I have a question for you 🙋♂, in colleges and universities, which math courses talks about Continuous Probability Distribution? Which courses talks about this? Which courses? The reason why I wanted to know which courses talks about Continuous Probability Distributions in colleges and universities because I don't know which courses talks about that? Please give me an answer to the question of which courses talks about Continuous Probability Distribution. Please answer my question.
A very good lesson..thank u for this sir,but i have a question In question 1c Is there no way it could be solved direct without solving solving for 0,1 and 2...
You may need to watch the introductory videos on probability for clear understanding of binomial probability distribution. See the link of the playlist containing all the videos on Probability and Probability Distribution: th-cam.com/play/PLYwM9CzPztOkBlVGFRjyxyZLu4UcI-moj.html
Remember coin has two sides ,, that means head is one side and other side there's a tail ..therefore if we toss it once one may get head or tail which is 1/2
Thanks very much but I have a lot of questions regarding part b of the second example. If I use Pr(x=0) + Pr(x=1) + Pr(x=2) + Pr(x=3) + Pr(x=4), I get an answer which is greater than 1. This arises from the fact that Pr(x=4)=10/9 which is impossible in probability. If I try your method, I still wonder why you did not subtract Pr(x=6). Otherwise the video was very helpful.
A coin has two faces, head(H) and tail(T). p = Pr(H) = ½ q = Pr(T) = ½ Please watch the video below for further clarification. th-cam.com/video/Z49J9lLCtm4/w-d-xo.html
Thank you for your feedback. There are 4 options for each multiple choice question in which only one option is correct. Probability of answering each question correctly is ¼ which is equal to p. Probability of answering it wrongly is ¾ which is q. You may need to watch the video on basic problem on probability for further clarification. Warm regards.
Thank you for your feedback. On your question, we didn't include p(x=6) because there is no need for it since the number of trials in the question is 5 (n = 5). You may need to watch the video again for further clarification. Warm regards.
i use a casio fx-82za plus calculator so for me is just put in 6-shift (the devide button which is your C) 4 that will give you 15... hope this helps XD
You just have to think of a number that will make the number of success whole or complete. For example, u were given a success or (p) of 2/5 then think of a number that will make 2 a 5 and that is 3. So, your failure or (q) is 3/5
Thanks for your feedback. You may need to watch our video on Introduction to probability for better understanding. See the link below 👇 th-cam.com/video/Z49J9lLCtm4/w-d-xo.html
Thanks sir, much appreciated from south Africa here.
your lessons are just incredible. thank you so much for sharing with us
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This is really good
Explained in such the simplest way 🙂🙂
Thanks a lots for very good explanation 😊
In example 1 how did you got the 32 and 64?
Hello good day. Why does in example 1 letter C you included Probability of 0? We are talking about of having a head right?
Thanks 😊 for sharing
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Thank you so much sir.
This helped me alot
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We are glad you enjoyed the video.
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In the example 2 sir how did you get the success(p) and failure (q).
I have a question for you 🙋♂, in colleges and universities, which math courses talks about Continuous Probability Distribution? Which courses talks about this? Which courses? The reason why I wanted to know which courses talks about Continuous Probability Distributions in colleges and universities because I don't know which courses talks about that? Please give me an answer to the question of which courses talks about Continuous Probability Distribution. Please answer my question.
probability and statsics
Probability and statistics, at the University of Zambia Mat2901/2602
Also data management course
WELL DONE!
A very good lesson..thank u for this sir,but i have a question
In question 1c
Is there no way it could be solved direct without solving solving for 0,1 and 2...
Yes, you can but it will be cumbersome.
Sir please how did you get the probability of success as p and q as a failure from the given question
You may need to watch the introductory videos on probability for clear understanding of binomial probability distribution.
See the link of the playlist containing all the videos on Probability and Probability Distribution: th-cam.com/play/PLYwM9CzPztOkBlVGFRjyxyZLu4UcI-moj.html
Sir how are we getting 1/2 for p and q?
Please example 1 how did you get the probability to be 1\2
Pls how did you get 1/2 in the first example
What do you mean by 6c4 is 15 I'm not getting it clearly
Thank you for this wonderful tutorial, well explained 😍
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How did you get P1/2??
Hi
Remember coin has two sides ,, that means head is one side and other side there's a tail ..therefore if we toss it once one may get head or tail which is 1/2
This is well explained 🥰🥰
Thank you so much!
You’re welcome 😊
We appreciate your feedback and compliment.
On atmost question.. it is possible to use combination of 2 itself and only? Excluding 0?
We don't actually know the particular question you are referring to. Meanwhile, any other way will give you the same answer.
Nope you have to consider all options of 2 or 1 or 0( none). Those are all the possible outcomes
Pls how did you get p=1/2 and q=1/2
God bless you
Amen
how did you get 1/2??
Thanks so much.
Thanks very much but I have a lot of questions regarding part b of the second example. If I use Pr(x=0) + Pr(x=1) + Pr(x=2) + Pr(x=3) + Pr(x=4), I get an answer which is greater than 1. This arises from the fact that Pr(x=4)=10/9 which is impossible in probability. If I try your method, I still wonder why you did not subtract Pr(x=6). Otherwise the video was very helpful.
I wonder the same, coming in one year later.
@Oninab please come through 😢
But a good concept
3:49 how do u get 1/2
A coin has two faces, head(H) and tail(T).
p = Pr(H) = ½
q = Pr(T) = ½
Please watch the video below for further clarification.
th-cam.com/video/Z49J9lLCtm4/w-d-xo.html
How did you get 1/4 and 3/4 in the third question
Thank you for your feedback.
There are 4 options for each multiple choice question in which only one option is correct.
Probability of answering each question correctly is ¼ which is equal to p. Probability of answering it wrongly is ¾ which is q. You may need to watch the video on basic problem on probability for further clarification.
Warm regards.
thanks sir
How did u get failure 0.2
P(success) = 0.8
P(failure) = 1- 0.8 = 0.2
Success and failure are complementary events and their individual probability sum up to 1.
amazing
Thank you! Cheers!
Have gotten it
Thanks so much
You're welcome!
You're welcome!
recheck Q1
Thanks
You are welcome
How did you derive 6 combination 5 to be 6?
Thank you for watching.
We appreciate your feedback. You can input 6C5 in your calculator.
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Thank You Sir
You are welcome.
the example 2 / b id didn't understand very well why you didnt inclidees even the probabibilty p(x=6) when calculating p(x>,=4 )?
Thank you for your feedback.
On your question, we didn't include p(x=6) because there is no need for it since the number of trials in the question is 5 (n = 5). You may need to watch the video again for further clarification.
Warm regards.
@@OninabResources thank you
Pls the final answer how do we do it
Pls how is 6c4 =15
How is 6c4 15
i use a casio fx-82za plus calculator so for me is just put in 6-shift (the devide button which is your C) 4 that will give you 15... hope this helps XD
Sir pls how did you get you success (p) and failure (q) in question 2&3 its confusing
He got 1/2 from the sides of a coin (head and tail)
how is in (b) 6*1/(1/32) is equal to 6/64? it is wrong
Thank you for your feedback.
You may need to watch the video again. What we have in b is 6× ¹/32 × ½ which gives 6/64.
Warm regards.
How you came out with 1 half and the rest
Thanks bro
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Moral is good
I don't know how get the 0.2 but u are doing very well
q is obtained by the equation (1-p), so p is 0.8 hence (1-0.8)=0.2
@@sheriweri thank you
Pls how can I get the failure
You just have to think of a number that will make the number of success whole or complete.
For example, u were given a success or (p) of 2/5 then think of a number that will make 2 a 5 and that is 3. So, your failure or (q) is 3/5
In the examole 2, 2/3 to the third is 2/27, not 8/27. Reputability check. Unless my calc has got an internal issue.
(2/3)³ = 2³/3³ = 8/27 sir.
Change your calculator or check your input.
Okay of this one
p: it rains
q: there will be flood
❤❤❤❤❤
Sorry at least 5 it supposed to be 0,1,2,3,4,5
Consult with your English teacher for more clarification on at least and at most. Thank you.
At least means the smallest figure should be 5 which implies that it's only 5 and 6.
This is for at most 5 not at least 5
@@OninabResources u should have just corrected him, instead of saying that. What is the essence of being the teacher?
John M Sesay
Thank you so much for your feedback.
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Yeah
We have seen what is p as probability of success but we don't know how we seek a number P
Thank you for your feedback.
The value of p is either given in the question or use the information in the question to calculate it.
Good but too long solutions ..
I don't understand number 1 how is the probability 1/2?
Thanks for your feedback. You may need to watch our video on Introduction to probability for better understanding. See the link below 👇
th-cam.com/video/Z49J9lLCtm4/w-d-xo.html
oh i got it now
Thanks sir
You are welcome.
Thanks for your feedback.
Warm regards.
recheck Q1