For people asking why 60 can't be the answer to max # of people playing 3 sports in the Football (F), Badminton (B) and Hockey (H) problem, try to visualize the venn diagram. If N(FnBnH)=60, it means N(Only H)=N(BnH)=N(FnH)=0 since N(H)=60. Now in Football, there are 80-60=20 students left to be allotted and in Badminton there are 70-60 =10 students to be allotted. In the extreme case, even if you consider N(Only F)=20 and N(Only B)=10 and N(FnB)=0, then the total number of students become N(FnBnH)+N(Only F)+N(Only B) = 60+20+10 = 90 which is less than 100 and hence doesn't satisfy the constraint that each student plays at least 1 sport. If no such constraints are present, go ahead and select the minimum number of the 3 as the common maximum.
simple bro, itna bhi zarurat nhi tha, just simply think if 60 people get 3 chocs, 180 are used, left with 30 chocs and 40 people having zero chocs, so, even if we distribute 1 to each , 10 people get nothing, minimum condition violated. simple.
and in the english subject 1st qn one, 12*5=60 and the remaining 18 students can get any percentage so thats why max 12 can be considered right? @@bhaskarbawaly8515
He's worded it wrong hence the confusion. It's each student playing atleast one sport and not each sport played by atleast one student (in which case the answer would be 60)
Sir I have doubt that how you choose min value in each class. But in previous chocolate distribution questions why not choose minimum number of student 60 from hockey
Sir at 10:27 Question is Each sport is being played by atleast 1 student and not each student plays atleast 1 sport, then why to give 1 chocolate to all 100 ?
but there can be students playing none of the sports. what if suppose only 80 out of 100 students are playing and 20 are not playing? Then the max would probably be 60. @@rishipatel4282
You are right , the language of the question must be each student plays atleast one sport otherwise it's not compulsory to give one chocolate to each student
I see some inconsistency here, a/c to the ques. each sport is being played by at least one student, but you have solved considering each student is playing at least one sport. These two are not the same. Pls have a look sir.
You explain every concept very well sir...and I appreciate that . i am commenting on all ur videos to pls make video on coordinate geometry , either you don't check comment section properly or u r ignoring it Pls consider my point
There is a Difference between "Maximum no. of student who CAN get" and "Maximum no. of students who got". Can is the Possibility, means we can write the minimum no. Of the table as our answer. But when asked specifically, then we need to apply Chocolate Distribution method.
yeh kaisa logic diya bro, aise mat samjhao, it simply because if we distribute by giving 3 to max 60, some people will get zero, that violates the min condition@@nisbaansayed9155
Sir if the total no. Of student in class 7 is 34 then the logic to take the minimum common to give all 5 chocs , is not applicable, pls tell me if I am wrong
![How I Trick My Brain To Study Focussed Everyday?[Andrew Huberman Method]](http://i.ytimg.com/vi/eBz5JwWMg3Q/mqdefault.jpg)
The same set has come and taught in times but i did not understand anything but you explained very well sir. Thank you
Sir consume honey. it's beneficial for throat/cough problems
Sir my mock score boosted from single digit in quants to 28 now! thenksss sirr
How'd you do in the exam?
@@venumohan5500 wbu
min students who will play all three sports-10
max students who will play all three sports -55
You're GOD
Keep providing for those who can't pay
Don't said God. God give many things which no one can't😅
For people asking why 60 can't be the answer to max # of people playing 3 sports in the Football (F), Badminton (B) and Hockey (H) problem, try to visualize the venn diagram.
If N(FnBnH)=60, it means N(Only H)=N(BnH)=N(FnH)=0 since N(H)=60.
Now in Football, there are 80-60=20 students left to be allotted and in Badminton there are 70-60 =10 students to be allotted. In the extreme case, even if you consider N(Only F)=20 and N(Only B)=10 and N(FnB)=0, then the total number of students become N(FnBnH)+N(Only F)+N(Only B) = 60+20+10 = 90 which is less than 100 and hence doesn't satisfy the constraint that each student plays at least 1 sport.
If no such constraints are present, go ahead and select the minimum number of the 3 as the common maximum.
simple bro, itna bhi zarurat nhi tha, just simply think if 60 people get 3 chocs, 180 are used, left with 30 chocs and 40 people having zero chocs, so, even if we distribute 1 to each , 10 people get nothing, minimum condition violated. simple.
and in the english subject 1st qn one, 12*5=60 and the remaining 18 students can get any percentage so thats why max 12 can be considered right? @@bhaskarbawaly8515
He's worded it wrong hence the confusion. It's each student playing atleast one sport and not each sport played by atleast one student (in which case the answer would be 60)
sir i am fane of your teching
What will be the minimum possible no. Here? For all three sports?
Thank you so much for this amazing session sir 🙏❤️
Sir shouldn't the question be that "each person plays at least one sport" instead of the reverse??
Yes
Yes
sir can you suggest mocks because all institutes mocks are so expensive.
Thankyou so much for the fantastic session. helped me solve a lot of questions
Hey are you preparing for CAT only? also can you solve all the rest questions of this set. happy to discuss regarding prep.
@@bhaskarbawaly8515 bhai ladke bhi krre hai prepare unse bhi puchle
Amazing as always
Nice explanation and steps for CD sir!!!! Awesome
Man is wearing unacademy tshirt for Rodha. He s got some guts
Brilliantly explained sir. Thank you !
Sir I have doubt that how you choose min value in each class.
But in previous chocolate distribution questions why not choose minimum number of student 60 from hockey
Sir at 10:27 Question is Each sport is being played by atleast 1 student and not each student plays atleast 1 sport, then why to give 1 chocolate to all 100 ?
Both are same I guess man
Because we have to find maximum
but there can be students playing none of the sports. what if suppose only 80 out of 100 students are playing and 20 are not playing? Then the max would probably be 60. @@rishipatel4282
You are right , the language of the question must be each student plays atleast one sport otherwise it's not compulsory to give one chocolate to each student
12:06 Is it also possible that 70 PPL play 3 sports and 30 people 0 ?
I see some inconsistency here, a/c to the ques. each sport is being played by at least one student, but you have solved considering each student is playing at least one sport. These two are not the same. Pls have a look sir.
I agree
Can I get a link of the next part of this video
Very ell explained sir. Thank you.
Sir ....mujh kal k mocks k analysis videos nhi mil rhee
Is maximization and minimisation similar to chocolate distribution?
in many questions yes
Sir 60 can't be the answer?
sir why u have not done all ques i have not found all the 7 ques
nice one
It should be “each student plays at least one sport” instead of “each sport is being used played by at least one student” @rodha
Sir what If the no of chocolates are not divisible by 2?
Ek tu khaa le baaki baat de
broooooo, @@kartikjain336
Thank you Sir...for the revision..
Really great and helpful
Thank you Sir 🙏
You explain every concept very well sir...and I appreciate that .
i am commenting on all ur videos to pls make video on coordinate geometry , either you don't check comment section properly or u r ignoring it
Pls consider my point
There's an entire series of 28 videos on geometry. Please find the link below. th-cam.com/play/PLG4bwc5fquziUvO3dlzG0MW9vqi3epud4.html
Is answer of question 5 is 61
Can max students be 50?
Thanku sir
Sir why not its 60?
There is a Difference between "Maximum no. of student who CAN get" and "Maximum no. of students who got". Can is the Possibility, means we can write the minimum no. Of the table as our answer. But when asked specifically, then we need to apply Chocolate Distribution method.
yeh kaisa logic diya bro, aise mat samjhao, it simply because if we distribute by giving 3 to max 60, some people will get zero, that violates the min condition@@nisbaansayed9155
@nisbaansayed9155 oh man u cleared the concept which understood as a dash of salt
Nice
Thank U Sir ❤💯
Question should have had each student should atleast play 1 sport.
Thank you sir :)
Thankyou sir
Sir if the total no. Of student in class 7 is 34 then the logic to take the minimum common to give all 5 chocs , is not applicable, pls tell me if I am wrong
Not 5 but 4. We already gave one chocolate to every student as each and every one has scored 90% in atleast one subject.
thank you sir
#RODHAFORCAT
Done 👍🏻
24 September 2024