If you mean the dimensions to find the minimum area, then that's because the minimum area would be 0. Imagine that I took the fencing and created a long enclosure that was really thin. So thin, in fact, that nothing could fit inside of it. That would be the minimum area. The dimensions of such an enclosure would be 0 by 300.
Thank you. My test is tomorrow. This helped a lot
Very-well explained!
i have a test on this in an hour u saved me thanks
but how did you find the 2W and 4L thou???
Count the horizontal line, then the four vertical lines on the diagram
Helped alot!! Only thing is that you talk wayyy too fast haha
How did you get 0 for x and not 2?
where did the extra x came from, im a bit lost
It gave idea of ax^2 + bx + c
what is the area?
Niceeed
lost...
❤️
I can tell mr. james is canadian
why don't you discuss how to find the minimum dimensions for the rectangle???
If you mean the dimensions to find the minimum area, then that's because the minimum area would be 0. Imagine that I took the fencing and created a long enclosure that was really thin. So thin, in fact, that nothing could fit inside of it. That would be the minimum area. The dimensions of such an enclosure would be 0 by 300.
the width could still be more than 150
Ur too fast?
You include so many unnecessary things in the video. Maybe that’s why it’s so fucking long