sources of error / limitations for each experiment, which would explain why our experimental value is never the same as the standard value.
I find it strange that you go to the bother of making such a helpful video and some of the comments ask you to provide more information. WTF?!
Thanks for taking the time to do this. It was extremely useful for me.
shut ur moute
Thank you so much! This really helped me understand my required practical on Planck's Constant.
You sir are a legend, saving me from failing my as level physics exam! Thank you so much
You make it so easy to understand! Thank you so much sir! :)
Thank you sir for making this video. Now I know that we can use double slit experiment to find the frequency of light.
BRAVO, EXCELLENT
really good explanation
Very helpful, thank you very much
Awesome experiment!
Its a really good experiment. I like the open circuit board where you can see all the components. Makes it less "black box" physics. Where did you buy the circuit board?
Yes! Where did he buy it? I would like to get several for physics students...
Thanks a lot for an amazing video!
Brilliant. Thank you. Simply stated and answered the question I had that several documentaries didn’t answer.
what is the wavelength of those LEDs?
Thank you very much!
The apparatus is not well explained. Each LED in the kit has its own dropper resistor. They aren't in parallel. If they were'nt separately fed and all the LEDs were in parallel, the red LED would clamp the voltage and the other LEDs would never light.
Do we have enough information to reverse engineer what the LED application board actually does? I'm thinking the 4-Bit DIP switch must make some for of digitally weighted resistance network, and the momentary SPST provides voltage in place of the pot. Is the other black component on the right side of the board a transistor?
I notice the DIP switch is not moved during the experiment.
Great video mate!
Hi @Physics Online! Where did you find/buy that circuit board? I manage a University lab and I think we could use this to improve our current physics lab on Planck's constant!
Are there any research papers for this?
Nice and precise
Would you get the same results if the lab where you do the experiment would be located on the ISS? What if the lab is located on the Moon or on Mars?
You should do, it’s a universal constant so the same everywhere in the Universe.
@@PhysicsOnline not set in stone...
Great video
I have another suggestion here. We can directly plot the graph of energy(E=eV) vs frequency ,so the gradient of the graph will be equal Planck constant ,h.
By multiplying the gradient by the charge on the electron, do you just mean 1.6 x 10^-19?
+Amin Shadowz Yes
+A Level Physics Online What's the purpose of the potential divider circuit here? It doesn't seem to be splitting the output voltage with another component. Thanks in advance
+Amin Shadowz This allows you to vary the p.d across the LED.
Is this needed for A Level Edexcel Physics? Thanks!
I do have a question. If you know you will get a straight line, why not only do the test with the highest voltage LED, that should give you a V and lambda and you can use his last blue formula, what is the point of finding the gradient?
To reduce an experimental errors and uncertainties - what if your result for the blue was significantly different, you wouldn't know that was an anomaly if you only had one data point.
@@PhysicsOnline Ahh ok, good point, thanks!
Thanks!
HOLD ON. Now they make LEDs that turn on at a lower voltage. If you video is true how does LEDs turn on at a lower voltage? Now a days TV are made for LED and other stuff and the turn on voltage is lower each year, so is Plank con wrong? Or does Plank con just gets smaller each year? Please help me to understand.
What sort of graph would you get if you plotted the voltage to the wavelength instead of the reciprocal wavelength? Also is there a way of calculating planks constant without doing 1/wavelength and just doing wavelength?
I think it is because E or V = hf, so V/f = h and f = 1/wavelength.
xVbM1 linear relationships are easier to work with. By taking the average of multiple readings, you can get more accurate results.
What is the name of that board he used?
How do you know the charge of the LEDs???!,???
The only problem here is that the wavelength of the LED's, as given in the datasheets are calculated from planks constant. You are using circular logic!
What pens are you using ?
Pilot Pens
Pilot v-sign pens
what exam board and spec are these videos built around?
I tried to make them suitable for every spec, although I currently teach OCR Spec A.
ok i need those pens 😂😂
thanks
but this got me wondering.. why when we increase the voltage, the wavelength (the color) remains the same for the same LED !! When we increase the voltage, we actually increase the potential energy for each electron, and since E goes up, so should be the frequency! The color is supposed to change !!!
Light is emitted from the diode when an electron from the conduction band drops down into the valence band. In other words, when an electron transitions to a lower energy level, it releases energy as a photon. The energy of this photon (and by extension its wavelength) depends on the size of this gap between energy levels, and that depends on the type of material from which the semiconductor is made. Because the material remains the same, the wavelength remains the same as well.
Increasing the voltage doesn't change the wavelength, because it can't change the chemical composition of the diode, but it does allow a larger number of electrons to make this transition per unit of time. This means that photons are emitted at a higher rate, which raises the intensity of the light, making it look brighter.
i know it is basic as f***, but why f=1/wavelength and not just f=wavelength?
Hi, 1 stands for second. The amount of wavelengths per second is the frequency.
Ratio
i have 550 nm gradient and 1.02v treshold
+jamal masarwa Best way to calculate planck's constant is if you have a Ek and frequency graph, the max kinetic energy Ek = q(electron charge)V and frequency which is f=c/wavelength, or at least that is what i used
why does the blue light up later or in a higher voltage?
it's has a different threshold voltage
Jasper D because blue light has a higher frequency and hence it requires more energy.
h.
Homework for pg 77
i keep doing this but it just wont give me plancks constant
+jamal masarwa From this, I'm thinking that you may need to look for the value of planck's constant in electronvolts since he says E=eV.
Wrong.
Planck derived the value of his constant using his law of radiation
Sorry, but you do not explain how h is calculated.
Have a look at 6:28 (using your value for the gradient and known values of e and c)
GCSE and A Level Physics Online it’s a bit of a cheat to require the value of e. How do you measure e?
@@williamdavis2505 It is a constant, just search it up online, there's no need to measure it, but if you want to find out how it was measured search up: oil drop experiment
@@Kris-cm6vf exactly. The video is about measuring h, not e. If you wanna be pedantic and do everything from scratch, just go repeat the oil drop experiment, albeit it's much much harder to do (especially to do it precisely), and requires much much more calculations